9.1: Area Between Curves
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We have seen how integration can be used to find an area between a curve and the x-axis. With very little change we can find some areas between curves; indeed, the area between a curve and the x-axis may be interpreted as the area between the curve and a second "curve'' with equation y=0. In the simplest of cases, the idea is quite easy to understand.

It is clear from the figure that the area we want is the area under f minus the area under g, which is to say ∫21f(x)dx−∫21g(x)dx=∫21f(x)−g(x)dx. It doesn't matter whether we compute the two integrals on the left and then subtract or compute the single integral on the right. In this case, the latter is perhaps a bit easier: ∫21f(x)−g(x)dx=∫21−x2+4x+3−(−x3+7x2−10x+5)dx=∫21x3−8x2+14x−2dx=x44−8x33+7x2−2x|21=164−643+28−4−(14−83+7−2)=23−563−14=4912.
It is worth examining this problem a bit more. We have seen one way to look at it, by viewing the desired area as a big area minus a small area, which leads naturally to the difference between two integrals. But it is instructive to consider how we might find the desired area directly. We can approximate the area by dividing the area into thin sections and approximating the area of each section by a rectangle, as indicated in figure 9.1.2. The area of a typical rectangle is Δx(f(xi)−g(xi)), so the total area is approximately n−1∑i=0(f(xi)−g(xi))Δx. This is exactly the sort of sum that turns into an integral in the limit, namely the integral ∫21f(x)−g(x)dx. Of course, this is the integral we actually computed above, but we have now arrived at it directly rather than as a modification of the difference between two other integrals. In that example it really doesn't matter which approach we take, but in some cases this second approach is better.

Contributors and Attributions
Integrated by Justin Marshall.