10.4E: Exercises
- Page ID
- 120525
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Exercises
In Exercises 1 - 6, use the Even / Odd Identities to verify the identity. Assume all quantities are defined.
- \(\sin(3\pi - 2\theta) = -\sin(2\theta - 3\pi)\)
- \(\cos \left( -\dfrac{\pi}{4} - 5t \right) = \cos \left( 5t + \dfrac{\pi}{4} \right)\)
- \(\tan(-t^{2} + 1) = -\tan(t^{2} - 1)\)
- \(\csc(-\theta - 5) = -\csc(\theta + 5)\)
- \(\sec(-6t) = \sec(6t)\)
- \(\cot(9 - 7\theta) = -\cot(7\theta - 9)\)
In Exercises 7 - 21, use the Sum and Difference Identities to find the exact value. You may have need of the Quotient, Reciprocal or Even / Odd Identities as well.
- \(\cos(75^{\circ})\)
- \(\sec(165^{\circ})\)
- \(\sin(105^{\circ})\)
- \(\csc(195^{\circ})\)
- \(\cot(255^{\circ})\)
- \(\tan(375^{\circ})\)
- \(\cos\left(\dfrac{13\pi}{12}\right)\)
- \(\sin\left(\dfrac{11\pi}{12}\right)\)
- \(\tan\left(\dfrac{13\pi}{12}\right)\)
- [cos7pi12] \(\cos \left( \dfrac{7\pi}{12} \right)\)
- \(\tan \left( \dfrac{17\pi}{12} \right)\)
- \(\sin \left( \dfrac{\pi}{12} \right)\)
- \(\cot \left( \dfrac{11\pi}{12} \right)\)
- \(\csc \left( \dfrac{5\pi}{12} \right)\)
- \(\sec \left( -\dfrac{\pi}{12} \right)\)
- If \(\alpha\) is a Quadrant IV angle with \(\cos(\alpha) = \dfrac{\sqrt{5}}{5}\), and \(\sin(\beta) = \dfrac{\sqrt{10}}{10}\), where \(\dfrac{\pi}{2} < \beta < \pi\), find
- \(\cos(\alpha + \beta)\)
- \(\sin(\alpha + \beta)\)
- \(\tan(\alpha + \beta)\)
- \(\cos(\alpha - \beta)\)
- \(\sin(\alpha - \beta)\)
- \(\tan(\alpha - \beta)\)
- If \(\csc(\alpha) = 3\), where \(0 < \alpha < \dfrac{\pi}{2}\), and \(\beta\) is a Quadrant II angle with \(\tan(\beta) = -7\), find
- \(\cos(\alpha + \beta)\)
- \(\sin(\alpha + \beta)\)
- \(\tan(\alpha + \beta)\)
- \(\cos(\alpha - \beta)\)
- \(\sin(\alpha - \beta)\)
- \(\tan(\alpha - \beta)\)
- If \(\sin(\alpha) = \dfrac{3}{5}\), where \(0 < \alpha < \dfrac{\pi}{2}\), and \(\cos(\beta) = \dfrac{12}{13}\) where \(\dfrac{3\pi}{2} < \beta < 2\pi\), find
- \(\sin(\alpha + \beta)\)
- \(\cos(\alpha - \beta)\)
- \(\tan(\alpha - \beta)\)
- If \(\sec(\alpha) = -\dfrac{5}{3}\), where \(\dfrac{\pi}{2} < \alpha < \pi\), and \(\tan(\beta) = \dfrac{24}{7}\), where \(\pi < \beta < \dfrac{3\pi}{2}\), find
- \(\csc(\alpha - \beta)\)
- \(\sec(\alpha + \beta)\)
- \(\cot(\alpha + \beta)\)
In Exercises 26 - 38, verify the identity.
