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5.10: Homework- Growth and Decay

  • Page ID
    88674
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    1. Money that is compounded continuously follows the differential equation \(M'(t) = r M(t)\), where \(t\) is measured in years, \(M(t)\) is measured in dollars, and \(r\) is the rate. Suppose \(r = 0.05\) and \(M(0) = 1000\).
      1. What is a function that satisfies this initial value problem?
        We know from class that this is an exponential \(M(t) = 1000 e^{0.05 t}\).
        ans
      2. How much money will there be at year 30 (i.e. \(t = 30\))?
        $4481. 69
        ans
      3. When will there be \(2000\) dollars?
        \(13.86\) years.
        ans
    2. The mass of bacteria on a deceased animal follows the equation \(M'(t) = 0.1 M(t)\), where \(M(t)\) is measured in grams and \(t\) is measured in hours.
      1. If \(M(0) = 1\), what is a function that satisfies this initial value problem?
        \(M(t) = e^{0.1t}\)
        ans
      2. How much bacteria will there be at \(t = 24\)?
        \(11.02\) grams
        ans
      3. When will there be one kilogram of bacteria?
        2 days, 21 hours
        ans
    3. For a cooling object outside in \(0^\circ\) degree weather, temperature decreases according to the differential equation \(T'(t) = -0.05 T(t)\), where \(t\) is measured in minutes and \(T(t)\) measured in Fahrenheit.
      1. If the temperature is initially \(72^\circ\), what is the function that satisfies this initial value problem?
        \(T(t) = 72 e^{-0.05t}\)
        ans
      2. What is the temperature after 1/2 hour?
        \(16.06\) degrees
        ans
      3. At what time did the object reach the freezing point of water?
        Approximately \(16\) minutes
        ans

    This page titled 5.10: Homework- Growth and Decay is shared under a CC BY 4.0 license and was authored, remixed, and/or curated by Tyler Seacrest via source content that was edited to the style and standards of the LibreTexts platform; a detailed edit history is available upon request.