5.0: Algebra with Trigonometric Ratios
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In this chapter we apply some techniques from algebra to analyze more complicated trigonometric expressions. Before we begin, let’s review some algebraic terminology.
- An algebraic expression is any meaningful collection of numbers, variables, and operation symbols. For example, the height of a golf ball is given in feet by the expression −16t2+64t, where t is the number of seconds after the ball is hit.
- We evaluate an expression by substituting a specific value for the variable or variables involved. Thus, after 1 second, the height of the golf ball is
−16(1)2+64(11)=−16+64=48 feet
and after 2 seconds, the height is
−16(2)2+64(2)=−64+128=64 feet
and so on.
Evaluating Trigonometric Expressions
Trigonometric ratios represent numbers, and they may appear as part of an algebraic expression. Expressions containing trig ratios can be simplified or evaluated like other algebraic expressions.
Evaluate each expression for X=30∘ and Y=135∘.
a 2tanY+3sinX
b 6tanXcosY
- Answer
-
a Substituting the values for X and Y, we get
2tan135∘+3sin30∘
Next, we evaluate each trig ratio and follow the order of operations.
2tan135∘+3sin30∘=2(−1)+3(12)=−2+32=−12
b This expression includes the product of two trig ratios 6(tanX)(cosY), where the parentheses indicate multiplication.
6tanXcosY=6(tan30∘)(cos135∘)=6(1√3)(−1√2)=−6√6=−√6
Evaluate each expression for X=30∘,Y=60∘.
a 4sin(3X+45∘)
b 1−cos(4Y)
- Answer
-
a 2√2
b 32
In the previous Exercise, sin(3X+45∘) is not equal to sin3X+sin45∘. That is,
sin(90∘+45∘)≠sin90∘+sin45∘
(You can check this for yourself.) We must follow the order of operations and evaluate the expression 3X+45∘ inside parentheses before applying the sine function.
Simplifying Trigonometric Expressions
When we simplify an algebraic expression, we obtain a new expression that has the same values as the old one, but is easier to work with. For example, we can apply the distributive law and combine like terms to simplify
2x(x−6)+3(x+2)=2x2−12x+3x+6=2x2−9x+6
The new expression is equivalent to the old one, that is, the expressions have the same value when we evaluate them at any value of x. For instance, you can check that, at x=3,
2(3)(3−6)+3(3+2)=6(−3)+3(5)=−32(3)2−9(3)+6=18−27+6=−3
To simplify an expression containing trig ratios, we treat each ratio as a single variable. Compare the two calculations below:
8xy−6xy=2xy8cosθsinθ−6cosθsinθ=2cosθsinθ
Both calculations are examples of combining like terms. In the second calculation, we treat cosθ and sinθ as variables, just as we treat x and y in the first calculation.
Simplify.
a 3tanA+4tanA−2cosA
b 2−sinB+2sinB
- Answer
-
a Combine like terms.
3tanA+4tanA−2cosA=7tanA−2cosA
Note that tanA and cosA are not like terms.
b Combine like terms.
2−sinB+2sinB=2+sinB
Note that −sinB means −1⋅sinB.
Simplify 2cost−4coswsinw+3cost−2cosw
- Answer
-
5cost−4coswsinw−2cosw
In the previous Exercise, note that cost and cosw are not like terms. (We can choose values for t and w so that cost and cosw have different values.)
Simplify, and evaluate for z=40∘.
3sinz−sinztanz+3sinz
- Answer
-
We can combine like terms to get
6sinz−sinztanz
Because 40∘ is not one of the angles for which we know exact trig values, we use a calculator to evaluate the expression.
6sin40∘−(sin40∘)(tan40∘)=6(0.6428)(0.8391)=3.3174
Simplify, and evaluate for x=25∘,y=70∘
3cosx+cosy−2cosy+cosx
- Answer
-
3.2832
Powers of Trigonometric Ratios
Compare the two expressions
(cosθ)2andcos(θ2)
They are not the same.
- The first expression, (cosθ)2, says to compute cosθ and then square the result.
- cos(θ2) says to square the angle first, and then compute the cosine.
For example, if θ=30∘, then
(cos30∘)2=(√32)2=34 but cos(302)∘=cos900∘=cos180∘=−1
We usually write cos2θ instead of (cosθ)2, and cosθ2 for cos(θ2). You must remember that
cos2θ means (cosθ)2
The same notation applies to the other trig ratios, so that
sin2θ=(sinθ)2 and tan2θ=(tanθ)2
Evaluate sin245∘.
- Answer
-
sin245∘=(sin45∘)2=(1√2)2=12
Other powers are written in the same fashion. Thus, for example, sin3θ=(sinθ)3.
Evaluate tan460∘
- Answer
-
9
Products
We can multiply together trigonometric expressions, just as we multiply algebraic expressions. Recall that we use the distributive law in computing products such as
x(3x−2)=3x2−2x
and
(x−3)(x+5)=x2+2x−15
Using the distributive law, multiply cost(3cost−2).
