Skip to main content
Mathematics LibreTexts

4.14: Arithmetic Sequences

  1. Last updated
  2. Save as PDF
  • Page ID
    163841

    • \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)

    \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)

    \( \newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\)

    ( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\)

    \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)

    \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\)

    \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)

    \( \newcommand{\Span}{\mathrm{span}}\)

    \( \newcommand{\id}{\mathrm{id}}\)

    \( \newcommand{\Span}{\mathrm{span}}\)

    \( \newcommand{\kernel}{\mathrm{null}\,}\)

    \( \newcommand{\range}{\mathrm{range}\,}\)

    \( \newcommand{\RealPart}{\mathrm{Re}}\)

    \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)

    \( \newcommand{\Argument}{\mathrm{Arg}}\)

    \( \newcommand{\norm}[1]{\| #1 \|}\)

    \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)

    \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\AA}{\unicode[.8,0]{x212B}}\)

    \( \newcommand{\vectorA}[1]{\vec{#1}}      % arrow\)

    \( \newcommand{\vectorAt}[1]{\vec{\text{#1}}}      % arrow\)

    \( \newcommand{\vectorB}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)

    \( \newcommand{\vectorC}[1]{\textbf{#1}} \)

    \( \newcommand{\vectorD}[1]{\overrightarrow{#1}} \)

    \( \newcommand{\vectorDt}[1]{\overrightarrow{\text{#1}}} \)

    \( \newcommand{\vectE}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{\mathbf {#1}}}} \)

    \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)

    \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)

    \(\newcommand{\avec}{\mathbf a}\) \(\newcommand{\bvec}{\mathbf b}\) \(\newcommand{\cvec}{\mathbf c}\) \(\newcommand{\dvec}{\mathbf d}\) \(\newcommand{\dtil}{\widetilde{\mathbf d}}\) \(\newcommand{\evec}{\mathbf e}\) \(\newcommand{\fvec}{\mathbf f}\) \(\newcommand{\nvec}{\mathbf n}\) \(\newcommand{\pvec}{\mathbf p}\) \(\newcommand{\qvec}{\mathbf q}\) \(\newcommand{\svec}{\mathbf s}\) \(\newcommand{\tvec}{\mathbf t}\) \(\newcommand{\uvec}{\mathbf u}\) \(\newcommand{\vvec}{\mathbf v}\) \(\newcommand{\wvec}{\mathbf w}\) \(\newcommand{\xvec}{\mathbf x}\) \(\newcommand{\yvec}{\mathbf y}\) \(\newcommand{\zvec}{\mathbf z}\) \(\newcommand{\rvec}{\mathbf r}\) \(\newcommand{\mvec}{\mathbf m}\) \(\newcommand{\zerovec}{\mathbf 0}\) \(\newcommand{\onevec}{\mathbf 1}\) \(\newcommand{\real}{\mathbb R}\) \(\newcommand{\twovec}[2]{\left[\begin{array}{r}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\ctwovec}[2]{\left[\begin{array}{c}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\threevec}[3]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\cthreevec}[3]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\fourvec}[4]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\cfourvec}[4]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\fivevec}[5]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\cfivevec}[5]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\mattwo}[4]{\left[\begin{array}{rr}#1 \amp #2 \\ #3 \amp #4 \\ \end{array}\right]}\) \(\newcommand{\laspan}[1]{\text{Span}\{#1\}}\) \(\newcommand{\bcal}{\cal B}\) \(\newcommand{\ccal}{\cal C}\) \(\newcommand{\scal}{\cal S}\) \(\newcommand{\wcal}{\cal W}\) \(\newcommand{\ecal}{\cal E}\) \(\newcommand{\coords}[2]{\left\{#1\right\}_{#2}}\) \(\newcommand{\gray}[1]{\color{gray}{#1}}\) \(\newcommand{\lgray}[1]{\color{lightgray}{#1}}\) \(\newcommand{\rank}{\operatorname{rank}}\) \(\newcommand{\row}{\text{Row}}\) \(\newcommand{\col}{\text{Col}}\) \(\renewcommand{\row}{\text{Row}}\) \(\newcommand{\nul}{\text{Nul}}\) \(\newcommand{\var}{\text{Var}}\) \(\newcommand{\corr}{\text{corr}}\) \(\newcommand{\len}[1]{\left|#1\right|}\) \(\newcommand{\bbar}{\overline{\bvec}}\) \(\newcommand{\bhat}{\widehat{\bvec}}\) \(\newcommand{\bperp}{\bvec^\perp}\) \(\newcommand{\xhat}{\widehat{\xvec}}\) \(\newcommand{\vhat}{\widehat{\vvec}}\) \(\newcommand{\uhat}{\widehat{\uvec}}\) \(\newcommand{\what}{\widehat{\wvec}}\) \(\newcommand{\Sighat}{\widehat{\Sigma}}\) \(\newcommand{\lt}{<}\) \(\newcommand{\gt}{>}\) \(\newcommand{\amp}{&}\) \(\definecolor{fillinmathshade}{gray}{0.9}\)
    Learning Objectives

