2.3E: Exercises - Using Transformations to Graph Functions
- Page ID
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Exercise \(\PageIndex{3}\)
Match the graph to the function definition.
- \(f(x) = \sqrt{x + 4}\)
- \(f(x) = |x − 2| − 2\)
- \(f(x) = \sqrt{x + 1} -1\)
- \(f(x) = |x − 2| + 1\)
- \(f(x) = \sqrt{x + 4} + 1\)
- \(f(x) = |x + 2| − 2\)
- Answer
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1. e
3. d
5. f
Exercise \(\PageIndex{4}\)
Graph the given function. Identify the basic function and translations used to sketch the graph. Then state the domain and range.
- \(f(x) = x + 3\)
- \(f(x) = x − 2\)
- \(g(x) = x^{2} + 1\)
- \(g(x) = x^{2} − 4\)
- \(g(x) = (x − 5)^{2}\)
- \(g(x) = (x + 1)^{2}\)
- \(g(x) = (x − 5)^{2} + 2\)
- \(g(x) = (x + 2)^{2} − 5\)
- \(h(x) = |x + 4|\)
- \(h(x) = |x − 4|\)
- \(h(x) = |x − 1| − 3\)
- \(h(x) = |x + 2| − 5\)
- \(g(x) = \sqrt{x} − 5\)
- \(g(x) = \sqrt{x − 5}\)
- \(g(x) = \sqrt{x − 2} + 1\)
- \(g(x) = \sqrt{x + 2} + 3\)
- \(h(x) = (x − 2)^{3}\)
- \(h(x) = x^{3} + 4\)
- \(h(x) = (x − 1)^{3} − 4\)
- \(h(x) = (x + 1)^{3} + 3\)
- \(f(x) = \frac{1}{x−2}\)
- \(f(x) = \frac{1}{x+3}\)
- \(f(x) = \frac{1}{x} + 5\)
- \(f(x) = \frac{1}{x} − 3\)
- \(f(x) = \frac{1}{x+1} − 2\)
- \(f(x) = \frac{1}{x−3} + 3\)
- \(g(x) = −4\)
- \(g(x) = 2\)
- \(f ( x ) = \sqrt [ 3 ] { x - 2 } + 6\)
- \(f ( x ) = \sqrt [ 3 ] { x + 8 } - 4\)
- Answer
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1. \(y = x\); Shift up \(3\) units; domain: \(\mathbb{R}\); range: \(\mathbb{R}\)
3. \(y = x^{2}\); Shift up \(1\) unit; domain: \(ℝ\); range: \([1, ∞)\)
5. \(y = x^{2}\); Shift right \(5\) units; domain: \(ℝ\); range: \([0, ∞)\)
7. \(y = x^{2}\); Shift right \(5\) units and up \(2\) units; domain: \(ℝ\); range: \([2, ∞)\)
9. \(y = |x|\); Shift left \(4\) units; domain: \(ℝ\); range: \([0, ∞)\)
11. \(y = |x|\); Shift right \(1\) unit and down \(3\) units; domain: \(ℝ\); range: \([−3, ∞)\)
13. \(y = \sqrt{x}\); Shift down \(5\) units; domain: \([0, ∞)\); range: \([−5, ∞)\)
15. \(y = \sqrt{x}\); Shift right \(2\) units and up \(1\) unit; domain: \([2, ∞)\); range: \([1, ∞)\)
17. \(y = x^{3}\) ; Shift right \(2\) units; domain: \(ℝ\); range: \(ℝ\)
19. \(y = x^{3}\); Shift right \(1\) unit and down \(4\) units; domain: \(ℝ\); range: \(ℝ\)
21. \(y = \frac{1}{x}\); Shift right \(2\) units; domain: \((−∞, 2) ∪ (2, ∞)\); range: \((−∞, 0) ∪ (0, ∞)\)
23. \(y = \frac{1}{x}\); Shift up \(5\) units; domain: \((−∞, 0) ∪ (0, ∞)\); range: \((−∞, 1) ∪ (1, ∞)\)
25. \(y = \frac{1}{x}\); Shift left \(1\) unit and down \(2\) units; domain: \((−∞, −1) ∪ (−1, ∞)\); range: \((−∞, −2) ∪ (−2, ∞)\)
27. Basic graph \(y = −4\); domain: \(ℝ\); range: \(\{−4\}\)
29. \(y = \sqrt [ 3 ] { x }\); Shift up \(6\) units and right \(2\) units; domain: \(ℝ\); range: \(ℝ\)
Exercise \(\PageIndex{5}\)
Graph the piecewise functions.
