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5.5: Graphs of Logarithmic Functions

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    34006
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    Skills to Develop

    • Identify the domain of a logarithmic function.
    • Graph logarithmic functions.

    In Section 5.3, we saw how creating a graphical representation of an exponential model gives us another layer of insight for predicting future events. How do logarithmic graphs give us insight into situations? Because every logarithmic function is the inverse function of an exponential function, we can think of every output on a logarithmic graph as the input for the corresponding inverse exponential equation. In other words, logarithms give the cause for an effect.

    To illustrate, suppose we invest \($2500\) in an account that offers an annual interest rate of \(5\%\),compounded continuously. We already know that the balance in our account for any year \(t\) can be found with the equation \(A=2500e^{0.05t}\).

    But what if we wanted to know the year for any balance? We would need to create a corresponding new function by interchanging the input and the output; thus we would need to create a logarithmic model for this situation. By graphing the model, we can see the output (year) for any input (account balance). For instance, what if we wanted to know how many years it would take for our initial investment to double? Figure \(\PageIndex{1}\) shows this point on the logarithmic graph.

    fig 6.5.1.jpg

    Figure \(\PageIndex{1}\)

    In this section we will discuss the values for which a logarithmic function is defined, and then turn our attention to graphing the family of logarithmic functions.

    Finding the Domain of a Logarithmic Function

    Before working with graphs, we will take a look at the domain (the set of input values) for which the logarithmic function is defined.

    Recall that the exponential function is defined as \(y=b^x\) for any real number \(x\) and constant \(b>0\), \(b≠1\), where

    • The domain of \(y\) is \((−\infty,\infty)\).
    • The range of \(y\) is \((0,\infty)\).

    In the last section we learned that the logarithmic function \(y={\log}_b(x)\) is the inverse of the exponential function \(y=b^x\). So, as inverse functions:

    • The domain of \(y={\log}_b(x)\) is the range of \(y=b^x\): \((0,\infty)\).
    • The range of \(y={\log}_b(x)\) is the domain of \(y=b^x\): \((−\infty,\infty)\).

    Transformations of the toolkit function \(y={\log}_b(x)\) behave similarly to those of other functions. Just as with other toolkit functions, we can apply the four types of transformations—shifts, stretches, compressions, and reflections—to the toolkit function without loss of shape.

    In Section 5.3 we saw that certain transformations can change the range of \(y=b^x\). Similarly, applying transformations to the toolkit function \(y={\log}_b(x)\) can change the domain. When finding the domain of a logarithmic function, therefore, it is important to remember that the domain consists only of positive real numbers. That is, the input value, or argument, of the logarithmic function must be greater than zero.

    For example, consider \(f(x)={\log}_4(2x−3)\). This function is defined for any values of \(x\) such that the argument, in this case \(2x−3\),is greater than zero. To find the domain, we set up an inequality and solve for \(x\):

    \[\begin{align*} 2x-3&> 0 \qquad \text {Show the argument greater than zero}\\ 2x&> 3 \qquad \text{Add 3} \\ x&> 1.5 \qquad \text{Divide by 2} \\ \end{align*}\]

    In interval notation, the domain of \(f(x)={\log}_4(2x−3)\) is \((1.5,\infty)\).

    how-to.png Given a logarithmic function, identify the domain

    1. Set up an inequality showing the argument greater than zero.
    2. Solve for \(x\).
    3. Write the domain in interval notation.

    Example \(\PageIndex{1}\): Identifying the Domain of a Logarithmic Shift

    What is the domain of \(f(x)={\log}_2(x+3)\)?

    Solution

    The logarithmic function is defined only when the input is positive, so this function is defined when \(x+3>0\). Solving this inequality,

    \[\begin{align*} x+3&> 0 \qquad \text{The input must be positive}\\ x&> -3 \qquad \text{Subtract 3} \end{align*}\]

    The domain of \(f(x)={\log}_2(x+3)\) is \((−3,\infty)\).

    try-it.png \(\PageIndex{1}\)

    What is the domain of \(f(x)={\log}_5(x−2)+1\)?