- Answer
-
Think of cost as a single variable, and multiply by each term inside parentheses. (The algebraic form of the calculation is shown on the right in blue).
cost(3cost−2)=(cost)(3cost)−(cost)⋅2)x(3x−2)=x⋅3x−x⋅2=3cos2t−2cost=3x2−2x
Notice that we write (cost)2 as cos2t.
Multiply 2tanβ(4tan2β+tanα)
- Answer
-
8tan3β+2tanβtanα
We can also use the distributive law to multiply binomials that include trig ratios. You may have used the acronym FOIL to remember the four multiplications in a product of binomials: First terms, Outside terms, Inside terms, and Last terms.
Multiply (4sinC−1)(3sinC+2).
- Answer
-
This calculation is similar to the product (4x−1)(3x+2), except that the variable x has been replaced by sinC. Compare the calculations for the two products; first the familiar algebraic product:
(4x−1)(3x+2)=4x⋅3x+4x⋅2−1⋅3x−1⋅2=12x2+8x−3x−2=12x2+5x−2
We compute the product in this example in the same way, but replacing x by sinC.
(4sinC−1)(sinC+2)=(4sinC)(3sinC)+(4sinC)⋅2−1(3sinC)−1⋅2=12sin2C+5sinC−2
Expand (4cosα+3)2
- Answer
-
16cos2α+24cosα+9
Factoring
We can factor trigonometric expressions with the same techniques we use for algebraic expressions. In the next two Examples, compare the familiar algebraic factoring with a similar trigonometric expression.
Factor.
a 6w2−9w
b 6sin2θ−9sinθ
- Answer
-
a We factor out the common factor, 3w.
6w2−9w=3w(2w−3)
b We factor out the common factor, 3sinθ.
6sin2θ−9sinθ=3sinθ(2sinθ−3)
Factor.
a 2a2−ab
b 2cos2ϕ−cosϕsinϕ
- Answer
-
a a(2a−b)
b cosϕ(2cosϕ−sinϕ)
We can also factor quadratic trinomials.
Factor.
a t2−3t−10
b tan2α−3tanα−10
- Answer
-
a We look for numbers p and q so that (t+p)(t+q)=t2−3t−10. Their product is pq=−10, and their sum is p+q=−3. By checking the factors of −10 for the correct sum, we find p=−5 and q=2. Thus,
t2−3t−10=(t−5)(t+2)
b Now replace t by tanα to find
tan2α−3tanα−10=(tanα−5)(tanα+2)
Factor.
a 3z2−2z−1
b 3sin2β−2sinβ−1
- Answer
-
a (3z+1)(z−1)
b (3sinβ+1)(sinβ−1)
Review the following skills you will need for this section.
Factor.
1 2x2+5x−12
2 3x2−2x−8
3 12x2+x−1
4 6x2−13x−15
5 6x2−x−12
6 24x2+10x−21
- Algebra Refresher Answers
-
1 (2x−3)(x+4)
2 (3x+4)(x−2)
3 (4x−1)(3x+1)
4 (6x+5)(x−3)
5 (2x−3)(3x+4)
6 (6x+7)(4x−3)
Section 5.1 Summary
Vocabulary
• Expression
• Evaluate
• Binomial
• Trinomial
• Simplify
• Equivalent expression
• Like terms
• Distributive law
• Factor
Concepts
1 Expression containing trig ratios can be simplified or evaluated like other algebraic expressions. To simplify an expression containing trig ratios, we treat each ratio as a single variable.
2 sin(X+Y) is not equal to sinX+sinY (and the same holds for the other trig ratios). Remember that the parentheses indicate function notation, not multiplication.
3 We write cos2θ to denote (cosθ)2, and cosnθ to denote (cosθ)n. (Similarly for the other trig ratios.)
4 We can factor trigonometric expressions with the same techniques we use for algebraic expressions.
Study Questions
1 To evaluate cos230∘, Delbert used the keystrokes
COS 30x2 ENTER
and got the answer 1. Were his keystrokes correct? Why or why not?
2 Make up an example to show that tan(θ+ϕ)≠tanθ+tanϕ.
3 Factor each expression, if possible.
a x2−4x e x2−4x+4 b x2−4 f x2+4x c x2+4 g x2−4x−4 d x2+4x+4 h −x2+4
Skills
1 Evaluate trigonometric expressions #1–22
2 Simplify trigonometric expressions #23–34
3 Recognize equivalent expressions #35–44
4 Multiply or expand trigonometric expressions #45–56
5 Factor trigonometric expressions #57–70
Homework 5.1
For Problems 1-8, evaluate the expressions, using exact values for the trigonometric ratios.
1. 5tan135∘+6cos60∘
2. 3tan240∘+8sin300∘
3. sin(15∘+30∘)
4. cos(2⋅75∘)
5. 8cos2(30∘)
6. 12sin2(315∘)
7. 3tan2(150∘)−sin2(45∘)
8. 1+tan2(120∘)
For Problems 9-16, evaluate the expressions for x=30∘,y=45∘, and z=60∘. Give exact values for your answers.