    After completing this section, you should be able to:

    • Identify arithmetic sequences.
    • Find a given term in an arithmetic sequence.
    • Find the nnth term of an arithmetic sequence.
    • Find the sum of a finite arithmetic sequence.
    • Use arithmetic sequences to solve real-world applications

     

    As we saw in the previous section, we are adding about 2.5 quintillion bytes of data per day to the Internet. If there are 550 quintillion bytes of data today, then there will be 552.5 quintillion bytes tomorrow, and 555 quintillion bytes in 2 days. This is an example of an arithmetic sequence. There are many situations where this concept of fixed increases comes into play, such as raises or table arrangements.

    Identifying Arithmetic Sequences

    A sequence of numbers is just that, a list of numbers in order. It can be a short list, such as the number of points earned on each assignment in a class, such as {10, 10, 8, 9, 10, 6, 10}. Or it can be a longer list, even infinitely long, such as the list of prime numbers. For example, here’s a sequence of numbers, specifically, the squares of the first 12 natural numbers.

    {1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144}

    Each value in the sequence is called a term. Terms in the list are often referred to by their location in the sequence, as in the Figure 3.48).

    A sequence of numbers. The numbers are as follows: 10, 10, 8, 9, 10, 6, and 10. A callout to the first 10 reads, First term, a sub 1. A callout to the second 10 reads, Second term, a sub 2. A callout to the third 10 reads, Fifth term, a sub 5.
    Figure 3.48 Sequence showing first, second, and fifth terms

    The notation we use with sequences is a letter, which represents a term in the sequence, and a subscript, which indicates what place the term is in the sequence. For the sequence {1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144}, we will use the letter aa as a value in the sequence, and so (\a_5\) would be the term in the sequence at the fifth position. That number is 25, so we can write a5=25.

    In this section, we focus on a special kind of sequence, one referred to as an arithmetic sequence. Arithmetic sequences have terms that increase by a fixed number or decrease by a fixed number, called the constant difference (denoted by dd), provided that value is not 0. This means the next term is always the previous term plus or minus a specified, constant value. Another way to say this is that the difference between any consecutive terms of the sequence is always the same value.

    To see a constant difference, look at the following sequence: {7, 15, 23, 31, 39, 47, 55, 63, 71, 79, 87}. Figure 3.49 illustrates that each term of the sequence is the previous term plus 8. Eight is the constant difference here.

    A sequence of numbers. The numbers are as follows: 7, 15, 23, 31, 39, 47, 55, 63, 71, 79, and 87. Hops labeled plus 8 from each number points to the next number from left to right.
    Figure 3.49 Sequence of numbers with 8 added to each term
    Example \(\PageIndex{1}\)

    Identifying Arithmetic Sequences

    Determine if the following sequences are arithmetic sequences. Explain your reasoning.

    1. {4,7,10,13,16,19,22,25,...}{4,7,10,13,16,19,22,25,...}
    2. {20,40,80,160,320,640}{20,40,80,160,320,640}
    3. {7,1,−5,−11,−17,−23,−29,−34,−40}{7,1,−5,−11,−17,−23,−29,−34,−40}
    Answer

     