- \(\cos(\theta - \pi) = -\cos(\theta)\)
- \(\sin(\pi - \theta) = \sin(\theta)\)
- \(\tan\left(\theta + \dfrac{\pi}{2} \right) = -\cot(\theta)\)
- \(\sin(\alpha + \beta) + \sin(\alpha - \beta) = 2\sin(\alpha)\cos(\beta)\)
- \(\sin(\alpha + \beta) - \sin(\alpha - \beta) = 2\cos(\alpha) \sin(\beta)\)
- \(\cos(\alpha + \beta) + \cos(\alpha - \beta) = 2\cos(\alpha) \cos(\beta)\)
- \(\cos(\alpha + \beta) - \cos(\alpha - \beta) = -2\sin(\alpha) \sin(\beta)\)
- \(\dfrac{\sin(\alpha+\beta)}{\sin(\alpha-\beta)} = \dfrac{1+\cot(\alpha) \tan(\beta)}{1 - \cot(\alpha) \tan(\beta)}\)
- \(\dfrac{\cos(\alpha + \beta)}{\cos(\alpha - \beta)} = \dfrac{1 - \tan(\alpha)\tan(\beta)}{1 + \tan(\alpha)\tan(\beta)}\)
- \(\dfrac{\tan(\alpha + \beta)}{\tan(\alpha - \beta)} = \dfrac{\sin(\alpha)\cos(\alpha) + \sin(\beta)\cos(\beta)}{\sin(\alpha)\cos(\alpha) - \sin(\beta)\cos(\beta)}\)
- \(\dfrac{\sin(t + h) - \sin(t)}{h} = \cos(t) \left(\dfrac{\sin(h)}{h} \right) + \sin(t) \left( \dfrac{\cos(h) - 1}{h} \right)\)
- \(\dfrac{\cos(t + h) - \cos(t)}{h} = \cos(t) \left( \dfrac{\cos(h) - 1}{h} \right) - \sin(t) \left(\dfrac{\sin(h)}{h} \right)\)
- \(\dfrac{\tan(t + h) - \tan(t)}{h} = \left( \dfrac{\tan(h)}{h} \right) \left(\dfrac{\sec^{2}(t)}{1 - \tan(t)\tan(h)} \right)\)
In Exercises 39 - 48, use the Half Angle Formulas to find the exact value. You may have need of the Quotient, Reciprocal or Even / Odd Identities as well.
- \(\cos(75^{\circ})\) (compare with Exercise 7)
- \(\sin(105^{\circ})\) (compare with Exercise 9)
- \(\cos(67.5^{\circ})\)
- \(\sin(157.5^{\circ})\)
- \(\tan(112.5^{\circ})\)
- \(\cos\left( \dfrac{7\pi}{12} \right)\) (compare with Exercise 16)
- \(\sin\left( \dfrac{\pi}{12} \right)\) (compare with Exercise 18)
- \(\cos \left( \dfrac{\pi}{8} \right)\)
- \(\sin \left( \dfrac{5\pi}{8} \right)\)
- \(\tan \left( \dfrac{7\pi}{8} \right)\)
In Exercises 49 - 58, use the given information about \(\theta\) to find the exact values of
- \(\sin(2\theta)\)
- \(\sin\left(\dfrac{\theta}{2}\right)\)
- \(\cos(2\theta)\)
- \(\cos\left(\dfrac{\theta}{2}\right)\)
- \(\tan(2\theta)\)
- \(\tan\left(\dfrac{\theta}{2}\right)\)
- \(\sin(\theta) = -\dfrac{7}{25}\) where \(\dfrac{3\pi}{2} < \theta < 2\pi\)
- \(\cos(\theta) = \dfrac{28}{53}\) where \(0 < \theta < \dfrac{\pi}{2}\)
- \(\tan(\theta) = \dfrac{12}{5}\) where \(\pi < \theta < \dfrac{3\pi}{2}\)
- \(\csc(\theta) = 4\) where \(\dfrac{\pi}{2} < \theta < \pi\)
- \(\cos(\theta) = \dfrac{3}{5}\) where \(0 < \theta < \dfrac{\pi}{2}\)
- \(\sin(\theta) = -\dfrac{4}{5}\) where \(\pi < \theta < \dfrac{3\pi}{2}\)
- \(\cos(\theta) = \dfrac{12}{13}\) where \(\dfrac{3\pi}{2} < \theta < 2\pi\)
- \(\sin(\theta) = \dfrac{5}{13}\) where \(\dfrac{\pi}{2} < \theta < \pi\)
- \(\sec(\theta) = \sqrt{5}\) where \(\dfrac{3\pi}{2} < \theta < 2\pi\)
- \(\tan(\theta) = -2\) where \(\dfrac{\pi}{2} < \theta < \pi\)
In Exercises 59 - 73, verify the identity. Assume all quantities are defined.