    Answer

    \((2,\infty)\)

    Graphing Logarithmic Functions

    Now that we have a feel for the set of values for which a logarithmic function is defined, we move on to graphing logarithmic functions. The family of logarithmic functions includes the toolkit function \(y={\log}_b(x)\) along with all its transformations: shifts, stretches, compressions, and reflections.

    We begin with the toolkit function \(y={\log}_b(x)\). Because every logarithmic function of this form is the inverse of an exponential function with the form \(y=b^x\), their graphs will be reflections of each other across the line \(y=x\). To illustrate this, we can observe the relationship between the input and output values of \(y=2^x\) and its equivalent \(x={\log}_2(y)\) in Table \(\PageIndex{1}\).

    Table \(\PageIndex{1}\)
    \(x\) \(−3\) \(−2\) \(−1\) \(0\) \(1\) \(2\) \(3\)
    \(2^x=y\) \(\dfrac{1}{8}\) \(\dfrac{1}{4}\) \(\dfrac{1}{2}\) \(1\) \(2\) \(4\) \(8\)
    \({\log}_2(y)=x\) \(−3\) \(−2\) \(−1\) \(0\) \(1\) \(2\) \(3\)

    Using the inputs and outputs from Table \(\PageIndex{1}\), we can build another table to observe the relationship between points on the graphs of the inverse functions \(f(x)=2^x\) and \(g(x)={\log}_2(x)\). See Table \(\PageIndex{2}\).

    Table \(\PageIndex{2}\)

    \(f(x)=2^x\)

    \(\left(−3,\dfrac{1}{8}\right)\)

    \(\left(−2,\dfrac{1}{4}\right)\)

    \(\left(−1,\dfrac{1}{2}\right)\)

    \((0,1)\)

    \((1,2)\)

    \((2,4)\)

    \((3,8)\)

    \(g(x)={\log}_2(x)\)

    \(\left(\dfrac{1}{8},−3\right)\)

    \(\left(\dfrac{1}{4},−2\right)\)

    \(\left(\dfrac{1}{2},−1\right)\)

    \((1,0)\)

    \((2,1)\)

    \((4,2)\)

    \((8,3)\)

    As expected, the \(x\)- and \(y\)-coordinates are reversed for the inverse functions. Figure \(\PageIndex{2}\) shows the graph of \(f\) and \(g\).

    fig 6.5.2.jpg

    Figure \(\PageIndex{2}\): Notice that the graphs of \(f(x)=2^x\) and \(g(x)={\log}_2(x)\) are reflections about the line \(y=x\).

    Observe the following from the graph:

    • \(f(x)=2^x\) has a \(y\)-intercept at \((0,1)\) and \(g(x)={\log}_2(x)\) has an \(x\)-intercept at \((1,0)\).
    • The domain of \(f(x)=2^x\), \((−\infty,\infty)\), is the same as the range of \(g(x)={\log}_2(x)\).
    • The range of \(f(x)=2^x\), \((0,\infty)\), is the same as the domain of \(g(x)={\log}_2(x)\).

    CHARACTERISTICS OF THE GRAPH OF THE toolkit FUNCTION, \(f(x) = \log_b(x)\)

    For any real number \(x\) and constant \(b>0\), \(b≠1\), we can see the following characteristics in the graph of \(f(x)={\log}_b(x)\):

    • one-to-one function
    • vertical asymptote: \(x=0\)
    • domain: \((0,\infty)\)
    • range: \((−\infty,\infty)\) 
    • \(x\)-intercept: \((1,0)\) and key point \((b,1)\)
    • \(y\)-intercept: none
    • increasing if \(b>1\)
    • decreasing if \(0<b<1\)

    See Figure \(\PageIndex{3}\).

    fig 6.5.3.jpg

    Figure \(\PageIndex{3}\)

    Figure \(\PageIndex{4}\) shows how changing the base \(b\) in \(f(x)={\log}_b(x)\) can affect the graphs. Observe that the graphs compress vertically as the value of the base increases. (Note: recall that the function \(\ln(x)\) has base \(e≈2.718\).)

    fig 6.5.4.jpg

    Figure \(\PageIndex{4}\): The graphs of three logarithmic functions with different bases, all greater than 1.

    how-to.pngGiven a logarithmic function with the form \(f(x)={\log}_b(x)\), graph the function.