    1. In the sequence {4,7,10,13,16,19,22,25,...}{4,7,10,13,16,19,22,25,...}, every term is the previous term plus 3. The ellipsis indicates that the pattern continues, which means keep adding 3 to the previous term to get the new term. Therefore, this is an infinite arithmetic sequence.
    2. In the sequence {20,40,80,160,320,640}{20,40,80,160,320,640}, terms increase by various amounts, for instance from term 1 to term 2, the sequence increases by 20, but from term 2 to term 3 the sequence increases by 40. So, this is not an arithmetic sequence.
    3. In the sequence {7,1,−5,−11,−17,−23,−29,−34,−40}{7,1,−5,−11,−17,−23,−29,−34,−40}, every term is the previous term minus 6, so this is an arithmetic sequence.
    Your Turn \(\PageIndex{1}\)
    Determine if the following sequences are arithmetic sequences. Explain your reasoning.
    1. {7.6, 5.4, 3.2, 1.0, -1.2, -3.4, -5.6, -7.8, -10.0}
    2. {14, 16, 18, 22, 28, 40, 32, 0}
    3. {14, 20, 26, 32, 38, 44, 50, 56, 62, 68, 74, 80, ...}

    Arithmetic sequences can be expressed with a formula. When we know the first term of an arithmetic sequence, which we label \(a_1\) a1a1, and we know the constant difference, which is denoted \(d\), we can find any other term of the arithmetic sequence. The formula for the \(i\)th term of an arithmetic sequence is \(a_i = a_1 + d \times (i - 1)\).

    FORMULA \(\PageIndex{1}\)

    If we have an arithmetic sequence with the first term \(a_1\) and constant difference \(d\), then the \(i\)th term of the arithmetic sequence is \(a_i = a_1 + d \times (i - 1)\).

    Let’s examine the formula with this arithmetic sequence: {4,7,10,13,16,19,22,25,...}{4,7,10,13,16,19,22,25,...}. In this sequence a1=4 and d=3d=3. The table below shows the values calculated.

    ii, Place in Sequence ai, ith Term Value of Term Term Written as a1+3×(i−1)a1+3×(i−1)
    1 a1a1 4 4+3×04+3×0
    2 a2a2 7 4+3×14+3×1
    3 a3a3 10 4+3×24+3×2
    4 a4a4 13 4+3×34+3×3
    5 a5a5 16 4+3×44+3×4
    ii aiai   4+3×(i−1)4+3×(i−1)

    We can see how the ithith term can be directly calculated. In this sequence, the formula is a1+3×(i−1)a1+3×(i−1) where the first term, a1a1, is 4 and the constant difference dd is 3. We can then determine the 47th47th term of this sequence: a47=4+3×(47−1)=4+3×46=4+138=142a47=4+3×(47−1)=4+3×46=4+138=142.

    Example \(\PageIndex{2}\)

    Calculating a Term in an Arithmetic Sequence

    Identify a1a1 and dd for the following arithmetic sequence. Use this information to determine the 60th60th term.

    {18,31,44,57,70,83,...}{18,31,44,57,70,83,...}

    Answer

     

    Inspecting the sequence shows that a1=18a1=18 and d=13d=13. We use those values in the formula, with i=60i=60.

    a60=a1+d×(i−1)=18+13×(60−1)=18+13×59=18+767=785a60=a1+d×(i−1)=18+13×(60−1)=18+13×59=18+767=785
    Your Turn \(\PageIndex{2}\)

    Identify \(a_1\) and \(d\) for the following arithmetic sequence. Use this information to determine the \(86^{th}\) term.

     {4.5,8.1,11.7,15.3,18.9,22.5,26.1,...} 
     
    Video \(\PageIndex{1}\)

    Arithmetic Sequences

    If we know two terms of the sequence, it is possible to determine the general form of an arithmetic sequence, ai=a1+d×(i−1)ai=a1+d×(i−1).

    FORMULA \(\PageIndex{2}\)

    If we have the iith term of an arithmetic sequence, aiai, and the jjth term of the sequence, ajaj, then the constant difference is d=aj−aij−id=aj−aij−i and the first term of the sequence is a1=ai−d(i−1)a1=ai−d(i−1).

    Example \(\PageIndex{3}\)

    Determining First Term and Constant Difference Using Two Terms

    A sequence is known to be arithmetic. Two of its terms are a7=56a7=56 and a19=104a19=104. Use that information to find the constant difference, the first term, and then the 50th50th term of the sequence.

    Answer

     

    To find the constant difference, use d=aj−aij−id=aj−aij−i. The location of the terms is given by the subscript of the two aa terms, i=7i=7 and j=19j=19. So, the constant difference can be calculated as such:

    d=104−5619−7=4812=4d=104−5619−7=4812=4.

