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5.0: Algebra with Trigonometric Ratios

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In this chapter we apply some techniques from algebra to analyze more complicated trigonometric expressions. Before we begin, let’s review some algebraic terminology.

  • An algebraic expression is any meaningful collection of numbers, variables, and operation symbols. For example, the height of a golf ball is given in feet by the expression 16t2+64t, where t is the number of seconds after the ball is hit.
  • We evaluate an expression by substituting a specific value for the variable or variables involved. Thus, after 1 second, the height of the golf ball is

16(1)2+64(11)=16+64=48 feet 

and after 2 seconds, the height is

16(2)2+64(2)=64+128=64 feet 

and so on.

Evaluating Trigonometric Expressions

Trigonometric ratios represent numbers, and they may appear as part of an algebraic expression. Expressions containing trig ratios can be simplified or evaluated like other algebraic expressions.

Example 5.1

Evaluate each expression for X=30 and Y=135.

a 2tanY+3sinX
b 6tanXcosY

Answer

a Substituting the values for X and Y, we get

2tan135+3sin30

Next, we evaluate each trig ratio and follow the order of operations.

2tan135+3sin30=2(1)+3(12)=2+32=12

b This expression includes the product of two trig ratios 6(tanX)(cosY), where the parentheses indicate multiplication.

6tanXcosY=6(tan30)(cos135)=6(13)(12)=66=6

Checkpoint 5.2

Evaluate each expression for X=30,Y=60.

a 4sin(3X+45)
b 1cos(4Y)

Answer

a 22
b 32

Caution 5.3

In the previous Exercise, sin(3X+45) is not equal to sin3X+sin45. That is,

sin(90+45)sin90+sin45

(You can check this for yourself.) We must follow the order of operations and evaluate the expression 3X+45 inside parentheses before applying the sine function.

Simplifying Trigonometric Expressions

When we simplify an algebraic expression, we obtain a new expression that has the same values as the old one, but is easier to work with. For example, we can apply the distributive law and combine like terms to simplify

2x(x6)+3(x+2)=2x212x+3x+6=2x29x+6

The new expression is equivalent to the old one, that is, the expressions have the same value when we evaluate them at any value of x. For instance, you can check that, at x=3,

2(3)(36)+3(3+2)=6(3)+3(5)=32(3)29(3)+6=1827+6=3

To simplify an expression containing trig ratios, we treat each ratio as a single variable. Compare the two calculations below:

8xy6xy=2xy8cosθsinθ6cosθsinθ=2cosθsinθ

Both calculations are examples of combining like terms. In the second calculation, we treat cosθ and sinθ as variables, just as we treat x and y in the first calculation.

Example 5.4

Simplify.

a 3tanA+4tanA2cosA
b 2sinB+2sinB

Answer

a Combine like terms.

3tanA+4tanA2cosA=7tanA2cosA

Note that tanA and cosA are not like terms.

b Combine like terms.

2sinB+2sinB=2+sinB

Note that sinB means 1sinB.

Checkpoint 5.5

Simplify 2cost4coswsinw+3cost2cosw

Answer

5cost4coswsinw2cosw

Caution 5.6

In the previous Exercise, note that cost and cosw are not like terms. (We can choose values for t and w so that cost and cosw have different values.)

Example 5.7

Simplify, and evaluate for z=40.

3sinzsinztanz+3sinz

Answer

We can combine like terms to get

6sinzsinztanz

Because 40 is not one of the angles for which we know exact trig values, we use a calculator to evaluate the expression.

6sin40(sin40)(tan40)=6(0.6428)(0.8391)=3.3174

Checkpoint 5.8

Simplify, and evaluate for x=25,y=70

3cosx+cosy2cosy+cosx

Answer

3.2832

Powers of Trigonometric Ratios

Compare the two expressions

(cosθ)2andcos(θ2)

They are not the same.

  • The first expression, (cosθ)2, says to compute cosθ and then square the result.
  • cos(θ2) says to square the angle first, and then compute the cosine.

For example, if θ=30, then

(cos30)2=(32)2=34 but cos(302)=cos900=cos180=1

We usually write cos2θ instead of (cosθ)2, and cosθ2 for cos(θ2). You must remember that

The square of cosine.

cos2θ means (cosθ)2

The same notation applies to the other trig ratios, so that

sin2θ=(sinθ)2 and tan2θ=(tanθ)2

Example 5.9

Evaluate sin245.

Answer

sin245=(sin45)2=(12)2=12

Other powers are written in the same fashion. Thus, for example, sin3θ=(sinθ)3.

Checkpoint 5.10

Evaluate tan460

Answer

9

Products

We can multiply together trigonometric expressions, just as we multiply algebraic expressions. Recall that we use the distributive law in computing products such as

x(3x2)=3x22x

and

(x3)(x+5)=x2+2x15

Example 5.11

Using the distributive law, multiply cost(3cost2).