    1. Draw and label the vertical asymptote, \(x=0\).
    2. Plot the x-intercept, \((1,0)\).
    3. Plot the key point \((b,1)\).
    4. Draw a smooth curve through the points.
    5. State the domain, \((0,\infty)\),the range, \((−\infty,\infty)\), and the vertical asymptote, \(x=0\).

    Example \(\PageIndex{2}\): Graphing a Logarithmic Function with the Form \(f(x) = log_b(x)\)

    Graph \(f(x)={\log}_5(x)\). State the domain, range, and asymptote.

    Solution

    Before graphing, identify the behavior and key points for the graph.

    • Since \(b=5\) is greater than one, we know the function is increasing. The left tail of the graph will approach the vertical asymptote \(x=0\), and the right tail will increase slowly without bound.
    • The \(x\)-intercept is \((1,0)\).
    • The key point \((5,1)\) is on the graph.
    • We draw and label the asymptote, plot and label the points, and draw a smooth curve through the points (see Figure \(\PageIndex{5}\)).

    fig 6.5.5.jpg

    Figure \(\PageIndex{5}\)

    The domain is \((0,\infty)\), the range is \((−\infty,\infty)\), and the vertical asymptote is \(x=0\).

    try-it.png \(\PageIndex{2}\)

    Graph \(f(x)={\log}_{\tfrac{1}{5}}(x)\). State the domain, range, and asymptote.

    Answer

    fig 6.5.6.jpg

    Figure \(\PageIndex{6}\)

    The domain is \((0,\infty)\), the range is \((−\infty,\infty)\), and the vertical asymptote is \(x=0\).

    Graphing Transformations of Logarithmic Functions

    As we mentioned in the beginning of the section, transformations of logarithmic graphs behave similarly to those of other toolkit functions. We can shift and reflect the toolkit function \(y={\log}_b(x)\) without loss of shape.

    Graphing a Horizontal Shift of \(f(x) = log_b(x)\)

    When a positive constant \(c\) is added or subtracted to the input of the toolkit function \(f(x)={\log}_b(x)\), the result is a horizontal shift \(c\) units left if \(c\) is positive and \(c\) units right if \(c\) is negative. To visualize horizontal shifts, we can observe the general graph of the toolkit function \(f(x)={\log}_b(x)\) and for \(c>0\) alongside the shift left, \(g(x)={\log}_b(x+c)\), and the shift right, \(h(x)={\log}_b(x−c)\). See Figure \(\PageIndex{7}\).

    fig 6.5.7.jpg

    Figure \(\PageIndex{7}\)

    HORIZONTAL SHIFTS OF THE toolkit FUNCTION \(y=\log_b(x)\)

    For any constant \(c\), the function \(f(x)={\log}_b(x+c)\)

    • shifts the toolkit function \(y={\log}_b(x)\) left \(c\) units if \(c>0\).
    • shifts the toolkit function \(y={\log}_b(x)\) right \(|c|\) units if \(c<0\).
    • has the vertical asymptote \(x=−c\).
    • has domain \((−c,\infty)\).
    • has range \((−\infty,\infty)\).

    how-to.png Given a logarithmic function with the form \(f(x)=\log_b(x+c)\), graph the translation.

    1. Identify the horizontal shift:
      • If \(c>0\),shift the graph of \(f(x)={\log}_b(x)\) left \(c\) units.
      • If \(c<0\),shift the graph of \(f(x)={\log}_b(x)\) right \(|c|\) units.
    2. Draw the vertical asymptote \(x=−c\).
    3. Identify three key points from the toolkit function, including the \(x\)-intercept \((1,0)\), the point \((b,1)\), and one other point. Find new coordinates for the shifted functions by subtracting \(c\) from the \(x\)-coordinate.
    4. Label the three points.
    5. The domain is \((−c,\infty)\),the range is \((−\infty,\infty)\), and the vertical asymptote is \(x=−c\).