- \((\cos(\theta) + \sin(\theta))^2 = 1 + \sin(2\theta)\)
- \((\cos(\theta) - \sin(\theta))^2 = 1 - \sin(2\theta)\)
- \(\tan(2\theta) = \dfrac{1}{1-\tan(\theta)} - \dfrac{1}{1+\tan(\theta)}\)
- \(\csc(2\theta) = \dfrac{\cot(\theta) + \tan(\theta)}{2}\)
- \(8 \sin^{4}(\theta) = \cos(4\theta) - 4\cos(2\theta)+3\)
- \(8 \cos^{4}(\theta) = \cos(4\theta) + 4\cos(2\theta)+3\)
- [sine3theta] \(\sin(3\theta) = 3\sin(\theta) - 4\sin^{3}(\theta)\)
- \(\sin(4\theta) = 4\sin(\theta)\cos^{3}(\theta) - 4\sin^{3}(\theta)\cos(\theta)\)
- \(32\sin^{2}(\theta) \cos^{4}(\theta) = 2 + \cos(2\theta) - 2\cos(4\theta) - \cos(6\theta)\)
- \(32\sin^{4}(\theta) \cos^{2}(\theta) = 2 - \cos(2\theta) - 2\cos(4\theta) + \cos(6\theta)\)
- \(\cos(4\theta) = 8\cos^{4}(\theta) - 8\cos^{2}(\theta) + 1\)
- \(\cos(8\theta) = 128\cos^{8}(\theta)-256\cos^{6}(\theta)+160\cos^{4}(\theta)-32\cos^{2}(\theta)+1\) (HINT: Use the result to 69.)
- \(\sec(2\theta) = \dfrac{\cos(\theta)}{\cos(\theta) + \sin(\theta)} + \dfrac{\sin(\theta)}{\cos(\theta)-\sin(\theta)}\)
- \(\dfrac{1}{\cos(\theta) - \sin(\theta)} + \dfrac{1}{\cos(\theta) + \sin(\theta)} = \dfrac{2\cos(\theta)}{\cos(2\theta)}\)
- \(\dfrac{1}{\cos(\theta) - \sin(\theta)} - \dfrac{1}{\cos(\theta) + \sin(\theta)} = \dfrac{2\sin(\theta)}{\cos(2\theta)}\)
In Exercises 74 - 79, write the given product as a sum. You may need to use an Even/Odd Identity.
- \(\cos(3\theta)\cos(5\theta)\)
- \(\sin(2\theta)\sin(7\theta)\)
- \(\sin(9\theta)\cos(\theta)\)
- \(\cos(2\theta) \cos(6\theta)\)
- \(\sin(3\theta) \sin(2\theta)\)
- \(\cos(\theta) \sin(3\theta)\)
In Exercises 80 - 85, write the given sum as a product. You may need to use an Even/Odd or Cofunction Identity.
- \(\cos(3\theta) + \cos(5\theta)\)
- \(\sin(2\theta) - \sin(7\theta)\)
- \(\cos(5\theta) - \cos(6\theta)\)
- \(\sin(9\theta) - \sin(-\theta)\)
- \(\sin(\theta) + \cos(\theta)\)
- \(\cos(\theta) - \sin(\theta)\)
- Suppose \(\theta\) is a Quadrant I angle with \(\sin(\theta) = x\). Verify the following formulas
- \(\cos(\theta) = \sqrt{1-x^2}\)
- \(\sin(2\theta) = 2x\sqrt{1-x^2}\)
- \(\cos(2\theta) = 1 - 2x^2\)
- Discuss with your classmates how each of the formulas, if any, in Exercise 86 change if we change assume \(\theta\) is a Quadrant II, III, or IV angle.
