3.2E: Exercises
- Page ID
- 120141
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Exercises
In Exercises 1 - 6, use polynomial long division to perform the indicated division. Write the polynomial in the form \(p(x) = d(x)q(x) + r(x)\).
- \(\left(4 x^{2}+3 x-1\right) \div(x-3)\)
- \(\left(2 x^{3}-x+1\right) \div\left(x^{2}+x+1\right)\)
- \(\left(5 x^{4}-3 x^{3}+2 x^{2}-1\right) \div\left(x^{2}+4\right)\)
- \(\left(-x^{5}+7 x^{3}-x\right) \div\left(x^{3}-x^{2}+1\right)\)
- \(\left(9 x^{3}+5\right) \div(2 x-3)\)
- \(\left(4 x^{2}-x-23\right) \div\left(x^{2}-1\right)\)
In Exercises 7 - 20 use synthetic division to perform the indicated division. Write the polynomial in the form \(p(x) = d(x)q(x)+r(x)\).
- \(\left(3 x^{2}-2 x+1\right) \div(x-1)\)
- \(\left(x^{2}-5\right) \div(x-5)\)
- \(\left(3-4 x-2 x^{2}\right) \div(x+1)\)
- \(\left(4 x^{2}-5 x+3\right) \div(x+3)\)
- \(\left(x^{3}+8\right) \div(x+2)\)
- \(\left(4 x^{3}+2 x-3\right) \div(x-3)\)
- \(\left(18 x^{2}-15 x-25\right) \div\left(x-\frac{5}{3}\right)\)
- \(\left(4 x^{2}-1\right) \div\left(x-\frac{1}{2}\right)\)
- \(\left(2 x^{3}+x^{2}+2 x+1\right) \div\left(x+\frac{1}{2}\right)\)
- \(\left(3 x^{3}-x+4\right) \div\left(x-\frac{2}{3}\right)\)
- \(\left(2 x^{3}-3 x+1\right) \div\left(x-\frac{1}{2}\right)\)
- \(\left(4 x^{4}-12 x^{3}+13 x^{2}-12 x+9\right) \div\left(x-\frac{3}{2}\right)\)
- \(\left(x^{4}-6 x^{2}+9\right) \div(x-\sqrt{3})\)
- \(\left(x^{6}-6 x^{4}+12 x^{2}-8\right) \div(x+\sqrt{2})\)
In Exercises 21 - 30, determine \(p(c)\) using the Remainder Theorem for the given polynomial functions and value of \(c\). If \(p(c)=0\), factor \(p(x)=(x-c) q(x)\).
- \(p(x)=2 x^{2}-x+1, c=4\)
- \(p(x)=4 x^{2}-33 x-180, c=12\)
- \(p(x)=2 x^{3}-x+6, c=-3\)
- \(p(x)=x^{3}+2 x^{2}+3 x+4, c=-1\)
- \(p(x)=3 x^{3}-6 x^{2}+4 x-8, c=2\)
- \(p(x)=8 x^{3}+12 x^{2}+6 x+1, c=-\frac{1}{2}\)
- \(p(x)=x^{4}-2 x^{2}+4, c=\frac{3}{2}\)
- \(p(x)=6 x^{4}-x^{2}+2, c=-\frac{2}{3}\)
- \(p(x)=x^{4}+x^{3}-6 x^{2}-7 x-7, c=-\sqrt{7}\)
- \(p(x)=x^{2}-4 x+1, c=2-\sqrt{3}\)
In Exercises 31 - 40, you are given a polynomial and one of its zeros. Use the techniques in this section to find the rest of the real zeros and factor the polynomial.