- \(h ( x ) = \left\{ \begin{array} { l l } { x ^ { 2 } + 2 } & { \text { if } x < 0 } \\ { x + 2 } & { \text { if } x \geq 0 } \end{array} \right.\)
- \(h ( x ) = \left\{ \begin{array} { l l } { x ^ { 2 } - 3 \text { if } x < 0 } \\ { \sqrt { x } - 3 \text { if } x \geq 0 } \end{array} \right.\)
- \(h ( x ) = \left\{ \begin{array} { l l } { x ^ { 3 } - 1 } & { \text { if } x < 0 } \\ { | x - 3 | - 4 } & { \text { if } x \geq 0 } \end{array} \right.\)
- \(h ( x ) = \left\{ \begin{array} { c c } { x ^ { 3 } } & { \text { if } x < 0 } \\ { ( x - 1 ) ^ { 2 } - 1 } & { \text { if } x \geq 0 } \end{array} \right.\)
- \(h ( x ) = \left\{ \begin{array} { l l } { x ^ { 2 } - 1 } & { \text { if } x < 0 } \\ { 2 } & { \text { if } x \geq 0 } \end{array} \right.\)
- \(h ( x ) = \left\{ \begin{array} { l l } { x + 2 } & { \text { if } x < 0 } \\ { ( x - 2 ) ^ { 2 } } & { \text { if } x \geq 0 } \end{array} \right.\)
- \(h ( x ) = \left\{ \begin{array} { l l } { ( x + 10 ) ^ { 2 } - 4 } & { \text { if } x < - 8 } \\ { x + 4 } & { \text { if } - 8 \leq x < - 4 } \\ { \sqrt { x + 4 } } & { \text { if } x \geq - 4 } \end{array} \right.\)
- \(f ( x ) = \left\{ \begin{array} { l l } { x + 10 } & { \text { if } x \leq - 10 } \\ { | x - 5 | - 15 } & { \text { if } - 10 < x \leq 20 } \\ { 10 } & { \text { if } x > 20 } \end{array} \right.\)
- Answer
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7.
Exercise \(\PageIndex{6}\)
Write an equation that represents the function whose graph is given.
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- Answer
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1. \(f ( x ) = \sqrt { x - 5 }\)
3. \(f ( x ) = ( x - 15 ) ^ { 2 } - 10\)
5. \(f ( x ) = \frac { 1 } { x + 8 } + 4\)
7. \(f ( x ) = \sqrt { x + 16 } - 4\)
Exercise \(\PageIndex{6}\)
Match the graph to the given function defintion.
- \(f ( x ) = - 3 | x |\)
- \(f ( x ) = - ( x + 3 ) ^ { 2 } - 1\)
- \(f ( x ) = - | x + 1 | + 2\)
- \(f ( x ) = - x ^ { 2 } + 1\)
- \(f ( x ) = - \frac { 1 } { 3 } | x |\)
- \(f ( x ) = - ( x - 2 ) ^ { 2 } + 2\)
- Answer
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1. b
3. d
5. f
Exercise \(\PageIndex{7}\)
Use the transformations to graph the following functions.
- \(f ( x ) = - x + 5\)
- \(f ( x ) = - | x | - 3\)
- \(g ( x ) = - | x - 1 |\)
- \(f ( x ) = - ( x + 2 ) ^ { 2 }\)
- \(h ( x ) = \sqrt { - x } + 2\)
- \(g ( x ) = - \sqrt { x } + 2\)
- \(g ( x ) = - ( x + 2 ) ^ { 3 }\)
- \(h ( x ) = - \sqrt { x - 2 } + 1\)
- \(g ( x ) = - x ^ { 3 } + 4\)
- \(f ( x ) = - x ^ { 2 } + 6\)
- \(f ( x ) = - 3 | x |\)
- \(g ( x ) = - 2 x ^ { 2 }\)
- \(h ( x ) = \frac { 1 } { 2 } ( x - 1 ) ^ { 2 }\)
- \(h ( x ) = \frac { 1 } { 3 } ( x + 2 ) ^ { 2 }\)
- \(g ( x ) = - \frac { 1 } { 2 } \sqrt { x - 3 }\)
- \(f ( x ) = - 5 \sqrt { x + 2 }\)
- \(f ( x ) = 4 \sqrt { x - 1 } + 2\)
- \(h ( x ) = - 2 x + 1\)
- \(g ( x ) = - \frac { 1 } { 4 } ( x + 3 ) ^ { 3 } - 1\)
- \(f ( x ) = - 5 ( x - 3 ) ^ { 2 } + 3\)
- \(h ( x ) = - 3 | x + 4 | - 2\)
- \(f ( x ) = - \frac { 1 } { x }\)
- \(f ( x ) = - \frac { 1 } { x + 2 }\)
- \(f ( x ) = - \frac { 1 } { x + 1 } + 2\)
- Answer
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Exercise \(\PageIndex{8}\)
- Use different colors to graph the family of graphs defined by \(y=kx^{2}\), where \(k \in \left\{ 1 , \frac { 1 } { 2 } , \frac { 1 } { 3 } , \frac { 1 } { 4 } \right\}\). What happens to the graph when the denominator of \(k\) is very large? Share your findings on the discussion board.
- Graph \(f ( x ) = \sqrt { x }\) and \(g ( x ) = - \sqrt { x }\) on the same set of coordinate axes. What does the general shape look like? Try to find a single equation that describes the shape. Share your findings.
- Explore what happens to the graph of a function when the domain values are multiplied by a factor \(a\) before the function is applied, \(f(ax)\). Develop some rules for this situation and share them on the discussion board.
- Answer
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