12.6: Exercises
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Prove: If B is finite and A⊆B, then A is finite and |A|≤|B|.
Suppose that A, B, and C are finite subsets of a universal set U.
- Prove: If A and B are disjoint, then |A⊔B|=|A|+|B|.
- Prove: |A∪B|=|A|+|B|−|A∩B|.
- Hint.
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See Exercise 9.9.5, and use the equality from Task a.
- Determine a similar formula for |A∪B∪C.
- Hint.
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Draw a Venn diagram first.
Use induction to prove directly that if |A|=n then |P(A)|=2n. Use Worked Example 12.2.1 as a model for your proof of the induction step.
Prove: If |A|=∞ and A⊆B, then |B|=∞.
Prove Fact 12.3.2.
Combine Example 12.3.3 and Example 12.3.10 to verify that the unit interval (0,1) and R have the same size.
- Hint.
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First map the punctured circle ˆS onto some open interval in the x-axis by “unrolling” ˆS.
Use Example 12.3.3 and the function f(x)=tanx to prove that the interval (−π/2,π/2) and R have the same size.
- Hint.
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The function f(x)=tanx is not one-to-one, but it becomes one-to-one if you restrict its domain to an appropriate interval
Suppose A is a set with |A|=n. Then we can enumerate its elements as A={a1,a2,…,an}.
- Construct a bijection from the power set of A to the set of words in the alphabet Σ={T,F} of length n.
Note that there are two tasks required here.
- Explicitly describe a function f:P(A)→Σ∗n by describing the input-output rule: give a detailed description of how, given a subset B⊆A, the word f(B) should be produced.
- Prove that your function f is a bijection.
- Hint.
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When determining the input-output rule for your function f:P(A)→Σ∗n, think of how one might construct an arbitrary subset of A, and then relate that process to a sequence of answers to n true/false questions.
- Use Task a to determine the cardinality of P(A). Explain.
- Hint
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See Note 1.3.1.
- Suppose k is some fixed (but unknown) integer, with 0≤k≤n. Let P(A)k represent the subset of P(A) consisting of all subsets of A that have exactly k elements. Describe how your bijection from Task a, could be used to count the elements of P(A)k.
- Hint.
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Consider how restricting the domain might help.