Answer

Think of cost as a single variable, and multiply by each term inside parentheses. (The algebraic form of the calculation is shown on the right in blue).

cost(3cost2)=(cost)(3cost)(cost)2)x(3x2)=x3xx2=3cos2t2cost=3x22x

Notice that we write (cost)2 as cos2t.

Checkpoint 5.12

Multiply 2tanβ(4tan2β+tanα)

Answer

8tan3β+2tanβtanα

We can also use the distributive law to multiply binomials that include trig ratios. You may have used the acronym FOIL to remember the four multiplications in a product of binomials: First terms, Outside terms, Inside terms, and Last terms.

Example 5.13

Multiply (4sinC1)(3sinC+2).

Answer

This calculation is similar to the product (4x1)(3x+2), except that the variable x has been replaced by sinC. Compare the calculations for the two products; first the familiar algebraic product:

(4x1)(3x+2)=4x3x+4x213x12=12x2+8x3x2=12x2+5x2

We compute the product in this example in the same way, but replacing x by sinC.

(4sinC1)(sinC+2)=(4sinC)(3sinC)+(4sinC)21(3sinC)12=12sin2C+5sinC2

Checkpoint 5.14

Expand (4cosα+3)2

Answer

16cos2α+24cosα+9

Factoring

We can factor trigonometric expressions with the same techniques we use for algebraic expressions. In the next two Examples, compare the familiar algebraic factoring with a similar trigonometric expression.

Example 5.15

Factor.

a 6w29w
b 6sin2θ9sinθ

Answer

a We factor out the common factor, 3w.

6w29w=3w(2w3)

b We factor out the common factor, 3sinθ.

6sin2θ9sinθ=3sinθ(2sinθ3)

Checkpoint 5.16

Factor.

a 2a2ab
b 2cos2ϕcosϕsinϕ

Answer

a a(2ab)
b cosϕ(2cosϕsinϕ)

We can also factor quadratic trinomials.

Example 5.17

Factor.

a t23t10
b tan2α3tanα10

Answer

a We look for numbers p and q so that (t+p)(t+q)=t23t10. Their product is pq=10, and their sum is p+q=3. By checking the factors of 10 for the correct sum, we find p=5 and q=2. Thus,

t23t10=(t5)(t+2)

b Now replace t by tanα to find

tan2α3tanα10=(tanα5)(tanα+2)

Checkpoint 5.18

Factor.

a 3z22z1
b 3sin2β2sinβ1

Answer

a (3z+1)(z1)
b (3sinβ+1)(sinβ1)

Review the following skills you will need for this section.

Algebra Refresher 5.1

Factor.

1 2x2+5x12

2 3x22x8

3 12x2+x1

4 6x213x15

5 6x2x12

6 24x2+10x21

Algebra Refresher Answers

1 (2x3)(x+4)

2 (3x+4)(x2)

3 (4x1)(3x+1)

4 (6x+5)(x3)

5 (2x3)(3x+4)

6 (6x+7)(4x3)

Section 5.1 Summary

Vocabulary

• Expression

• Evaluate

• Binomial

• Trinomial

• Simplify

• Equivalent expression

• Like terms

• Distributive law

• Factor

Concepts

1 Expression containing trig ratios can be simplified or evaluated like other algebraic expressions. To simplify an expression containing trig ratios, we treat each ratio as a single variable.

2 sin(X+Y) is not equal to sinX+sinY (and the same holds for the other trig ratios). Remember that the parentheses indicate function notation, not multiplication.

3 We write cos2θ to denote (cosθ)2, and cosnθ to denote (cosθ)n. (Similarly for the other trig ratios.)

4 We can factor trigonometric expressions with the same techniques we use for algebraic expressions.

Study Questions

1 To evaluate cos230, Delbert used the keystrokes

 COS 30x2 ENTER 

and got the answer 1. Were his keystrokes correct? Why or why not?

2 Make up an example to show that tan(θ+ϕ)tanθ+tanϕ.

3 Factor each expression, if possible.

 a x24x e x24x+4 b x24 f x2+4x c x2+4 g x24x4 d x2+4x+4 h x2+4

Skills

1 Evaluate trigonometric expressions #1–22

2 Simplify trigonometric expressions #23–34

3 Recognize equivalent expressions #35–44

4 Multiply or expand trigonometric expressions #45–56

5 Factor trigonometric expressions #57–70

Homework 5.1

For Problems 1-8, evaluate the expressions, using exact values for the trigonometric ratios.