- Suppose \(\theta\) is a Quadrant I angle with \(\tan(\theta) = x\). Verify the following formulas
- \(\cos(\theta) = \dfrac{1}{\sqrt{x^2+1}}\)
- \(\sin(\theta) = \dfrac{x}{\sqrt{x^2+1}}\)
- \(\sin(2\theta) = \dfrac{2x}{x^2+1}\)
- \(\cos(2\theta) = \dfrac{1-x^2}{x^2+1}\)
- Discuss with your classmates how each of the formulas, if any, in Exercise 88 change if we change assume \(\theta\) is a Quadrant II, III, or IV angle.
- If \(\sin(\theta) = \dfrac{x}{2}\) for \(-\dfrac{\pi}{2} < \theta < \dfrac{\pi}{2}\), find an expression for \(\cos(2\theta)\) in terms of \(x\).
- If \(\tan(\theta) = \dfrac{x}{7}\) for \(-\dfrac{\pi}{2} < \theta < \dfrac{\pi}{2}\), find an expression for \(\sin(2\theta)\) in terms of \(x\).
- If \(\sec(\theta) = \dfrac{x}{4}\) for \(0 < \theta < \dfrac{\pi}{2}\), find an expression for \(\ln|\sec(\theta) + \tan(\theta)|\) in terms of \(x\).
- Show that \(\cos^{2}(\theta) - \sin^{2}(\theta) = 2\cos^{2}(\theta) - 1 = 1 - 2\sin^{2}(\theta)\) for all \(\theta\).
- Let \(\theta\) be a Quadrant III angle with \(\cos(\theta) = -\dfrac{1}{5}\). Show that this is not enough information to determine the sign of \(\sin\left(\dfrac{\theta}{2}\right)\) by first assuming \(3\pi < \theta < \dfrac{7\pi}{2}\) and then assuming \(\pi < \theta < \dfrac{3\pi}{2}\) and computing \(\sin\left(\dfrac{\theta}{2}\right)\) in both cases.
- Without using your calculator, show that \(\dfrac{\sqrt{2 + \sqrt{3}}}{2} = \dfrac{\sqrt{6} + \sqrt{2}}{4}\)
- In part d of Example 10.4.3, we wrote \(\cos(3\theta)\) as a polynomial in terms of \(\cos(\theta)\). In Exercise 69, we had you verify an identity which expresses \(\cos(4\theta)\) as a polynomial in terms of \(\cos(\theta)\). Can you find a polynomial in terms of \(\cos(\theta)\) for \(\cos(5\theta)\)? \(\cos(6\theta)\)? Can you find a pattern so that \(\cos(n\theta)\) could be written as a polynomial in cosine for any natural number \(n\)?
- In Exercise 65, we has you verify an identity which expresses \(\sin(3\theta)\) as a polynomial in terms of \(\sin(\theta)\). Can you do the same for \(\sin(5\theta)\)? What about for \(\sin(4\theta)\)? If not, what goes wrong?
- Verify the Even / Odd Identities for tangent, secant, cosecant and cotangent.
- Verify the Cofunction Identities for tangent, secant, cosecant and cotangent.
- Verify the Difference Identities for sine and tangent.
- Verify the Product to Sum Identities.
- Verify the Sum to Product Identities.