    The constant difference of 4 is then used to find a1a1.

    a1=ai−d(i−1)=a7−4(7−1)=56−4×6=32a1=ai−d(i−1)=a7−4(7−1)=56−4×6=32.

    So d=4d=4 and a1=32a1=32.

    With this information, the 50th50th term can be found.

    a50=a1+d×(i−1)=32+4×(50−1)=32+4×49=32+196=228a50=a1+d×(i−1)=32+4×(50−1)=32+4×49=32+196=228.

    The 50th term is \(a_{50}=228\).

    Your Turn \(\PageIndex{3}\)
     
    A sequence is known to be arithmetic. Two of the terms are \(a_{14} = 41\) and \(a_{38} = 161\). Use that information to find the constant difference and the first term. Then determine the \(151^{st}\) term of the sequence.
     
    Video \(\PageIndex{2}\)

    Finding the First Term and Constant Difference for an Arithmetic Sequence

    Finding the Sum of a Finite Arithmetic Sequence

    Sometimes we want to determine the sum of the numbers of a finite arithmetic sequence. The formula for this is fairly straightforward.

    FORMULA \(\PageIndex{3}\)

    The sum of the first nn terms of a finite arithmetic sequence, written snsn, with first and last term a1a1 and anan, respectively, is sn=n(a1+an2)sn=n(a1+an2).

    Example \(\PageIndex{4}\)

    Finding the Sum of a Finite Arithmetic Sequence

    What is the sum of the first 60 terms of an arithmetic sequence with a1=4.5a1=4.5 and d=2.5d=2.5?

    Answer

     

    The formula requires the first and last terms of the sequence. The first term is given, a1=4.5a1=4.5. The 60th60th term is needed. Using the formula a1=ai+d(i−1)a1=ai+d(i−1) provides the value for the 60th60th term.

    a60=4.5+2.5(60−1)=4.5+2.5×59=4.5+147.5=152a60=4.5+2.5(60−1)=4.5+2.5×59=4.5+147.5=152.

    Applying the formula sn=n(a1+an2)sn=n(a1+an2) provides the sum of the first 60 terms.

    s60=60(4.5+1522)=60×156.52=4,695s60=60(4.5+1522)=60×156.52=4,695.

    The sum of the first 60 terms is 4,695.

    Your Turn \(\PageIndex{4}\)
     
    What is the sum of the first 101 terms of an arithmetic sequence with \(a_{1} = 13\) and \(d = 2.25\)?
     
    Video \(\PageIndex{3}\)

    Finding the Sum of a Finite Arithmetic Sequence

    Using Arithmetic Sequences to Solve Real-World Applications

    Applications of arithmetic sequences occur any time some quantity increases by a fixed amount at each step. For instance, suppose someone practices chess each week and increases the amount of time they study each week. The first week the person practices for 3 hours, and vows to practice 30 more minutes each week. Since the amount of time practicing increases by a fixed number each week, this would qualify as an arithmetic sequence.

    Example \(\PageIndex{5}\)

    Applying an Arithmetic Sequence

    Jordan has just watched The Queen’s Gambit and decided to hone their skills in chess. To really improve at the game, Jordan decides to practice for 3 hours the first week, and increase their time spent practicing by 30 minutes each week. How many hours will Jordan practice chess in week 20?

    Answer

     

    Jordan’s practice scheme is an arithmetic sequence, as it increases by a fixed amount each week. The first week there are 3 hours of practice. This means a1=3a1=3. Jordan increases the time spent practicing by 30 minutes, or half an hour, each week. This means d=0.5d=0.5. Using those values, and that we want to know the amount of time Jordan will study in week 20, we determine the time in week 20 using ai=a1+d×(i−1)ai=a1+d×(i−1).

    a 20 = 3 + 0.5 × ( 20 − 1 ) = 3 + 0.5 × 19 = 3 + 9.5 = 12.5 a 20 = 3 + 0.5 × ( 20 − 1 ) = 3 + 0.5 × 19 = 3 + 9.5 = 12.5

    So, Jordan will practice 12.5 hours in week 20.

    Your Turn \(\PageIndex{5}\)
     
    Christina decides to save money for after graduation. Christina starts by setting aside $10. Each week, Christina increases the amount she saves by $5. How much money will Christina save in week 52?
    Example \(\PageIndex{6}\)

    Finding the Sum of a Finite Arithmetic Sequence

    Let’s check back in on Jordan. Recall, Jordan had just watched The Queen’s Gambit and decided to hone their skills, practicing for 3 hours the first week, and increasing the time spent practicing by 30 minutes each week. How many hours total will Jordan have practiced chess after 30 weeks of practice?

