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- https://math.libretexts.org/Bookshelves/Combinatorics_and_Discrete_Mathematics/Applied_Discrete_Structures_(Doerr_and_Levasseur)/00%3A_Front_Matter/04%3A_ColophonEdition 3rd Edition - version 8 ©2021 Al Doerr, Ken Levasseur Applied Discrete Structures by Alan Doerr and Kenneth Levasseur is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike ...Edition 3rd Edition - version 8 ©2021 Al Doerr, Ken Levasseur Applied Discrete Structures by Alan Doerr and Kenneth Levasseur is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 United States License. You are free to Share: copy and redistribute the material in any medium or format; Adapt: remix, transform, and build upon the material. You may not use the material for commercial purposes. The licensor cannot revoke these freedoms as long as you follow the license terms.
- https://math.libretexts.org/Bookshelves/Combinatorics_and_Discrete_Mathematics/Applied_Discrete_Structures_(Doerr_and_Levasseur)/10%3A_TreesIn this chapter we will study the class of graphs called trees. Trees are frequently used in both mathematics and the sciences. Our solution of Example 2.1.1 is one simple instance. Since they are oft...In this chapter we will study the class of graphs called trees. Trees are frequently used in both mathematics and the sciences. Our solution of Example 2.1.1 is one simple instance. Since they are often used to illustrate or prove other concepts, a poor understanding of trees can be a serious handicap. For this reason, our ultimate goals are to: (1) define the various common types of trees, (2) identify some basic properties of trees, and (3) discuss some of the common applications of trees.
- https://math.libretexts.org/Courses/SUNY_Schenectady_County_Community_College/Discrete_Structures/12%3A_Boolean_Algebra/12.01%3A_Posets_RevisitedConsider the poset (P(A),⊆), where A={1,2,3}. The greatest lower bound of {1,2} and {1,3} is ℓ={1}. For any other element \...Consider the poset (P(A),⊆), where A={1,2,3}. The greatest lower bound of {1,2} and {1,3} is ℓ={1}. For any other element ℓ′ which is a subset of {a,b} and {a,c} (there is only one; what is it?), ℓ′⊆ℓ. The least element of P(A) is ∅ and the greatest element is A={a,b,c}. The Hasse diagram of this poset is shown in Figure \(\PageInd…
- https://math.libretexts.org/Bookshelves/Combinatorics_and_Discrete_Mathematics/Applied_Discrete_Structures_(Doerr_and_Levasseur)/00%3A_Front_Matter/01%3A_TitlePageApplied Discrete Structures Al Doerr Ken Levasseur Department of Mathematical Sciences University of Massachusetts Lowell kenneth_levasseur@uml.edu May 25, 2021
- https://math.libretexts.org/Bookshelves/Combinatorics_and_Discrete_Mathematics/Applied_Discrete_Structures_(Doerr_and_Levasseur)/00%3A_Front_Matter/07%3A_PrefaceWe had signed a contract for the second edition with Science Research Associates in 1988 but by the time the book was ready to print, SRA had been sold to MacMillan. The open source software movement ...We had signed a contract for the second edition with Science Research Associates in 1988 but by the time the book was ready to print, SRA had been sold to MacMillan. The open source software movement was just starting in the late 1980's and in 2005, the first version of Sage (later renamed SageMath), an open-source computer algebra system, was first released.