9. 3sinx+5cosy
10. 4tany+6cosy
11. −2tan3y
12. sin(3x−2x)
13. cos2x+sin2x
14. 7sin2y+7cos2y
15. cosxcosx−sinxsinz
16. tan(180∘−x)tanx
For Problems 17–22, evaluate the expressions using a calculator.
17.
a sin(10∘+40∘)
b sin10∘+sin40∘
c sin10∘cos40∘+cos10∘sin40∘
18.
a cos(20∘+50∘)
b cos20∘+cos50∘
c cos20∘cos50∘−sin20∘sin50∘
19.
a cos(2⋅24∘)
b 2cos24∘
c 2cos2(24∘)−1
20.
a cos(3⋅49∘)
b 3cos49∘
c 4cos3(49∘)−3cos49∘
21.
a cos2(17∘)+sin2(17∘)
b cos2(86∘)+sin2(86∘)
c cos2(111∘)+sin2(111∘)
22.
a 1cos2(25∘)−tan2(25∘)
b 1cos2(100∘)−tan2(100∘)
c 1cos2(8∘)−tan2(8∘)
For Problems 23–28, combine like terms.
23.
a 3x2−x−5x2
b 3cos2θ−cosθ−5cos2θ
24.
a 4x+5y−y
b 4cosθ+5sinθ−sinθ
25.
a −3SC+7SC
b −3sinθcosθ+7sinθcosθ
26.
a 4SC+11SC−17SC
b 4sinθcosθ+11sinθcosθ−17sinθcosθ
27.
a −C2S3+6C2S3
b −cos2θsin3θ+6cos2θsin3θ
28.
a 7C2S2−(2CS)2
b 7cos2θsin2θ−(2cosθsinθ)2
For Problems 29-34, simplify the expression, then evaluate.
29. cost+2costsint−3cost, for t=143∘
30. 11tanw−4tanw+6tanwcosw, for w=8∘
31. 7tanθ−4tanϕ+3tanϕ−6tanθ, for θ=21∘,ϕ=89∘
32. 5sinA+sinB−6sinB+6sinA, for A=111∘,B=26∘
33. −sinxcosx−sin(2x)+3sinxcosx, for x=107∘
34. 4cosusinu+3sin2u−10sinucosu, for u=2∘
For Problems 35–44, decide whether or not the expressions are equivalent. Explain.
35. cos(x+y),cosx+cosy
36. sin(θ−ϕ),sinθ−sinϕ
37. tan(2A),2tanA
38. cos(12β),12cosβ
39. (sinα)2,sin2α
40. (tanB)2,tan(B2)
41. sin3t+sin5t,sin8t
42. 3cos2x+5cos2x,8cos2x
43. tan(θ+45∘)−tanθ,tan45∘
44. sin(30∘+z)+sin(30∘−z),sin60∘
For Problems 45–56, multiply or expand.
45.
a x(2x−1)
b sinA(2sinA−1)
46.
a q(5r−q)
b cosθ(5sinθ−cosθ)
47.
a a(b−3a)
b tanA(tanB−3tanA)
48.
a 3w(2w−z)
b 3sinα(2sinα−sinβ)
49.
a (C+1)(2C−1)
b (cosϕ+1)(2cosϕ−1)
50.
a (3S−2)(S+1)
b (3sinB−2)(sinB+1)
51.
a (a+b)(a−b)
b (cosθ+cosϕ)(cosθ−cosϕ)
52.
a (t−w)(t+4w)
b (tanα−tanβ)(tanα+4tanβ)
53.
a (1−T)2
b (1−tanθ)2
54.
a (2+3S)2
b (2+3sinθ)2
55.
a (T2+2)(T2−2)
b (tan2θ+2)(tan2θ−2)
56.
a (2c2−3)(2c2+3)
b (2cos2ϕ−3)(2cos2ϕ+3)
For Problems 57–70, factor.
57.
a 9m+15n
b 9cosα+15cosβ
58.
a 12p−20q
b 12sinθ−20sinϕ
59.
a 5r2−10qr
b 5tan2C−10tanBtanC
60.
a 2x2−6xy
b 2sin2a−6sinAcosA
61.
a 9C2−1
b 9cos2β−1
62.
a 25S2−16S
b 25sin2β−16sinβ
63.
a 6T3−8T2
b 6tan3A−8tan2A
64.
a 9T2−15T3
b 9tan2B−15tan3B
65.
a t2−t−20
b tan2θ−tanθ−20
66.
a s2+5s−6
b sin2A+5sinA−6
67.
a 3c2+2c−1
b 3cos2B+2cosB−1
68.
a 8S2−6S+1
b 8sin2ϕ−6sinϕ+1
69.
a 6S2−5S−1
b 6sin2α−5sinα−1
70.
a T2−4T−12
b tan2α−4tanα−12