    Answer

     

    To calculate the total amount of time that Jordan practiced, we need to use sn=n(a1+an2)sn=n(a1+an2). The formula requires the first and last terms of the sequence. Since Jordan practiced 3 hours in the first week, the first term is a1=3a1=3. Because we want the total practice time after 30 weeks, we need the 30th30th term. Because the constant difference is d=0.5d=0.5, the 30th30th term is a30=3+0.5(30−1)=3+0.5×29=3+14.5=17.5a30=3+0.5(30−1)=3+0.5×29=3+14.5=17.5.

    Applying the formula sn=n(a1+an2)sn=n(a1+an2) provides the sum of the first 30 terms.

    s30=30(3+17.52)=60×20.52=615s30=30(3+17.52)=60×20.52=615.

    This means that Jordan practiced a total of 615 hours after 30 weeks.

    Your Turn \(\PageIndex{6}\)
     
    In a theater, the first row has 24 seats. Each row after that has 2 more seats. How many total seats are there if there are 40 rows of seat in the theater?
     
    Who Knew?

    The Fibonacci Sequence

    Not all sequences are arithmetic. One special sequence is the Fibonacci sequence, which is the sequence that has as its first two terms 1 and 1. Every term thereafter is the sum of the previous two terms. The first nine terms of the Fibonacci sequence are 1, 1, 2, 3, 5, 8, 13, 21, and 34.

    This sequence is found in nature, architecture, and even music! In nature, the Fibonacci sequence describes the spirals of sunflower seeds, certain galaxy spirals, and flower petals. In music, the band Tool used the Fibonacci sequence in the song “Lateralus.” The Fibonacci sequence even relates to architecture, as it is closely related to the golden ratio.

    Video \(\PageIndex{4}\)

    Fibonacci Sequence and “Lateralus”

    Check Your Understanding

    1. Is the following an arithmetic sequence? Explain.
      {3, 6, 9, 15, 25, 39, 90}
    2. What is the 7th term of the following sequence?
      {1, 5, 7, 100, 4, -17, 8, 100, 19, 7.6, 345}
    3. In an arithmetic sequence, the first term is 10 and the constant difference is 4.5. What is the 135th term?
    4. If the eighth term of an arithmetic sequence is 35 and the 40th term is 131, what is the constant difference and the first term of the sequence?
    5. What is the sum of the first 100 terms of the arithmetic sequence with first term 4 and constant difference 7?
    6. A new marketing firm began with 30 people in its survey group. The firm adds 4 people per day. How many people will be in their survey group after 100 days?

    Section 3.10 Exercises

    For the following exercises, determine if the sequence is an arithmetic sequence.

    1. {3,7,11,15,25,100,...}
    2. {27,24,21,18,15,12,9,...}
    3. {6, - 1, - 8, - 15, - 23, - 31, - 39,...}
    4. { - 5,4,13,22,31,40,49,58,67,...}
    5. {14,19,24,29,34,50,60}
    6. {3.9,2.3,0.7, - 0.9, - 2.5, - 4.1, - 5.7,...}
    7. {4, - 8,12, - 16,20, - 24,28, - 32,...}
    8. {1,2,3,5,8,13,21,34,55,...}

    For the following exercises, the sequences given are arithmetic sequences. Determine the constant difference for each sequence. Verify that each term is the previous term plus the constant difference.

    1. {18,68,118,168,218,268,...}
    2. {13,35,57,79,101,123,145,167,...}
    3. {14,11,8,5,2, - 1, - 4,...}
    4. {4.5,1.9, - 0.7, - 3.3, - 5.9,...}
    5. { - 27, - 13,1,15,29,43,57,71,...}
    6. {3.8,10.6,17.4,24.2,31,37.8,44.6,...}

    For the following exercises, the first term and the constant difference of an arithmetic sequence is given. Using that information, determine the indicated term of the sequence.