- \(x^{3}-6 x^{2}+11 x-6, \quad c=1\)
- \(x^{3}-24 x^{2}+192 x-512, \quad c=8\)
- \(3 x^{3}+4 x^{2}-x-2, \quad c=\frac{2}{3}\)
- \(2 x^{3}-3 x^{2}-11 x+6, \quad c=\frac{1}{2}\)
- \(x^{3}+2 x^{2}-3 x-6, \quad c=-2\)
- \(2 x^{3}-x^{2}-10 x+5, \quad c=\frac{1}{2}\)
- \(4 x^{4}-28 x^{3}+61 x^{2}-42 x+9, c=\frac{1}{2} \text { is a zero of multiplicity } 2\)
- \(x^{5}+2 x^{4}-12 x^{3}-38 x^{2}-37 x-12, c=-1 \text { is a zero of multiplicity } 3\)
- \(125 x^{5}-275 x^{4}-2265 x^{3}-3213 x^{2}-1728 x-324, c=-\frac{3}{5} \text { is a zero of multiplicity } 3\)
- \(x^{2}-2 x-2, \quad c=1-\sqrt{3}\)
In Exercises 41 - 45, create a polynomial \(p\) which has the desired characteristics. You may leave the polynomial in factored form.
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- The zeros of \(p\) are \(c=\pm 2\) and \(c=\pm 1\)
- The leading term of \(p(x)\) is \(117 x^{4}\).
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- The zeros of \(p\) are \(c = 1\) and \(c = 3\)
- \(c = 3\) is a zero of multiplicity 2.
- The leading term of \(p(x)\) is \(-5 x^{3}\)
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- The solutions to \(p(x) = 0\) are \(x=\pm 3\) and \(x = 6\)
- The leading term of \(p(x)\) is \(7 x^{4}\)
- The point (−3, 0) is a local minimum on the graph of \(y = p(x)\).
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- The solutions to \(p(x) = 0\) are \(x=\pm 3\), \(x = −2\), and \(x = 4\).
- The leading term of \(p(x)\) is \(-x^{5}\).
- The point (−2, 0) is a local maximum on the graph of \(y = p(x)\).
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- \(p\) is degree 4.
- as \(x \rightarrow \infty\), \(p(x) \rightarrow-\infty\)
- \(p\) has exactly three \(x\)-intercepts: (−6, 0), (1, 0) and (117, 0)
- The graph of \(y = p(x)\) crosses through the x-axis at (1, 0).
- Find a quadratic polynomial with integer coefficients which has \(x=\frac{3}{5} \pm \frac{\sqrt{29}}{5}\) as its real zeros.
Answers
- \(4 x^{2}+3 x-1=(x-3)(4 x+15)+44\)
- \(2 x^{3}-x+1=\left(x^{2}+x+1\right)(2 x-2)+(-x+3)\)
- \(5 x^{4}-3 x^{3}+2 x^{2}-1=\left(x^{2}+4\right)\left(5 x^{2}-3 x-18\right)+(12 x+71)\)
- \(-x^{5}+7 x^{3}-x=\left(x^{3}-x^{2}+1\right)\left(-x^{2}-x+6\right)+\left(7 x^{2}-6\right)\)
- \(9 x^{3}+5=(2 x-3)\left(\frac{9}{2} x^{2}+\frac{27}{4} x+\frac{81}{8}\right)+\frac{283}{8}\)
- \(4 x^{2}-x-23=\left(x^{2}-1\right)(4)+(-x-19)\)
- \(\left(3 x^{2}-2 x+1\right)=(x-1)(3 x+1)+2\)
- \(\left(x^{2}-5\right)=(x-5)(x+5)+20\)
