13.4: Introduction to Conics- Answers to the Homework Exercises
- Page ID
- 45126
\( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)
\( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)
\( \newcommand{\dsum}{\displaystyle\sum\limits} \)
\( \newcommand{\dint}{\displaystyle\int\limits} \)
\( \newcommand{\dlim}{\displaystyle\lim\limits} \)
\( \newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\)
( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\)
\( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)
\( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\)
\( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)
\( \newcommand{\Span}{\mathrm{span}}\)
\( \newcommand{\id}{\mathrm{id}}\)
\( \newcommand{\Span}{\mathrm{span}}\)
\( \newcommand{\kernel}{\mathrm{null}\,}\)
\( \newcommand{\range}{\mathrm{range}\,}\)
\( \newcommand{\RealPart}{\mathrm{Re}}\)
\( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)
\( \newcommand{\Argument}{\mathrm{Arg}}\)
\( \newcommand{\norm}[1]{\| #1 \|}\)
\( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)
\( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\AA}{\unicode[.8,0]{x212B}}\)
\( \newcommand{\vectorA}[1]{\vec{#1}} % arrow\)
\( \newcommand{\vectorAt}[1]{\vec{\text{#1}}} % arrow\)
\( \newcommand{\vectorB}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)
\( \newcommand{\vectorC}[1]{\textbf{#1}} \)
\( \newcommand{\vectorD}[1]{\overrightarrow{#1}} \)
\( \newcommand{\vectorDt}[1]{\overrightarrow{\text{#1}}} \)
\( \newcommand{\vectE}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{\mathbf {#1}}}} \)
\( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)
\(\newcommand{\longvect}{\overrightarrow}\)
\( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)
\(\newcommand{\ket}[1]{\left| #1 \right>}\)
\(\newcommand{\bra}[1]{\left< #1 \right|}\)
\(\newcommand{\braket}[2]{\left< #1 \vphantom{#2} \right| \left. #2 \vphantom{#1} \right>}\)
\(\newcommand{\braopket}[3]{\left< #1 \vphantom{#2}\vphantom{#3} \right| #2 \vphantom{#1}\vphantom{#3} \left| #3 \vphantom{#1}\vphantom{#2} \right>}\)
\(\newcommand{\qmvec}[1]{\mathbf{\vec{#1}}}\)
\(\newcommand{\op}[1]{\hat{\mathbf{#1}}}\)
\(\newcommand{\expect}[1]{\langle #1 \rangle}\)
\(\newcommand{\dfn}[1]{\emph{\textbf{#1}}}\)
Introduction to Conics
- \(\left(0,\dfrac{1}{2}\right)\); \(\sqrt{109}\approx 10.44\)
- \(\left(-\dfrac{1}{2},-\dfrac{3}{2}\right)\); \(\sqrt{34}\approx 5.83\)
- \(\left(\dfrac{185}{2},-69\right)\); \(41\)
- circle
- ellipse
- parabola
- parabola
Circles
- \((x+1)^2+(y+5)^2=100\)

Figure 13.4.1
- \((x+3)^2+\left(y-\dfrac{7}{13}\right)^2=\dfrac{1}{4}\)

Figure 13.4.2
- \((x+9)^2+y^2=25\); center \((-9,0)\), radius \(r=5\)

Figure 13.4.3
- \(\left(x+\dfrac{5}{2}\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{30}{4}\); center \(\left(-\dfrac{5}{2},\dfrac{1}{2}\right)\), radius \(r=\dfrac{\sqrt{30}}{2}\)

Figure 13.4.4
- \(\left(x+\dfrac{1}{2}\right)^2+\left(y-\dfrac{3}{5}\right)^2=\dfrac{161}{100}\); center \(\left(-\dfrac{1}{2},\dfrac{3}{5}\right)\), radius \(r=\dfrac{\sqrt{161}}{10}\)

Figure 13.4.5
- \((x-3)^2+(y-6)^2=20\)
- \((x-1)^2+\left(y-\dfrac{3}{2}\right)^2=\dfrac{13}{2}\)
Parabolas
- Vertex \((3,0)\); Focus \((3,-4)\); Directrix \(y=4\)

Figure 13.4.6
- Vertex \((-3,2)\); Focus \((-6,2)\); Directrix \(x=0\)

Figure 13.4.7
- Vertex \((1,-3)\); Focus \((1,-2)\); Directrix \(y=-4\)

Figure 13.4.8
- Vertex \((2,4)\); Focus \(\left(\dfrac{13}{2},4\right)\); Directrix \(x=-\dfrac{5}{2}\)

Figure 13.4.9
- \((x+1)^2=8(y-6)\); Vertex \((-1,6)\); Focus \((-1,8)\); Directrix \(y=4\)

Figure 13.4.10
- \((y+1)^2=-\dfrac{1}{2}(x-10)\); Vertex \((10,-1)\); Focus \(\left(\dfrac{79}{8},-1\right)\); Directrix \(x=\dfrac{81}{8}\)

Figure 13.4.11