- https://math.libretexts.org/Bookshelves/Combinatorics_and_Discrete_Mathematics/Applied_Discrete_Structures_(Doerr_and_Levasseur)/12%3A_More_Matrix_Algebra/12.05%3A_Some_Applications\begin{equation*} \begin{split} e^Ae^B &= \left(\sum _{k=0}^{\infty } \frac{A^k}{k!}\right) \left(\sum _{k=0}^{\infty } \frac{B^k}{k!}\right)\\ & =\left(I + A+\frac{A^2}{2}+ \frac{A^3}{6}+ \cdots \rig...\begin{equation*} \begin{split} e^Ae^B &= \left(\sum _{k=0}^{\infty } \frac{A^k}{k!}\right) \left(\sum _{k=0}^{\infty } \frac{B^k}{k!}\right)\\ & =\left(I + A+\frac{A^2}{2}+ \frac{A^3}{6}+ \cdots \right)\left(I +B+\frac{B^2}{2}+ \frac{B^3}{6}+ \cdots \right)\\ &= I + A + B+ \frac{A^2}{2}+ A B + \frac{B^2}{2}+\frac{A^3}{6}+ \frac{A^2B}{2}+\frac{A B^2}{2}+ \frac{B^3}{6}+\cdots \\ &= I + (A+B) + \frac{1}{2}\left(A^2+ 2 A B + B^2\right)+ \frac{1}{6}\left(A^3+ 3A^2B+ 3A B^2+ B^3\right)+\cdots \\ &=I…
- https://math.libretexts.org/Bookshelves/Combinatorics_and_Discrete_Mathematics/Applied_Discrete_Structures_(Doerr_and_Levasseur)/10%3A_Trees/10.02%3A_Spanning_TreesThe method that we have used (in Step 2.1) to select a bridge when more than one minimally weighted bridge exists is to order all bridges alphabetically by the vertex in L and then, if further tie...The method that we have used (in Step 2.1) to select a bridge when more than one minimally weighted bridge exists is to order all bridges alphabetically by the vertex in L and then, if further ties exist, by the vertex in R. The first vertex in that order is selected in Step 2.1 of the algorithm.
- https://math.libretexts.org/Courses/SUNY_Schenectady_County_Community_College/Discrete_Structures/12%3A_Boolean_Algebra/12.02%3A_Lattices\begin{equation*} \begin{array}{cc} \begin{array}{c|ccccc} \lor & \pmb{0} & a & b & c & \pmb{1} \\ \hline \pmb{0} & \pmb{0} & a & b & c & \pmb{1} \\ a & a & a & \pmb{1} & \pmb{1} & \pmb{1} \\ b & b & ...\begin{equation*} \boldsymbol{\begin{array}{cc} \begin{array}{c|ccccc} \lor & \pmb{0} & a & b & c & \pmb{1} \\ \hline \pmb{0} & \pmb{0} & a & b & c & \pmb{1} \\ a & a & a & \pmb{1} & \pmb{1} & \pmb{1} \\ b & b & \pmb{1} & b & \pmb{1} & \pmb{1} \\ c & c & \pmb{1} & \pmb{1} & c & \pmb{1} \\ \pmb{1} & \pmb{1} & \pmb{1} & \pmb{1} & \pmb{1} & \pmb{1} \\ \end{array}} & \begin{array}{c|ccccc} \land & \pmb{0} & a & b & c & \pmb{1} \\ \hline \pmb{0} & \pmb{0} & \pmb{0} & \pmb{0} & \pmb{0} & \pmb{0} \\ a & \pmb{0} & …
- https://math.libretexts.org/Courses/SUNY_Schenectady_County_Community_College/Discrete_Structures/13%3A_Monoids_and_Automata/13.05%3A_The_Machine_of_a_MonoidWill we obtain a unit-time delay machine when we construct the machine of U? We can't expect to get exactly the same machine because the unit-time delay machine is not a state machine and t...Will we obtain a unit-time delay machine when we construct the machine of U? We can't expect to get exactly the same machine because the unit-time delay machine is not a state machine and the machine of a monoid is a state machine.
- https://math.libretexts.org/Courses/SUNY_Schenectady_County_Community_College/Discrete_Structures/12%3A_Boolean_Algebra/12.04%3A_Atoms_of_a_Boolean_AlgebraCertainly, the Boolean algebras [D30;∨,∧,∧¯] and [P(A);∪,∩,c] have the same graph (that of Figure \(\PageIndex...Certainly, the Boolean algebras [D30;∨,∧,∧¯] and [P(A);∪,∩,c] have the same graph (that of Figure \PageIndex1), the same number of atoms, and, in all respects, look the same except for the names of the elements and the operations.
- https://math.libretexts.org/Bookshelves/Combinatorics_and_Discrete_Mathematics/Applied_Discrete_Structures_(Doerr_and_Levasseur)/11%3A_Algebraic_Structures/11.02%3A_Algebraic_SystemsIf A and B are sets, then A⊕B=(A∪B)−(A∩B). We will leave it to the reader to prove that ⊕ is associative over P(U). The identity of the g...If A and B are sets, then A⊕B=(A∪B)−(A∩B). We will leave it to the reader to prove that ⊕ is associative over P(U). The identity of the group is the empty set: A⊕∅=A. Every set is its own inverse since A⊕A=∅. Note that P(U) is not a group with union or intersection.