2.1E: Elementary Matrices Exercises
- Page ID
- 132800
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solutions
2
For each of the following elementary matrices, describe the corresponding elementary row operation and write the inverse.
\(E = \left[ \begin{array}{rrr} 1 & 0 & 3 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right]\) \(E = \left[ \begin{array}{rrr} 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \end{array} \right]\) \(E = \left[ \begin{array}{rrr} 1 & 0 & 0 \\ 0 & \frac{1}{2} & 0 \\ 0 & 0 & 1 \end{array} \right]\) \(E = \left[ \begin{array}{rrr} 1 & 0 & 0 \\ -2 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right]\) \(E = \left[ \begin{array}{rrr} 0 & 1 & 0 \\ 1 & 0 & 0 \\ 0 & 0 & 1 \end{array} \right]\) \(E = \left[ \begin{array}{rrr} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 5 \end{array} \right]\)
- Interchange rows 1 and 3 of \(I\). \(E^{-1} = E\).
- Add \((-2)\) times row 1 of \(I\) to row 2. \(E^{-1} = \left[ \begin{array}{rrr} 1 & 0 & 0 \\ 2 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right]\)
- Multiply row 3 of \(I\) by \(5\). \(E^{-1} = \left[ \begin{array}{rrr} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & \frac{1}{5} \end{array} \right]\)
In each case find an elementary matrix \(E\) such that \(B = EA\).
- \(A = \left[ \begin{array}{rr} 2 & 1 \\ 3 & -1 \end{array} \right]\), \(B = \left[ \begin{array}{rr} 2 & 1 \\ 1 & -2 \end{array} \right]\)
- \(A = \left[ \begin{array}{rr} -1 & 2 \\ 0 & 1 \end{array} \right]\), \(B = \left[ \begin{array}{rr} 1 & -2 \\ 0 & 1 \end{array} \right]\)
- \(A = \left[ \begin{array}{rr} 1 & 1 \\ -1 & 2 \end{array} \right]\), \(B = \left[ \begin{array}{rr} -1 & 2 \\ 1 & 1 \end{array} \right]\)
- \(A = \left[ \begin{array}{rr} 4 & 1 \\ 3 & 2 \end{array} \right]\), \(B = \left[ \begin{array}{rr} 1 & -1 \\ 3 & 2 \end{array} \right]\)
- \(A = \left[ \begin{array}{rr} -1 & 1 \\ 1 & -1 \end{array} \right]\), \(B = \left[ \begin{array}{rr} -1 & 1 \\ -1 & 1 \end{array} \right]\)
- \(A = \left[ \begin{array}{rr} 2 & 1 \\ -1 & 3 \end{array} \right]\), \(B = \left[ \begin{array}{rr} -1 & 3 \\ 2 & 1 \end{array} \right]\)
- \(\left[ \begin{array}{rr} -1 & 0 \\ 0 & 1 \end{array} \right]\)
- \(\left[ \begin{array}{rr} 1 & -1 \\ 0 & 1 \end{array} \right]\)
- \(\left[ \begin{array}{rr} 0 & 1 \\ 1 & 0 \end{array} \right]\)
Let \(A = \left[ \begin{array}{rr} 1 & 2 \\ -1 & 1 \end{array} \right]\) and
\(C = \left[ \begin{array}{rr} -1 & 1 \\ 2 & 1 \end{array} \right]\).
- Find elementary matrices \(E_{1}\) and \(E_{2}\) such that \(C = E_{2}E_{1}A\).
- Show that there is no elementary matrix \(E\) such that \(C = EA\).
- The only possibilities for \(E\) are \(\left[ \begin{array}{rr} 0 & 1 \\ 1 & 0 \end{array} \right]\), \(\left[ \begin{array}{rr} k & 0 \\ 0 & 1 \end{array} \right]\), \(\left[ \begin{array}{rr} 1 & 0 \\ 0 & k \end{array} \right]\), \(\left[ \begin{array}{rr} 1 & k \\ 0 & 1 \end{array} \right]\), and \(\left[ \begin{array}{rr} 1 & 0 \\ k & 1 \end{array} \right]\). In each case, \(EA\) has a row different from \(C\).
If \(E\) is elementary, show that \(A\) and \(EA\) differ in at most two rows.
- Is \(I\) an elementary matrix? Explain.
- Is \(0\) an elementary matrix? Explain.
- No, \(0\) is not invertible.
In each case find an invertible matrix \(U\) such that \(UA = R\) is in reduced row-echelon form, and express \(U\) as a product of elementary matrices.