Answers
- \(\cos(75^{\circ}) = \dfrac{\sqrt{6} - \sqrt{2}}{4}\)
- \(\sec(165^{\circ}) = -\dfrac{4}{\sqrt{2}+\sqrt{6}} = \sqrt{2} - \sqrt{6}\)
- \(\sin(105^{\circ}) = \dfrac{\sqrt{6}+\sqrt{2}}{4}\)
- \(\csc(195^{\circ}) = \dfrac{4}{\sqrt{2}-\sqrt{6}} = -(\sqrt{2}+\sqrt{6})\)
- \(\cot(255^{\circ}) = \dfrac{\sqrt{3}-1}{\sqrt{3}+1} = 2-\sqrt{3}\)
- \(\tan(375^{\circ}) = \dfrac{3-\sqrt{3}}{3+\sqrt{3}} = 2-\sqrt{3}\)
- \(\cos\left(\dfrac{13\pi}{12}\right) = -\dfrac{\sqrt{6}+\sqrt{2}}{4}\)
- \(\sin\left(\dfrac{11\pi}{12}\right) = \dfrac{\sqrt{6} - \sqrt{2}}{4}\)
- \(\tan\left(\dfrac{13\pi}{12}\right) = \dfrac{3-\sqrt{3}}{3+\sqrt{3}} = 2-\sqrt{3}\)
- \(\cos \left( \dfrac{7\pi}{12} \right) = \dfrac{\sqrt{2} - \sqrt{6}}{4}\)
- \(\tan \left( \dfrac{17\pi}{12} \right) = 2 + \sqrt{3}\)
- \(\sin \left( \dfrac{\pi}{12} \right) = \dfrac{\sqrt{6} - \sqrt{2}}{4}\)
- \(\cot \left( \dfrac{11\pi}{12} \right) = -(2 + \sqrt{3})\)
- \(\csc \left( \dfrac{5\pi}{12} \right) = \sqrt{6} - \sqrt{2}\)
- \(\sec \left( -\dfrac{\pi}{12} \right) = \sqrt{6} - \sqrt{2}\)
-
- \(\cos(\alpha + \beta) = -\dfrac{\sqrt{2}}{10}\)
- \(\sin(\alpha + \beta) = \dfrac{7\sqrt{2}}{10}\)
- \(\sin(\alpha - \beta) = \dfrac{\sqrt{2}}{2}\)
- \(\tan(\alpha - \beta) = -1\)
- \(\tan(\alpha + \beta) = -7\)
- \(\cos(\alpha - \beta)= -\dfrac{\sqrt{2}}{2}\)
-
- \(\cos(\alpha + \beta) = - \dfrac{4+7\sqrt{2}}{30}\)
- \(\sin(\alpha + \beta) = \dfrac{28-\sqrt{2}}{30}\)
- \(\sin(\alpha - \beta) = - \dfrac{28+\sqrt{2}}{30}\)
- \(\tan(\alpha - \beta)= \dfrac{28+\sqrt{2}}{4-7\sqrt{2}} = -\dfrac{63+100\sqrt{2}}{41}\)
- \(\tan(\alpha + \beta) = \dfrac{-28+\sqrt{2}}{4+7\sqrt{2}} = \dfrac{63-100\sqrt{2}}{41}\)
- \(\cos(\alpha - \beta) = \dfrac{-4+7\sqrt{2}}{30}\)
-
- \(\sin(\alpha + \beta) = \dfrac{16}{65}\)
- \(\cos(\alpha - \beta) = \dfrac{33}{65}\)
- \(\tan(\alpha - \beta) = \dfrac{56}{33}\)
-
- \(\csc(\alpha - \beta) = -\dfrac{5}{4}\)
- \(\sec(\alpha + \beta) = \dfrac{125}{117}\)
- \(\cot(\alpha + \beta) = \dfrac{117}{44}\)
- \(\cos(75^{\circ}) = \dfrac{\sqrt{2-\sqrt{3}}}{2}\)
- \(\sin(105^{\circ}) = \dfrac{\sqrt{2+\sqrt{3}}}{2}\)
- \(\cos(67.5^{\circ}) = \dfrac{\sqrt{2-\sqrt{2}}}{2}\)
- \(\sin(157.5^{\circ}) = \dfrac{\sqrt{2-\sqrt{2}}}{2}\)
- \(\tan(112.5^{\circ}) = - \sqrt{\dfrac{2+\sqrt{2}}{2-\sqrt{2}}} = -1 - \sqrt{2}\)
- \(\cos\left( \dfrac{7\pi}{12} \right) = -\dfrac{\sqrt{2-\sqrt{3}}}{2}\)