1. 5tan135+6cos60
2. 3tan240+8sin300
3. sin(15+30)
4. cos(275)
5. 8cos2(30)
6. 12sin2(315)
7. 3tan2(150)sin2(45)
8. 1+tan2(120)

For Problems 9-16, evaluate the expressions for x=30,y=45, and z=60. Give exact values for your answers.

9. 3sinx+5cosy
10. 4tany+6cosy
11. 2tan3y
12. sin(3x2x)
13. cos2x+sin2x
14. 7sin2y+7cos2y
15. cosxcosxsinxsinz
16. tan(180x)tanx

For Problems 17–22, evaluate the expressions using a calculator.

17.

a sin(10+40)

b sin10+sin40

c sin10cos40+cos10sin40

18.

a cos(20+50)

b cos20+cos50

c cos20cos50sin20sin50

19.

a cos(224)

b 2cos24

c 2cos2(24)1

20.

a cos(349)

b 3cos49

c 4cos3(49)3cos49

21.

a cos2(17)+sin2(17)

b cos2(86)+sin2(86)

c cos2(111)+sin2(111)

22.

a 1cos2(25)tan2(25)

b 1cos2(100)tan2(100)

c 1cos2(8)tan2(8)

For Problems 23–28, combine like terms.

23.

a 3x2x5x2

b 3cos2θcosθ5cos2θ

24.

a 4x+5yy

b 4cosθ+5sinθsinθ

25.

a 3SC+7SC

b 3sinθcosθ+7sinθcosθ

26.

a 4SC+11SC17SC

b 4sinθcosθ+11sinθcosθ17sinθcosθ

27.

a C2S3+6C2S3

b cos2θsin3θ+6cos2θsin3θ

28.

a 7C2S2(2CS)2

b 7cos2θsin2θ(2cosθsinθ)2

For Problems 29-34, simplify the expression, then evaluate.

29. cost+2costsint3cost, for t=143
30. 11tanw4tanw+6tanwcosw, for w=8
31. 7tanθ4tanϕ+3tanϕ6tanθ, for θ=21,ϕ=89
32. 5sinA+sinB6sinB+6sinA, for A=111,B=26
33. sinxcosxsin(2x)+3sinxcosx, for x=107
34. 4cosusinu+3sin2u10sinucosu, for u=2

For Problems 35–44, decide whether or not the expressions are equivalent. Explain.

35. cos(x+y),cosx+cosy
36. sin(θϕ),sinθsinϕ
37. tan(2A),2tanA
38. cos(12β),12cosβ
39. (sinα)2,sin2α
40. (tanB)2,tan(B2)
41. sin3t+sin5t,sin8t
42. 3cos2x+5cos2x,8cos2x
43. tan(θ+45)tanθ,tan45
44. sin(30+z)+sin(30z),sin60

For Problems 45–56, multiply or expand.

45.

a x(2x1)

b sinA(2sinA1)

46.

a q(5rq)

b cosθ(5sinθcosθ)

47.

a a(b3a)

b tanA(tanB3tanA)

48.

a 3w(2wz)

b 3sinα(2sinαsinβ)

49.

a (C+1)(2C1)

b (cosϕ+1)(2cosϕ1)

50.

a (3S2)(S+1)

b (3sinB2)(sinB+1)

51.

a (a+b)(ab)

b (cosθ+cosϕ)(cosθcosϕ)

52.

a (tw)(t+4w)

b (tanαtanβ)(tanα+4tanβ)

53.

a (1T)2

b (1tanθ)2

54.

a (2+3S)2

b (2+3sinθ)2

55.

a (T2+2)(T22)

b (tan2θ+2)(tan2θ2)

56.

a (2c23)(2c2+3)

b (2cos2ϕ3)(2cos2ϕ+3)

For Problems 57–70, factor.

57.

a 9m+15n

b 9cosα+15cosβ

58.

a 12p20q

b 12sinθ20sinϕ

59.

a 5r210qr

b 5tan2C10tanBtanC

60.

a 2x26xy

b 2sin2a6sinAcosA

61.

a 9C21

b 9cos2β1

62.

a 25S216S

b 25sin2β16sinβ

63.

a 6T38T2

b 6tan3A8tan2A

64.

a 9T215T3

b 9tan2B15tan3B

65.

a t2t20

b tan2θtanθ20

66.

a s2+5s6

b sin2A+5sinA6

67.

a 3c2+2c1

b 3cos2B+2cosB1

68.

a 8S26S+1

b 8sin2ϕ6sinϕ+1

69.

a 6S25S1

b 6sin2α5sinα1

70.

a T24T12

b tan2α4tanα12


This page titled 5.0: Algebra with Trigonometric Ratios is shared under a GNU Free Documentation License 1.3 license and was authored, remixed, and/or curated by Katherine Yoshiwara via source content that was edited to the style and standards of the LibreTexts platform.

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