2.1E: Elementary Matrices Exercises
( \newcommand{\kernel}{\mathrm{null}\,}\)
Exercises for 1
solutions
2
For each of the following elementary matrices, describe the corresponding elementary row operation and write the inverse.
E=[103010001] E=[001010100] E=[1000120001] E=[100−210001] E=[010100001] E=[100010005]
- Interchange rows 1 and 3 of I. E−1=E.
- Add (−2) times row 1 of I to row 2. E−1=[100210001]
- Multiply row 3 of I by 5. E−1=[1000100015]
In each case find an elementary matrix E such that B=EA.
- A=[213−1], B=[211−2]
- A=[−1201], B=[1−201]
- A=[11−12], B=[−1211]
- A=[4132], B=[1−132]
- A=[−111−1], B=[−11−11]
- A=[21−13], B=[−1321]
- [−1001]
- [1−101]
- [0110]
Let A=[12−11] and
C=[−1121].
- Find elementary matrices E1 and E2 such that C=E2E1A.
- Show that there is no elementary matrix E such that C=EA.
- The only possibilities for E are [0110], [k001], [100k], [1k01], and [10k1]. In each case, EA has a row different from C.
If E is elementary, show that A and EA differ in at most two rows.
- Is I an elementary matrix? Explain.
- Is 0 an elementary matrix? Explain.
- No, 0 is not invertible.
In each case find an invertible matrix U such that UA=R is in reduced row-echelon form, and express U as a product of elementary matrices.
A=[1−12−210] A=[121512−1] A=[12−1031121−332] A=[21−103−1211−231]
-
[1−201][10012][10−51]
A=[10701−3]. Alternatively,
[10012][1−101][10−51]
A=[10701−3]. -
[120010001][1000150001][1000100−11]
[100010−201][100−310001][001010100]A=[10151501−75−250000]
In each case find an invertible matrix U such that UA=B, and express U as a product of elementary matrices.
- A=[213−112], B=[1−1−2301]
- A=[2−10111], B=[3012−10]
- U=[1110]=[1101][0110]
In each case factor A as a product of elementary matrices.
A=[1121] A=[2312] A=[102011216] A=[10−3014−2215]
-
A=[0110][1021][100−1]
[1201] -
A=[100010−201][100010021]
[10−3010001][100014001]
[ex:ex2_5_9] Let E be an elementary matrix.
- Show that ET is also elementary of the same type.
- Show that ET=E if E is of type I or II.
Show that every matrix A can be factored as A=UR where U is invertible and R is in reduced row-echelon form.
UA=R by Theorem [thm:005294], so A=U−1R.
If A=[121−3] and
B=[52−5−3] find an elementary matrix F such that AF=B.
[Hint: See Exercise [ex:ex2_5_9].]
In each case find invertible U and V such that UAV=[Ir000], where r=rankA.
A=[11−1−2−24] A=[3221] A=[1−1212−10301−41] A=[110−132111013]
- U=A−1, V=I2; rankA=2
-
U=[−2103−102−11],
V=[10−1−3011400100001]; rankA=2
Prove Lemma [lem:005213] for elementary matrices of:
type I; type II.
While trying to invert A, [AI] is carried to [PQ] by row operations. Show that P=QA.
If A and B are n×n matrices and AB is a product of elementary matrices, show that the same is true of A.
If U is invertible, show that the reduced row-echelon form of a matrix [UA] is [IU−1A].
Write U−1=EkEk−1⋯E2E1, Ei elementary. Then [IU−1A]=[U−1UU−1A]
=U−1[UA]=EkEk−1⋯E2E1[UA]. So [UA]→[IU−1A] by row operations
(Lemma [lem:005213]).
[ex:ex2_5_17] Two matrices A and B are called row-equivalent (written Ar∼B) if there is a sequence of elementary row operations carrying A to B.
- Show that Ar∼B if and only if A=UB for some invertible matrix U.
- Show that:
- Ar∼A for all matrices A.
- If Ar∼B, then Br∼A
- If Ar∼B and Br∼C, then Ar∼C.
- Show that, if A and B are both row-equivalent to some third matrix, then Ar∼B.
-
Show that [1−13201411086] and
[1−145−21−11−8−1222] are row-equivalent. [Hint: Consider (c) and Theorem [thm:001017].]
- (i) Ar∼A because A=IA. (ii) If Ar∼B, then A=UB, U invertible, so B=U−1A. Thus Br∼A. (iii) If Ar∼B and Br∼C, then A=UB and B=VC, U and V invertible. Hence A=U(VC)=(UV)C, so Ar∼C.
If U and V are invertible n×n matrices, show that Ur∼V. (See Exercise [ex:ex2_5_17].)
(See Exercise [ex:ex2_5_17].) Find all matrices that are row-equivalent to:
[000000] [000001] [100010] [120001]
- If Br∼A, let B=UA, U invertible. If U=[db−bd], B=UA=[00b00d] where b and d are not both zero (as U is invertible). Every such matrix B arises in this way: Use U=[ab−ba]–it is invertible by Example [exa:003540].
Let A and B be m×n and n×m matrices, respectively. If m>n, show that AB is not invertible. [Hint: Use Theorem [thm:001473] to find x≠0 with Bx=0.]
Define an elementary column operation on a matrix to be one of the following: (I) Interchange two columns. (II) Multiply a column by a nonzero scalar. (III) Add a multiple of a column to another column. Show that:
- If an elementary column operation is done to an m×n matrix A, the result is AF, where F is an n×n elementary matrix.
- Given any m×n matrix A, there exist m×m elementary matrices E1,…,Ek and n×n elementary matrices F1,…,Fp such that, in block form,
Ek⋯E1AF1⋯Fp=[Ir000]
Suppose B is obtained from A by:
- interchanging rows i and j;
- multiplying row i by k≠0;
- adding k times row i to row j (i≠j).
In each case describe how to obtain B−1 from A−1. [Hint: See part (a) of the preceding exercise.]
- Multiply column i by 1/k.
Two m×n matrices A and B are called equivalent (written Ae∼B) if there exist invertible matrices U and V (sizes m×m and n×n) such that A=UBV.
- Prove the following the properties of equivalence.
- Ae∼A for all m×n matrices A.
- If Ae∼B, then Be∼A.
- If Ae∼B and Be∼C, then Ae∼C.
- Prove that two m×n matrices are equivalent if they have the same rank. [Hint: Use part (a) and Theorem [thm:005369].]