    1. \(a_1  = 12\), \(d= 11\), find \(a_{20}\).
    2. \(b_1 = 5\), \(d= 8\), find \(b_{38}\).
    3. \(c_1 = 48\), \(d= - 7\), find \(c_{50}\).
    4. \(a_1  = 110\), \(d= - 16\), find \(a_{27}\).
    5. \(t_1 = 15.3\), \(d= 4.2\), find \(t_{17}\).
    6. \(b_1 = 23.8\), \(d= 11.7\), find \(b_{120}\).
    7. \(b_1 = 27.45\), \(d= - 3.67\), find \(b_{40}\).
    8. \(a_1  = 67.4\), \(d= - 12.3\), find \(a_{200}\).

    For the following exercises, two terms of an arithmetic sequence are given. Using that information, identify the first term and the constant difference.

    1. \(a_5 = 27\), \(a_{15} = 77\)
    2. \(b_{10} = 47\), \(b_{25} = 137\)
    3. \(a_9 = 38\), \(a_{45} = 189.2\)
    4. \(a_6 = 43\), \(a_{41} = - 377\)
    5. \(a_4 = - 12.3\), \(a_{54} = - 106.5\)
    6. \(a_{12} = 45.9\), \(a_{60} = - 563.7\)

    For the following exercises, the first term and the constant difference is given for an arithmetic sequence. Use that information to find the sum of the first \(n\) terms of the sequence, \(s_n\).

    1. \(a_1  = 15\), \(d= 7\), calculate \(s_{10}\).
    2. \(a_1  = 2\), \(d= 13\), calculate \(s_{20}\).
    3. \(a_1  = 105\), \(d= 0.3\), calculate \(s_{15}\).
    4. \(a_1  = 56.2\), \(d= 1.1\), calculate \(s_{35}\).
    5. \(a_1  = 450\), \(d= - 20\), calculate \(s_{20}\).
    6. \(a_1 = 1400\), \(d= - 35\), calculate \(s_{40}\) .

    For the following exercises, apply your knowledge of arithmetic sequences to these real-world scenarios.

    1. A collection is taken up to support a family in need. The initial amount in the collection is $135. Everyone places $20 in the collection. When the 35th person puts their $20 in the collection, how much is present in the collection?
    2. There are 50 songs on a playlist. Every minute, 3 more songs are added to the playlist. How many songs are on the playlist after 40 minutes have passed?
    3. One genre on Netflix has 1,000 shows. Every week, 20 shows are added to that genre. After 15 weeks, how many shows are in that genre?
    4. A new local band has 10 people come to their first show. News of the band spreads afterwards. Each week, 4 more people attend their show than the previous week. After 50 weeks, how many people are at their show?
    5. The Jester Comic book store is going out of business and is taking in no new inventory. Its inventory is currently 13,563 titles. Each day after, they sell or give away 250 titles. After 15 days, how many titles are left?
    6. Jasmyn has decided to train for a marathon. In week one, Jasmyn runs 5 miles. Each week, Jasmyn increased the running distance by 2 miles. How many miles will Jasmyn run in week 13 of the training schedule?
    7. A 42-gallon bathtub sits with 14 gallons in it. The faucet is turned on and is now being filled at the rate of 2.2 gallons per minute, but is draining slowly, at 1.8 gallons per minute. After 20 minutes, how many gallons are in the tub?
    8. A trained diver is 250 feet deep. The diver is nearly out of air and needs to surface. However, the diver can only comfortably ascend 30 feet per minute. How deep is the diver after ascending for 5 minutes?
    9. Jaclyn, an investor, begins a start-up to revitalize homes in South Bend, Indiana. She begins with $10,000, making her investor 1. Each investor that joins will invest $500 more than the previous investor. How much does the 50th investor invest in the project? With that 50th investor, what is the total amount invested in the project?
    10. Jasmyn has decided to train for a marathon. In week one, Jasmyn runs 5 miles. Each week, Jasmyn increased the running distance by 2 miles. After training for 14 weeks, how many total miles will Jasmyn have run?
    11. The base of a pyramidal structure has 144 blocks. Each level above has 5 fewer blocks than the previous level. How many total blocks are there if the pyramidal structure has 25 levels?
    12. As part of a deal, a friend tells you they will give you $10 on day 1, $20 on day 2, $30 on day 3, for all 30 days of a month. At the end of that month, what is the total amount your friend has given you?

     

    This page titled 4.14: Arithmetic Sequences is shared under a CC BY 4.0 license and was authored, remixed, and/or curated by OpenStax via source content that was edited to the style and standards of the LibreTexts platform.