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4.3E: Shape of the Graph Exercises

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4.3: Derivatives and the Shape of a Graph

194) If c is a critical point of f(x), when is there no local maximum or minimum at c? Explain.

195) For the function y=x3, is x=0 both an inflection point and a local maximum/minimum?

Answer:
It is not a local maximum/minimum because f does not change sign; it is an inflection point because f does change sign.

196) For the function y=x3, is x=0 an inflection point?

197) Is it possible for a point c to be both an inflection point and a local extrema of a twice differentiable function?

Answer:
No

198) Why do you need continuity for the first derivative test? Come up with an example.

199) Explain whether a concave-down function has to cross y=0 for some value of x.

Answer:
False; for example, y=x.

200) Explain whether a polynomial of degree 2 can have an inflection point.


For the following exercises, analyze the graphs of f, then list all intervals where f is increasing or decreasing.

201)

CNX_Calc_Figure_04_05_201.jpeg

Answer:
Increasing for 2<x<1 and x>2; decreasing for x<2 and 1<x<2

202)

CNX_Calc_Figure_04_05_202.jpeg

203)

CNX_Calc_Figure_04_05_203.jpeg

Answer:
Decreasing for x<1, increasing for x>1

204)

CNX_Calc_Figure_04_05_204.jpeg

205)

CNX_Calc_Figure_04_05_205.jpeg

Answer:
Decreasing for 2<x<1 and 1<x<2; increasing for 1<x<1 and x<2 and x>2

For the following exercises, analyze the graphs of f, then list all intervals where

a. f is increasing and decreasing and

b. the minima and maxima are located.

206)

CNX_Calc_Figure_04_05_206.jpeg

207)

CNX_Calc_Figure_04_05_207.jpeg

Answer:
a. Increasing over 2<x<1,0<x<1,x>2, decreasing over x<2,1<x<0,1<x<2;
b. maxima at x=1 and x=1, minima at x=2 and x=0 and x=2

208)

CNX_Calc_Figure_04_05_208.jpeg

209)

CNX_Calc_Figure_04_05_209.jpeg

Answer:
a. Increasing over x>0, decreasing over x<0;
b. Minimum at x=0

210)

CNX_Calc_Figure_04_05_210.jpeg

For the following exercises, analyze the graphs of f, then list all inflection points and intervals f that are concave up and concave down.

211)

CNX_Calc_Figure_04_05_211.jpeg

Answer:
Concave up on all x, no inflection points

212)

CNX_Calc_Figure_04_05_212.jpeg

213)

CNX_Calc_Figure_04_05_213.jpeg

Answer:
Concave up on all x, no inflection points (since f'(x) is always increasing)

214)

CNX_Calc_Figure_04_05_214.jpeg

215)

CNX_Calc_Figure_04_05_215.jpeg

Answer:
Concave up for x<0 and x>1, concave down for 0<x<1
inflection points at x=0 and x=1

For the following exercises, draw a graph that satisfies the given specifications for the domain x=[3,3]. The function does not have to be continuous or differentiable.

216) f(x)>0,f(x)>0 over x>1,3<x<0,f(x)=0 over 0<x<1

217) f(x)>0 over x>2,3<x<1,f(x)<0 over 1<x<2,f(x)<0 for all x

Answer:
answers will vary

218) f(x)<0 over 1<x<1,f(x)>0,3<x<1,1<x<3, local maximum at x=0, local minima at x=±2

219) There is a local maximum at x=2, local minimum at x=1, and the graph is neither concave up nor concave down.

Answer:
answers will vary

220) There are local maxima at x=±1, the function is concave up for all x, and the function remains positive for all x.

For the following exercises, determine

a. intervals where f is increasing or decreasing and

b. local minima and maxima of f.

221) f(x)=sinx+sin3x over −π<x<π

Answer:

a. Increasing over −\frac{π}{2}<x<\frac{π}{2}, decreasing over x<−π\frac{π}{2},x>\frac{π}{2}

b. Local maximum at x=\frac{π}{2}; local minimum at x=−\frac{π}{2}

222) f(x)=x^2+cosx


For the following exercise, determine a. intervals where f is concave up or concave down, and b. the inflection points of f.

223) f(x)=x^3−4x^2+x+2

Answer:

a. Concave up for x>\frac{4}{3}, concave down for x<\frac{4}{3}

b. Inflection point at x=\frac{4}{3}


For the following exercises, determine

a. intervals where f is increasing or decreasing,

b. local minima and maxima of f,

c. intervals where f is concave up and concave down, and

d. the inflection points of f.

