1.3.3.1: Exercises
- Page ID
- 82925
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\(\newcommand{\avec}{\mathbf a}\) \(\newcommand{\bvec}{\mathbf b}\) \(\newcommand{\cvec}{\mathbf c}\) \(\newcommand{\dvec}{\mathbf d}\) \(\newcommand{\dtil}{\widetilde{\mathbf d}}\) \(\newcommand{\evec}{\mathbf e}\) \(\newcommand{\fvec}{\mathbf f}\) \(\newcommand{\nvec}{\mathbf n}\) \(\newcommand{\pvec}{\mathbf p}\) \(\newcommand{\qvec}{\mathbf q}\) \(\newcommand{\svec}{\mathbf s}\) \(\newcommand{\tvec}{\mathbf t}\) \(\newcommand{\uvec}{\mathbf u}\) \(\newcommand{\vvec}{\mathbf v}\) \(\newcommand{\wvec}{\mathbf w}\) \(\newcommand{\xvec}{\mathbf x}\) \(\newcommand{\yvec}{\mathbf y}\) \(\newcommand{\zvec}{\mathbf z}\) \(\newcommand{\rvec}{\mathbf r}\) \(\newcommand{\mvec}{\mathbf m}\) \(\newcommand{\zerovec}{\mathbf 0}\) \(\newcommand{\onevec}{\mathbf 1}\) \(\newcommand{\real}{\mathbb R}\) \(\newcommand{\twovec}[2]{\left[\begin{array}{r}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\ctwovec}[2]{\left[\begin{array}{c}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\threevec}[3]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\cthreevec}[3]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\fourvec}[4]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\cfourvec}[4]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\fivevec}[5]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\cfivevec}[5]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\mattwo}[4]{\left[\begin{array}{rr}#1 \amp #2 \\ #3 \amp #4 \\ \end{array}\right]}\) \(\newcommand{\laspan}[1]{\text{Span}\{#1\}}\) \(\newcommand{\bcal}{\cal B}\) \(\newcommand{\ccal}{\cal C}\) \(\newcommand{\scal}{\cal S}\) \(\newcommand{\wcal}{\cal W}\) \(\newcommand{\ecal}{\cal E}\) \(\newcommand{\coords}[2]{\left\{#1\right\}_{#2}}\) \(\newcommand{\gray}[1]{\color{gray}{#1}}\) \(\newcommand{\lgray}[1]{\color{lightgray}{#1}}\) \(\newcommand{\rank}{\operatorname{rank}}\) \(\newcommand{\row}{\text{Row}}\) \(\newcommand{\col}{\text{Col}}\) \(\renewcommand{\row}{\text{Row}}\) \(\newcommand{\nul}{\text{Nul}}\) \(\newcommand{\var}{\text{Var}}\) \(\newcommand{\corr}{\text{corr}}\) \(\newcommand{\len}[1]{\left|#1\right|}\) \(\newcommand{\bbar}{\overline{\bvec}}\) \(\newcommand{\bhat}{\widehat{\bvec}}\) \(\newcommand{\bperp}{\bvec^\perp}\) \(\newcommand{\xhat}{\widehat{\xvec}}\) \(\newcommand{\vhat}{\widehat{\vvec}}\) \(\newcommand{\uhat}{\widehat{\uvec}}\) \(\newcommand{\what}{\widehat{\wvec}}\) \(\newcommand{\Sighat}{\widehat{\Sigma}}\) \(\newcommand{\lt}{<}\) \(\newcommand{\gt}{>}\) \(\newcommand{\amp}{&}\) \(\definecolor{fillinmathshade}{gray}{0.9}\)Section 1.3.3.1 Exercises
- Identify the property of real numbers illustrated by each equation.
- \( (2 + 7) + 5 = 2 + (7 + 5) \)
- \( \sqrt{2}+(\sqrt{7}+\sqrt{5}) = \sqrt{2}+(\sqrt{5}+\sqrt{7})\)
- \( 2(7+\sqrt{5}) = 14+2\sqrt{5}\)
- \( 2\cdot \sqrt{7}=\sqrt{7}\cdot 2\)
- \( 2(7+\sqrt{5}) = (7+\sqrt{5})2\)
- \( 2 + 0 = 2\)
- \(\sqrt{5}\cdot 1=\sqrt{5} \)
- \(17 + (-17) = 0\)
- Evaluate \( 8 \left( \dfrac{3}{4}-\dfrac{1}{2}\right)\) in two ways using the distributive property. Which way do you think is easier?
- A deposit of P dollars, invested at a simple interest rate, r, (in decimal form) will grow to amount A after t years. \(A=P(1+rt)\)
- Rewrite the right side of this formula so that it has no parentheses.
- Simplify: \(12(\dfrac{1}{3}n+\dfrac{3}{4})\).
- Simplify: \(100(0.3+0.25q)\).
- Simplify: \(100(0.7+0.15p)\).
- Simplify: \(100(0.04+0.35d)\).
- Simplify: \(−2(4y+1)\).
- Simplify: \(−3(6m+5)\).
- Simplify: \(−6(8n+11)\).
- Simplify: \(−11(4-3a)\).
- Simplify: \(−5(2-3a)\).
- Simplify: \(−7(8-15y)\).
- Simplify: \(−(y+5)\).
- Simplify: \(−(z-11)\).
- Simplify: \(−(x -4)\).
- Simplify: \(8−2(x + 3)\).
- Simplify: \(9−3(x + 2)\).
- Simplify: \(7x−5(x + 4)\).
- Simplify: \(4(x - 8)−(x + 3)\).
- Simplify: \(6(x - 9)−(x + 12)\).
- Simplify: \(8(x - 1)-(x + 5)\).