    Example \(\PageIndex{3}\): Graphing a Horizontal Shift of the toolkit Function \(y = \log_b(x)\)

    Sketch the horizontal shift \(f(x)={\log}_3(x−2)\) alongside its toolkit function. Include the key points and asymptotes on the graph. State the domain, range, and asymptote.

    Solution

    Since the function is \(f(x)={\log}_3(x−2)\), we notice \(x+(−2)=x–2\).

    Thus \(c=−2\), so \(c<0\). This means we will shift the function \(f(x)={\log}_3(x)\) right 2 units.

    The vertical asymptote is \(x=−(−2)\) or \(x=2\).

    Consider the three key points from the toolkit function, \(\left(\dfrac{1}{3},−1\right)\), \((1,0)\),and \((3,1)\).

    The new coordinates are found by adding \(2\) to the \(x\) coordinates.

    Label the points \(\left(\dfrac{7}{3},−1\right)\), \((3,0)\),and \((5,1)\).

    The domain is \((2,\infty)\),the range is \((−\infty,\infty)\),and the vertical asymptote is \(x=2\).

    fig 6.5.8.jpg

    Figure \(\PageIndex{8}\)

    try-it.png \(\PageIndex{3}\)

    Sketch a graph of \(f(x)={\log}_3(x+4)\) alongside its toolkit function. Include the key points and asymptotes on the graph. State the domain, range, and asymptote.

    Answer

    fig 6.5.9.jpg

    Figure \(\PageIndex{9}\)

    The domain is \((−4,\infty)\),the range \((−\infty,\infty)\),and the asymptote \(x=–4\).

    Graphing a Vertical Shift of \(y = \log_b(x)\)

    When a positive constant \(d\) is added or subtracted to the toolkit function \(f(x)={\log}_b(x)\),the result is a vertical shift \(d\) units up if \(d\) is added and \(d\) units down if \(d\) is subtracted. 

    VERTICAL SHIFTS OF THE toolkit FUNCTION \(y=\log_b(x)\)

    For any constant \(d\), the function \(f(x)=\log_b(x)+d\)

    • shifts the toolkit function \(y={\log}_b(x)\) up \(d\) units if \(d>0\).
    • shifts the toolkit function \(y={\log}_b(x)\) down \(|d|\) units if \(d<0\).
    • has the vertical asymptote \(x=0\).
    • has domain \((0,\infty)\).
    • has range \((−\infty,\infty)\).

    how-to.png Given a logarithmic function with the form \(f(x)={\log}_b(x)+d\), graph the translation.

    1. Identify the vertical shift:
      • If \(d>0\), shift the graph of \(f(x)={\log}_b(x)\) up \(d\) units.
      • If \(d<0\), shift the graph of \(f(x)={\log}_b(x)\) down \(|d|\) units.
    2. Draw the vertical asymptote \(x=0\).
    3. Identify three key points from the toolkit function. Find new coordinates for the shifted functions by adding \(d\) to the \(y\)-coordinate.
    4. Label the three points.
    5. The domain is \((0,\infty)\), the range is \((−\infty,\infty)\),and the vertical asymptote is \(x=0\).

    Example \(\PageIndex{4}\): Graphing a Vertical Shift of the toolkit Function \(y = log_b(x)\)

    Sketch a graph of \(f(x)={\log}_3(x)−2\) alongside its toolkit function. Include the key points and asymptote on the graph. State the domain, range, and asymptote.

    Solution

    Since the function is \(f(x)={\log}_3(x)−2\), we notice \(d= -2\). Thus \(d<0\).

    This means we will shift the function \(f(x)={\log}_3(x)\) down \(2\) units.

    The vertical asymptote is \(x=0\).

    Consider these three key points from the toolkit function, \(\left(\dfrac{1}{3},−1\right)\), \((1,0)\), and \((3,1)\).

    The new coordinates are found by subtracting \(2\) from the \(y\)-coordinates.

    Label the points \(\left(\dfrac{1}{3},−3\right)\), \((1,−2)\), and \((3,−1)\).

