1.4: Composition and Inverses
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Composition of Functions
Example \PageIndex{1}
Sociologists in Holland determine that the number of people y waiting in a water ride at an amusement park is given by
y = \dfrac{1}{50}C^2 + C + 2 \nonumber
where C is the temperature in degrees C. The formula to convert Fahrenheit to Celsius C is given by
C = \dfrac{5}{9}F + \dfrac{160}{9}. \nonumber
To get a function of F we compose the two function:
y(C(F)) = \left(\dfrac{1}{50}\right)\left[\dfrac{5}{9}F + \dfrac{160}{9}\right]^2 + \left[\dfrac{5}{9}F + \dfrac{160}{9}\right] + 2 \nonumber
Exercise \PageIndex{1}
If
- f(x) = 3x + 2
- g(x) = 2x^2 + 1
- h(x) = \sqrt{x-2}
- c(x) = 4
Find
- f(g(x))
- f(h(x))
- f(f(x))
- h(c(x))
- c(f(g(h(x))))
1-1 Functions
Definition: 1-1 (one-to-one)
A function f(x) is 1-1 if
f(a) = f(b)
implies that
a = b.
Example \PageIndex{2}
If
f(x) = 3x + 1 \nonumber
then
3a + 1 = 3b + 1 \nonumber
implies that
3a = 3b \nonumber
hence
a = b \nonumber
therefore f(x) is 1-1.
Example \PageIndex{3}
If
f(x) = x^2 \nonumber
then
a^2 = b^2 \nonumber
implies that
a^2-b^2 = 0 \nonumber
or that
(a - b)(a + b) = 0 \nonumber
hence
a = b \text{ or } a = -b \nonumber
For example
f (2) = f (-2) = 4 \nonumber
Hence f(x) is not 1-1.
Horizontal Line Test
If every horizontal line passes through f(x) at most once then f(x) is 1-1.
Inverse Functions
Definition: Inverse function
A function g(x) is an inverse of f(x) if
f(g(x)) = g(f(x)) = x.
Example \PageIndex{4}
The volume of a lake is modeled by the equation
V(t) = \dfrac{1}{125}h^3. \nonumber
Show that the inverse is
h(N) = 5V^{\frac{1}{3}}. \nonumber
Solution: We have
h(V(h)) = 5(\dfrac{1}{125}h^3)^{\frac{1}{3}} = \dfrac{5}{5}h = h \nonumber
and
v(h(V)) = \dfrac{1}{125}(5V^{\frac{1}{3}})^3 = \dfrac{1}{125}(125V) = V. \nonumber
Step by Step Process for Finding the Inverse
- Interchange the variables
- Solve for y
- Write in terms of f^{-1}(x)
Example\PageIndex{5}
Find the inverse of
f (x) = y = 3x^3 - 5 \nonumber
Solution
\begin{align} x &= 3y^3 - 5 \\ x + 5 &= 3y^3 \\ \dfrac{(x + 5)}{3} &= y^3 ,\\ \left[\dfrac{(x + 5)}{3}\right]^{\frac{1}{3}}&=y \end{align}
f^{-1}(x) = \left[\dfrac{(x + 5)}{ 3 }\right]^{\frac{1}{3}}. \nonumber
Graphing
To graph an inverse we draw the y = x line and reflect the graph across this line.
To interactively view the graph of an inverse click here:
mathcsjava.emporia.edu/~greenlar/Inverse/inverse.html
Contributors and Attributions
- Larry Green (Lake Tahoe Community College)
Integrated by Justin Marshall.