- \(\left(3-4 x-2 x^{2}\right)=(x+1)(-2 x-2)+5\)
- \(\left(4 x^{2}-5 x+3\right)=(x+3)(4 x-17)+54\)
- \(\left(x^{3}+8\right)=(x+2)\left(x^{2}-2 x+4\right)+0\)
- \(\left(4 x^{3}+2 x-3\right)=(x-3)\left(4 x^{2}+12 x+38\right)+111\)
- \(\left(18 x^{2}-15 x-25\right)=\left(x-\frac{5}{3}\right)(18 x+15)+0\)
- \(\left(4 x^{2}-1\right)=\left(x-\frac{1}{2}\right)(4 x+2)+0\)
- \(\left(2 x^{3}+x^{2}+2 x+1\right)=\left(x+\frac{1}{2}\right)\left(2 x^{2}+2\right)+0\)
- \(\left(3 x^{3}-x+4\right)=\left(x-\frac{2}{3}\right)\left(3 x^{2}+2 x+\frac{1}{3}\right)+\frac{38}{9}\)
- \(\left(2 x^{3}-3 x+1\right)=\left(x-\frac{1}{2}\right)\left(2 x^{2}+x-\frac{5}{2}\right)-\frac{1}{4}\)
- \(\left(4 x^{4}-12 x^{3}+13 x^{2}-12 x+9\right)=\left(x-\frac{3}{2}\right)\left(4 x^{3}-6 x^{2}+4 x-6\right)+0\)
- \(\left(x^{4}-6 x^{2}+9\right)=(x-\sqrt{3})\left(x^{3}+\sqrt{3} x^{2}-3 x-3 \sqrt{3}\right)+0\)
- \(\left(x^{6}-6 x^{4}+12 x^{2}-8\right)=(x+\sqrt{2})\left(x^{5}-\sqrt{2} x^{4}-4 x^{3}+4 \sqrt{2} x^{2}+4 x-4 \sqrt{2}\right)+0\)
- \(p(4)=29\)
- \(p(12)=0, p(x)=(x-12)(4 x+15)\)
- \(p(-3)=-45\)
- \(p(-1)=2\)
- \(p(2)=0, p(x)=(x-2)\left(3 x^{2}+4\right)\)
- \(p\left(-\frac{1}{2}\right)=0, p(x)=\left(x+\frac{1}{2}\right)\left(8 x^{2}+8 x+2\right)\)
- \(p\left(\frac{3}{2}\right)=\frac{73}{16}\)
- \(p\left(-\frac{2}{3}\right)=\frac{74}{27}\)
- \(p(-\sqrt{7})=0, p(x)=(x+\sqrt{7})\left(x^{3}+(1-\sqrt{7}) x^{2}+(1-\sqrt{7}) x-\sqrt{7}\right)\)
- \(p(2-\sqrt{3})=0, p(x)=(x-(2-\sqrt{3}))(x-(2+\sqrt{3}))\)
- \(x^{3}-6 x^{2}+11 x-6=(x-1)(x-2)(x-3)\)
- \(x^{3}-24 x^{2}+192 x-512=(x-8)^{3}\)
- \(3 x^{3}+4 x^{2}-x-2=3\left(x-\frac{2}{3}\right)(x+1)^{2}\)
- \(2 x^{3}-3 x^{2}-11 x+6=2\left(x-\frac{1}{2}\right)(x+2)(x-3)\)
- \(x^{3}+2 x^{2}-3 x-6=(x+2)(x+\sqrt{3})(x-\sqrt{3})\)
- \(2 x^{3}-x^{2}-10 x+5=2\left(x-\frac{1}{2}\right)(x+\sqrt{5})(x-\sqrt{5})\)
- \(4 x^{4}-28 x^{3}+61 x^{2}-42 x+9=4\left(x-\frac{1}{2}\right)^{2}(x-3)^{2}\)
- \(x^{5}+2 x^{4}-12 x^{3}-38 x^{2}-37 x-12=(x+1)^{3}(x+3)(x-4)\)
- \(125 x^{5}-275 x^{4}-2265 x^{3}-3213 x^{2}-1728 x-324=125\left(x+\frac{3}{5}\right)^{3}(x+2)(x-6)\)
- \(x^{2}-2 x-2=(x-(1-\sqrt{3}))(x-(1+\sqrt{3}))\)
- \(p(x)=117(x+2)(x-2)(x+1)(x-1)\)
- \(p(x)=-5(x-1)(x-3)^{2}\)
- \(p(x)=7(x+3)^{2}(x-3)(x-6)\)
- \(p(x)=-(x+2)^{2}(x-3)(x+3)(x-4)\)
- \(p(x)=a(x+6)^{2}(x-1)(x-117) \text { or } p(x)=a(x+6)(x-1)(x-117)^{2} \text { where } a \text { can be any negative real number}\)
- \(p(x)=5 x^{2}-6 x-4\)