224) f(x)=x^2−6x

225) f(x)=x^3−6x^2

Answer:
a. Increasing over x<0 and x>4, decreasing over 0<x<4
b. Maximum at x=0, minimum at x=4
c. Concave up for x>2, concave down for x<2
d. Infection point at x=2

226) f(x)=x^4−6x^3

227) f(x)=x^{11}−6x^{10}

Answer:
a. Increasing over x<0 and x>\frac{60}{11}, decreasing over 0<x<\frac{60}{11} b. Minimum at x=\frac{60}{11} c. Concave down for x<\frac{54}{11}, concave up for x>\frac{54}{11} d. Inflection point at x=\frac{54}{11}

228) f(x)=x+x^2−x^3

229) f(x)=x^2+x+1

Answer:

a. Increasing over x>−\frac{1}{2}, decreasing over x<−\frac{1}{2} b. Minimum at x=−\frac{1}{2} c. Concave up for all x d. No inflection points

230) f(x)=x^3+x^4


For the following exercises, determine

a. intervals where f is increasing or decreasing,

b. local minima and maxima of f,

c. intervals where f is concave up and concave down, and

d. the inflection points of f. Sketch the curve, then use a calculator to compare your answer. If you cannot determine the exact answer analytically, use a calculator.

231) [T] f(x)=sin(πx)−cos(πx) over x=[−1,1]

Answer:
a. Increases over −\frac{1}{4}<x<\frac{3}{4}, decreases over x>\frac{3}{4} and x<−\frac{1}{4} b. Minimum at x=−\frac{1}{4}, maximum at x=\frac{3}{4} c. Concave up for −\frac{3}{4}<x<\frac{1}{4}, concave down for x<−\frac{3}{4} and x>\frac{1}{4} d. Inflection points at x=−\frac{3}{4},x=\frac{1}{4}

232) [T] f(x)=x+sin(2x) over x=[−\frac{π}{2},\frac{π}{2}]

233) f(x)=sinx+tanx over (−\frac{π}{2},\frac{π}{2})

Answer:
a. Increasing for all x
b. No local minimum or maximum
c. Concave up for x>0, concave down for x<0
d. Inflection point at x=0

234) [T] f(x)=(x−2)^2(x−4)^2

235) [T] f(x)=\frac{1}{1−x},x≠1

Answer:
a. Increasing for all x where defined
b. No local minima or maxima
c. Concave up for x<1; concave down for x>1
d. No inflection points in domain

236) [T] f(x)=\frac{sinx}{x} over x=[−2π,2π] [2π,0)∪(0,2π]

237) f(x)=sin(x)e^x over x=[−π,π]

Answer:
Solution: a. Increasing over −\frac{π}{4}<x<\frac{3π}{4}, decreasing over x>\frac{3π}{4},x<−\frac{π}{4} b. Minimum at x=−\frac{π}{4}, maximum at x=\frac{3π}{4} c. Concave up for −\frac{π}{2}<x<\frac{π}{2}, concave down for x<−\frac{π}{2},x>\frac{π}{2} d. Infection points at x=±\frac{π}{2}

238) f(x)=lnx\sqrt{x},x>0

239) f(x)=\frac{1}{4}\sqrt{x}+\frac{1}{x},x>0

Answer:
Solution: a. Increasing over x>4, decreasing over 0<x<4 b. Minimum at x=4 c. Concave up for 0<x<8\sqrt[3]{2}, concave down for x>8\sqrt[3]{2} d. Inflection point at x=8\sqrt[3]{2}

240) f(x)=\frac{e^x}{x},x≠0

For the following exercises, interpret the sentences in terms of f,f′, and f''.

241) The population is growing more slowly. Here f is the population.

Answer:
f>0,f′>0,f''<0

242) A bike accelerates faster, but a car goes faster. Here f= Bike’s position minus Car’s position.

243) The airplane lands smoothly. Here f is the plane’s altitude.

Answer:
f>0,f′<0,f''<0

244) Stock prices are at their peak. Here fis the stock price.

245) The economy is picking up speed. Here f is a measure of the economy, such as GDP.

Answer:
f>0,f′>0,f''>0

For the following exercises, consider a third-degree polynomial f(x), which has the properties f′(1)=0,f′(3)=0.

Determine whether the following statements are true or false. Justify your answer.

246) f(x)=0 for some 1≤x≤3

247) f''(x)=0 for some 1≤x≤3

Answer:
True, by the Mean Value Theorem

248) There is no absolute maximum at x=3

249) If f(x) has three roots, then it has 1 inflection point.

Answer:
True, examine derivative

250) If f(x) has one inflection point, then it has three real roots.


4.3E: Shape of the Graph Exercises is shared under a CC BY-NC-SA license and was authored, remixed, and/or curated by LibreTexts.

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