    The domain is \((0,\infty)\), the range is \((−\infty,\infty)\), and the vertical asymptote is \(x=0\).

    fig 6.5.11.jpg

    Figure \(\PageIndex{10}\)

    The domain is \((0,\infty)\),the range is \((−\infty,\infty)\),and the vertical asymptote is \(x=0\).

    try-it.png \(\PageIndex{4}\)

    Sketch a graph of \(f(x)={\log}_2(x)+2\) alongside its toolkit function. Include the key points and asymptote on the graph. State the domain, range, and asymptote.

    Answer

    fig 6.5.12.jpg

    Figure \(\PageIndex{11}\)

    The domain is \((0,\infty)\),the range is \((−\infty,\infty)\), and the vertical asymptote is \(x=0\).
    Good job, trying this problem, and checking your answer! If you look carefully at the graph of the shifted function \(f\), you will see that the labeled points are not vertical shifts of the two labeled points on the toolkit function. What are the correct points of the vertical shifts? Show them to your professor and make her give you extra credit!

     

    Graphing Reflections of \(f(x) = \log_b(x)\)

    When the toolkit function \(f(x)={\log}_b(x)\) is multiplied by \(−1\), the result is a reflection across the \(x\)-axis. When the input is multiplied by \(−1\), the result is a reflection across the \(y\)-axis.

    REFLECTIONS OF THE toolkit FUNCTION \(y=\log_b(x)\)

    The function \(f(x)=-\log_b(x)\)

    • reflects the toolkit function \(y={\log}_b(x)\) across the \(x\)-axis.
    • has domain, \((0,\infty)\), range, \((−\infty,\infty)\), and vertical asymptote, \(x=0\), which are unchanged from the toolkit function.

    The function \(f(x)={\log}_b(−x)\)

    • reflects the toolkit function \(y={\log}_b(x)\) across the \(y\)-axis.
    • has domain \((−\infty,0)\).
    • has range, \((−\infty,\infty)\), and vertical asymptote, \(x=0\), which are unchanged from the toolkit function.

    how-to.png Given a logarithmic function with the toolkit function \(f(x)=\log_b(x),\) graph a REFLECTION.

    Table \(\PageIndex{3}\)
    If \(f(x)=-\log_b(x)\) If \(f(x)=\log_b(−x)\)
    1. Draw the vertical asymptote, \(x=0\).
    1. Draw the vertical asymptote, \(x=0\).
    1. Plot the x-intercept, \((1,0)\).
    1. Plot the x-intercept, \((-1,0)\).
    1. Reflect the graph of the toolkit function \(f(x)={\log}_b(x)\) across the x-axis.
    1. Reflect the graph of the toolkit function \(f(x)={\log}_b(x)\) across the y-axis.
    1. Draw a smooth curve through the points.
    1. Draw a smooth curve through the points.
    1. State the domain, \((0,\infty)\), the range, \((−\infty,\infty)\), and the vertical asymptote \(x=0\).
    1. State the domain, \((−\infty,0)\), the range, \((−\infty,\infty)\), and the vertical asymptote \(x=0\).
     

    Example \(\PageIndex{5}\): Graphing a Reflection of a Logarithmic Function

    Sketch a graph of \(f(x)=\log(−x)\) alongside its toolkit function. Include the key points and asymptote on the graph. State the domain, range, and asymptote.

    Solution

    Before graphing \(f(x)=\log(−x)\), identify the behavior and key points for the graph.

    • Since \(b=10\) is greater than one, we know that the toolkit function is increasing. Since the input value is multiplied by \(−1\), \(f(x)\) is a reflection of the toolkit graph across the \(y\)-axis. Thus, \(f(x)=\log(−x)\) will be decreasing as \(x\) moves from negative infinity to zero, and the right tail of the graph will approach the vertical asymptote \(x=0\). 
    • The \(x\)-intercept is \((−1,0)\).
    • We draw and label the asymptote, plot and label the points, and draw a smooth curve through the points.

    fig 6.5.19.jpg

    Figure \(\PageIndex{16}\)

    The domain is \((−\infty,0)\), the range is \((−\infty,\infty)\), and the vertical asymptote is \(x=0\).

    try-it.png \(\PageIndex{5}\)

    Graph \(f(x)=−\log(−x)\). State the domain, range, and asymptote.

