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Graphs and Symmetry

  • Page ID
    221074
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    Graphs and Symmetry

    1. Symmetry (Geometry)

       

      Definition

      We say that a graph is symmetric with respect to the y axis if for every point (a,b) on the graph, there is also a point (-a,b) on the graph.

        
      Visually we have that the y axis acts as a mirror for the graph.  We will demonstrate several functions to test for symmetry graphically using the graphing calculator.


        Graph that is pretty flat near x=0 and goes up on the left and the right.  It is symmetric about the y-axis.

       

      Definition

      We say that a graph is symmetric with respect to the x axis if for every point (a,b) on the graph, there is also a point (a,-b) on the graph.


      Visually we have that the x axis acts as a mirror for the graph.  We will demonstrate several functions to test for symmetry graphically using the graphing calculator.  

       

       

      Definition

      We say that a graph is symmetric with respect to the origin if for every point (a,b) on the graph, there is also a point (-a,-b) on the graph.  


      Visually we have that given a point P on the graph if we draw a line segment PQ through P and the origin such that the origin is the midpoint of PQ, then Q is also on the graph.  


      Graph of a curve that goes up and then down in the second quadrant and down and up in the fourth quadrant.  Points P and Q are on the graph with the line connecting them going through the origin.

      We will use the graphing calculator to test for all three symmetries.

       

    2. Symmetry (Algebra)

       

      Examples:  
       

      1. x-axis Symmetry

        To test algebraically if a graph is symmetric with respect the x axis, we replace all the y's with -y and see if we get an equivalent expression.  

        1. For 

                  x - 2y = 5 

          we replace with 

                  x - 2(-y) = 5

          Simplifying we get

                  x + 2y = 5 

          which is not equivalent to the original expression.
           

        2. For 

                  x3 - y2 = 2 

          we replace with   

                  x3 - (-y)2 = 2 

          which is equivalent to the original expression, so that 

                  x3 - y2 = 2 

          is symmetric with respect to the x axis.
           

      2. y-axis Symmetry

        To test algebraically if a graph is symmetric with respect to the y axis, we replace all the x's with -x and see if we get an equivalent expression.
         

        1. For 

                  y = x 

          we replace with 

                  y = (-x)2 =  x 

          so that 

                  y = x 

          is symmetric with respect to the y axis.

        2. For 

                  y = x3  

                  we replace with  

                  y = (-x)3 = - x3  

          so that 

                  y = x3  

                  is not symmetric with respect to the y axis.
           

      3. Origin Symmetry

        To test algebraically if a graph is symmetric with respect to the origin we replace both x and y with -x and -y and see if the result is equivalent to the original expression.  

        1. For 

                  y = x3

          we replace with 

                  (-y) = (-x)3  

                  so that 

                  -y = -x3 or y = x3

          Hence  

                  y = x3  

          is symmetric with respect to the origin.  

       

    3. Intercepts

      We define the x intercepts as the points on the graph where the graph crosses the x axis.  If a point is on the x axis, then the y coordinate of the point is 0.  Hence to find the x intercepts, we set y = 0 and solve.

      Example:  

      Find the x intercepts of

              y = x2 + x - 2

      We set y = 0 so that

              0 =  x2 + x - 2 = (x + 2)(x - 1)

      Hence that x intercepts are at (-2,0) and (1,0)

       

      We define the y intercepts of a graph to be the points where the graph crosses the y axis.  At these points the x coordinate is 0 hence to fine the y intercepts we set x = 0 and find y.

      Example:   

      Find the y intercepts of  

              y = x2 + x - 2

      Solution:  

      We set x = 0 to get:  

              y = 0 + 0 - 2 = -2.  

      Hence the y intercept is at (0,-2).

     



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