- \(\sin\left( \dfrac{\pi}{12} \right) = \dfrac{\sqrt{2-\sqrt{3}}}{2}\)
- \(\cos \left( \dfrac{\pi}{8} \right) = \dfrac{\sqrt{2 + \sqrt{2}}}{2}\)
- \(\sin \left( \dfrac{5\pi}{8} \right) = \dfrac{\sqrt{2 + \sqrt{2}}}{2}\)
- \(\tan \left( \dfrac{7\pi}{8} \right) = -\sqrt{ \dfrac{2 - \sqrt{2}}{2 + \sqrt{2}} } =1-\sqrt{2}\)
-
- \(\sin(2\theta) = -\dfrac{336}{625}\)
- \(\sin\left(\frac{\theta}{2}\right) = \dfrac{\sqrt{2}}{10}\)
- \(\cos(2\theta) = \dfrac{527}{625}\)
- \(\cos\left(\frac{\theta}{2}\right) = -\dfrac{7\sqrt{2}}{10}\)
- \(\tan(2\theta) = -\dfrac{336}{527}\)
- \(\tan\left(\frac{\theta}{2}\right) = -\dfrac{1}{7}\)
-
- \(\sin(2\theta) = \dfrac{2520}{2809}\)
- \(\sin\left(\frac{\theta}{2}\right) = \dfrac{5\sqrt{106}}{106}\)
- \(\cos(2\theta) = -\dfrac{1241}{2809}\)
- \(\cos\left(\frac{\theta}{2}\right) = \dfrac{9\sqrt{106}}{106}\)
- \(\tan(2\theta) = -\dfrac{2520}{1241}\)
- \(\tan\left(\frac{\theta}{2}\right) = \dfrac{5}{9}\)
-
- \(\sin(2\theta) = \dfrac{120}{169}\)
- \(\sin\left(\frac{\theta}{2}\right) = \dfrac{3\sqrt{13}}{13}\)
- \(\cos(2\theta) = -\dfrac{119}{169}\)
- \(\cos\left(\frac{\theta}{2}\right) = -\dfrac{2\sqrt{13}}{13}\)
- \(\tan(2\theta) = -\dfrac{120}{119}\)
- \(\tan\left(\frac{\theta}{2}\right) = -\dfrac{3}{2}\)
-
- \(\sin(2\theta) = -\dfrac{\sqrt{15}}{8}\)
- \(\sin\left(\frac{\theta}{2}\right) =\dfrac{\sqrt{8+2\sqrt{15}}}{4} \\ \phantom{\tan\left(\frac{\theta}{2}\right) = 4+\sqrt{15}}\)
- \(\cos(2\theta) = \dfrac{7}{8}\)
- \(\cos\left(\frac{\theta}{2}\right) = \dfrac{\sqrt{8-2\sqrt{15}}}{4} \\ \phantom{\tan\left(\frac{\theta}{2}\right) = 4+\sqrt{15}}\)
- \(\tan(2\theta) = -\dfrac{\sqrt{15}}{7}\)
- \(\tan\left(\frac{\theta}{2}\right) = \sqrt{\dfrac{8+2\sqrt{15}}{8-2\sqrt{15}}} \\ \tan\left(\frac{\theta}{2}\right) = 4+\sqrt{15}\)
-
- \(\sin(2\theta) = \dfrac{24}{25}\)
- \(\sin\left(\frac{\theta}{2}\right) = \dfrac{\sqrt{5}}{5}\)
- \(\cos(2\theta) = -\dfrac{7}{25}\)
- \(\cos\left(\frac{\theta}{2}\right) = \dfrac{2\sqrt{5}}{5}\)
- \(\tan(2\theta)=-\dfrac{24}{7}\)
- \(\tan\left(\frac{\theta}{2}\right) = \dfrac{1}{2}\)
-
- \(\sin(2\theta) = \dfrac{24}{25}\)
- \(\sin\left(\frac{\theta}{2}\right) = \dfrac{2\sqrt{5}}{5}\)
- \(\cos(2\theta) = -\dfrac{7}{25}\)
- \(\cos\left(\frac{\theta}{2}\right) = -\dfrac{\sqrt{5}}{5}\)
- \(\tan(2\theta)=-\dfrac{24}{7}\)
- \(\tan\left(\frac{\theta}{2}\right) = -2\)
-
- \(\sin(2\theta) = -\dfrac{120}{169}\)