    Answer

    fig 6.5.20.jpg

    Figure \(\PageIndex{17}\)

    The domain is \((−\infty,0)\),the range is \((−\infty,\infty)\),and the vertical asymptote is \(x=0\).

    Summarizing Transformations of the Logarithmic Function

    Now that we have worked with each type of translation for the logarithmic function, we can summarize each in Table \(\PageIndex{4}\) to arrive at the general equation for translating exponential functions.

    Table \(\PageIndex{4}\)

    Translations of the toolkit Function \(y={\log}_b(x)\)
    Translation Form

    Shift

    Horizontally \(c\) units to the left or right

    Vertically \(d\) units up or down

    \(y={\log}_b(x+c)+d\)
    Reflect about the \(x\)-axis \(y=−{\log}_b(x)\)
    Reflect about the \(y\)-axis \(y={\log}_b(−x)\)
    General equation for all translations

    \(y=\log_b(x+c)+d\)

    Finding the Vertical Asymptote

    Example \(\PageIndex{6}\): Finding the Vertical Asymptote of a Logarithm Graph

    What is the vertical asymptote of \(f(x)=\log_3(x+4)+5\)?

    Solution

    The vertical asymptote is at \(x=−4\).

    Analysis

    The base and the upward translation do not affect the asymptote. The shift of the curve \(4\) units to the left shifts the vertical asymptote to \(x=−4\).

    try-it.png \(\PageIndex{6}\)

    What is the vertical asymptote of \(f(x)=3+\ln(x−1)\)?

    Answer

    \(x=1\)

    Media

    Access these online resources for additional instruction and practice with graphing logarithms.

    Key Equations

    General Form for the Translation of the toolkit Logarithmic Function \(f(x)={\log}_b(x)\) \(f(x)={\log}_b(x+c)+d\)

    Key Concepts

    • To find the domain of a logarithmic function, set up an inequality showing the argument greater than zero, and solve for \(x\). See Example \(\PageIndex{1}\) and Example \(\PageIndex{2}.\)
    • The graph of the toolkit function \(f(x)={\log}_b(x)\) has an x-intercept at \((1,0)\), domain \((0,\infty)\), range \((−\infty,\infty)\),vertical asymptote \(x=0\), and
      • if \(b>1\), the function is increasing.
      • if \(0<b<1\), the function is decreasing.

    See Figure \(\PageIndex{3}\).

    • The equation \(f(x)={\log}_b(x+c)\) shifts the toolkit function \(y={\log}_b(x)\) horizontally.
      • left \(c\) units if \(c>0\).
      • right \(c\) units if \(c<0\).

    See Example \(\PageIndex{3}\).

    • The equation \(f(x)={\log}_b(x)+d\) shifts the toolkit function \(y={\log}_b(x)\) vertically.
      • up \(d\) units if \(d>0\).
      • down \(d\) units if \(d<0\).

    See Example \(\PageIndex{4}\).

    • When the toolkit function \(y={\log}_b(x)\) is multiplied by \(−1\), the result is a reflection across the x-axis. When the input is multiplied by \(−1\), the result is a reflection across the y-axis.
      • The equation \(f(x)=-{\log}_b(x)\) represents a reflection of the toolkit function across the x-axis.
      • The equation \(f(x)={\log}_b(-x)\) represents a reflection of the toolkit function across the y-axis.

    See Example \(\PageIndex{5}\).

    • Translations of the logarithmic function can be summarized by the general equation \(f(x)={\log}_b(x+c)+d\). See Table \(\PageIndex{4}\).
    • Given an equation with the general form \(f(x)={\log}_b(x+c)+d\),we can identify the vertical asymptote \(x=−c\) for the transformation. See Example \(\PageIndex{6}\).

    Contributors

    • Lynn Marecek (Santa Ana College) and MaryAnne Anthony-Smith (formerly of Santa Ana College). This content produced by OpenStax and is licensed under a Creative Commons Attribution License 4.0 license.

    This page titled 5.5: Graphs of Logarithmic Functions is shared under a CC BY 4.0 license and was authored, remixed, and/or curated by OpenStax via source content that was edited to the style and standards of the LibreTexts platform; a detailed edit history is available upon request.