- \(\sin\left(\frac{\theta}{2}\right) = \dfrac{\sqrt{26}}{26}\)
- \(\cos(2\theta) = \dfrac{119}{169}\)
- \(\cos\left(\frac{\theta}{2}\right) = -\dfrac{5\sqrt{26}}{26}\)
- \(\tan(2\theta)=-\dfrac{120}{119}\)
- \(\tan\left(\frac{\theta}{2}\right) = -\dfrac{1}{5}\)
-
- \(\sin(2\theta) = -\dfrac{120}{169}\)
- \(\sin\left(\frac{\theta}{2}\right) = \dfrac{5\sqrt{26}}{26}\)
- \(\cos(2\theta) = \dfrac{119}{169}\)
- \(\cos\left(\frac{\theta}{2}\right) = \dfrac{\sqrt{26}}{26}\)
- \(\tan(2\theta)=-\dfrac{120}{119}\)
- \(\tan\left(\frac{\theta}{2}\right) = 5\)
-
- \(\sin(2\theta) = -\dfrac{4}{5}\)
- \(\sin\left(\frac{\theta}{2}\right) = \dfrac{\sqrt{50-10\sqrt{5}}}{10} \\ \phantom{\tan\left(\frac{\theta}{2}\right) =\dfrac{5-5\sqrt{5}}{10}}\)
- \(\cos(2\theta) = -\dfrac{3}{5}\)
- \(\cos\left(\frac{\theta}{2}\right)= -\dfrac{\sqrt{50+10\sqrt{5}}}{10} \\ \phantom{\tan\left(\frac{\theta}{2}\right) =\dfrac{5-5\sqrt{5}}{10}}\)
- \(\tan(2\theta)=\dfrac{4}{3}\)
- \(\tan\left(\frac{\theta}{2}\right) = -\sqrt{\dfrac{5-\sqrt{5}}{5+\sqrt{5}}} \\ \tan\left(\frac{\theta}{2}\right) =\dfrac{5-5\sqrt{5}}{10}\)
-
- \(\sin(2\theta) = -\dfrac{4}{5}\)
- \(\sin\left(\frac{\theta}{2}\right) = \dfrac{\sqrt{50+10\sqrt{5}}}{10} \\ \phantom{\tan\left(\frac{\theta}{2}\right) =\dfrac{5-5\sqrt{5}}{10}}\)
- \(\cos(2\theta) = -\dfrac{3}{5}\)
- \(\cos\left(\frac{\theta}{2}\right)= \dfrac{\sqrt{50-10\sqrt{5}}}{10} \\ \phantom{\tan\left(\frac{\theta}{2}\right) =\dfrac{5-5\sqrt{5}}{10}}\)
- \(\tan(2\theta)=\dfrac{4}{3}\)
- \(\tan\left(\frac{\theta}{2}\right) = \sqrt{\dfrac{5+\sqrt{5}}{5-\sqrt{5}}} \\ \tan\left(\frac{\theta}{2}\right) =\dfrac{5+5\sqrt{5}}{10}\)
- \(\dfrac{\cos(2\theta) + \cos(8\theta)}{2}\)
- \(\dfrac{\cos(5\theta) - \cos(9\theta)}{2}\)
- \(\dfrac{\sin(8\theta) + \sin(10\theta)}{2}\)
- \(\dfrac{\cos(4\theta) + \cos(8\theta)}{2}\)
- \(\dfrac{\cos(\theta) - \cos(5\theta)}{2}\)
- \(\dfrac{\sin(2\theta) + \sin(4\theta)}{2}\)
- \(2\cos(4\theta)\cos(\theta)\)
- \(-2\cos \left( \dfrac{9}{2}\theta \right) \sin \left( \dfrac{5}{2}\theta \right)\)
- \(2\sin \left( \dfrac{11}{2}\theta \right) \sin \left( \dfrac{1}{2}\theta \right)\)
- \(2\cos(4\theta)\sin(5\theta)\)
- \(\sqrt{2}\cos \left(\theta - \dfrac{\pi}{4} \right)\)
- \(-\sqrt{2}\sin \left(\theta - \dfrac{\pi}{4} \right)\)
- \(1 - \dfrac{x^{2}}{2}\)
- \(\dfrac{14x}{x^{2} + 49}\)
- \(\ln |x + \sqrt{x^{2} + 16}| - \ln(4)\)