\(A = \left[ \begin{array}{rrr} 1 & -1 & 2 \\ -2 & 1 & 0 \end{array} \right]\) \(A = \left[ \begin{array}{rrr} 1 & 2 & 1 \\ 5 & 12 & -1 \end{array} \right]\) \(A = \left[ \begin{array}{rrrr} 1 & 2 & -1 & 0 \\ 3 & 1 & 1 & 2 \\ 1 & -3 & 3 & 2 \end{array} \right]\) \(A = \left[ \begin{array}{rrrr} 2 & 1 & -1 & 0 \\ 3 & -1 & 2 & 1 \\ 1 & -2 & 3 & 1 \end{array} \right]\)
-
\(\left[ \begin{array}{rr} 1 & -2 \\ 0 & 1 \end{array} \right] \left[ \begin{array}{rr} 1 & 0 \\ 0 & \frac{1}{2} \end{array} \right] \left[ \begin{array}{rr} 1 & 0 \\ -5 & 1 \end{array} \right]\)
\(A = \left[ \begin{array}{rrr} 1 & 0 & 7 \\ 0 & 1 & -3 \end{array} \right]\). Alternatively,
\(\left[ \begin{array}{rr} 1 & 0 \\ 0 & \frac{1}{2} \end{array} \right] \left[ \begin{array}{rr} 1 & -1 \\ 0 & 1 \end{array} \right] \left[ \begin{array}{rr} 1 & 0 \\ -5 & 1 \end{array} \right]\)
\(A = \left[ \begin{array}{rrr} 1 & 0 & 7 \\ 0 & 1 & -3 \end{array} \right]\). -
\(\left[ \begin{array}{rrr} 1 & 2 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right] \left[ \begin{array}{rrr} 1 & 0 & 0 \\ 0 & \frac{1}{5} & 0 \\ 0 & 0 & 1 \end{array} \right] \left[ \begin{array}{rrr} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & -1 & 1 \end{array} \right]\)
\(\left[ \begin{array}{rrr} 1 & 0 & 0 \\ 0 & 1 & 0 \\ -2 & 0 & 1 \end{array} \right] \left[ \begin{array}{rrr} 1 & 0 & 0 \\ -3 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right]\)\(\left[ \begin{array}{rrr} 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \end{array} \right] A = \left[ \def\arraystretch{1.5}\begin{array}{rrrr} 1 & 0 & \frac{1}{5} & \frac{1}{5} \\ 0 & 1 & -\frac{7}{5} & -\frac{2}{5} \\ 0 & 0 & 0 & 0 \end{array} \right]\)
In each case find an invertible matrix \(U\) such that \(UA = B\), and express \(U\) as a product of elementary matrices.
- \(A = \left[ \begin{array}{rrr} 2 & 1 & 3 \\ -1 & 1 & 2 \end{array} \right]\), \(B = \left[ \begin{array}{rrr} 1 & -1 & -2 \\ 3 & 0 & 1 \end{array} \right]\)
- \(A = \left[ \begin{array}{rrr} 2 & -1 & 0 \\ 1 & 1 & 1 \end{array} \right]\), \(B = \left[ \begin{array}{rrr} 3 & 0 & 1 \\ 2 & -1 & 0 \end{array} \right]\)
- \(U = \left[ \begin{array}{rr} 1 & 1 \\ 1 & 0 \end{array} \right] = \left[ \begin{array}{rr} 1 & 1 \\ 0 & 1 \end{array} \right] \left[ \begin{array}{rr} 0 & 1 \\ 1 & 0 \end{array} \right]\)
In each case factor \(A\) as a product of elementary matrices.
\(A = \left[ \begin{array}{rr} 1 & 1 \\ 2 & 1 \end{array} \right]\) \(A = \left[ \begin{array}{rr} 2 & 3 \\ 1 & 2 \end{array} \right]\) \(A = \left[ \begin{array}{rrr} 1 & 0 & 2 \\ 0 & 1 & 1 \\ 2 & 1 & 6 \end{array} \right]\) \(A = \left[ \begin{array}{rrr} 1 & 0 & -3 \\ 0 & 1 & 4 \\ -2 & 2 & 15 \end{array} \right]\)
-
\(A = \left[ \begin{array}{rr} 0 & 1 \\ 1 & 0 \end{array} \right] \left[ \begin{array}{rr} 1 & 0 \\ 2 & 1 \end{array} \right] \left[ \begin{array}{rr} 1 & 0 \\ 0 & -1 \end{array} \right]\)
\(\left[ \begin{array}{rr} 1 & 2 \\ 0 & 1 \end{array} \right]\) -
\(A = \left[ \begin{array}{rrr} 1 & 0 & 0 \\ 0 & 1 & 0 \\ -2 & 0 & 1 \end{array} \right] \left[ \begin{array}{rrr} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 2 & 1 \end{array} \right]\)
\(\left[ \begin{array}{rrr} 1 & 0 & -3 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right] \left[ \begin{array}{rrr} 1 & 0 & 0 \\ 0 & 1 & 4 \\ 0 & 0 & 1 \end{array} \right]\)
[ex:ex2_5_9] Let \(E\) be an elementary matrix.
- Show that \(E^{T}\) is also elementary of the same type.
- Show that \(E^{T} = E\) if \(E\) is of type I or II.
Show that every matrix \(A\) can be factored as \(A = UR\) where \(U\) is invertible and \(R\) is in reduced row-echelon form.
\(UA = R\) by Theorem [thm:005294], so \(A = U^{-1}R\).
If \(A = \left[ \begin{array}{rr} 1 & 2 \\ 1 & -3 \end{array} \right]\) and
\(B = \left[ \begin{array}{rr} 5 & 2 \\ -5 & -3 \end{array} \right]\) find an elementary matrix \(F\) such that \(AF = B\).
[Hint: See Exercise [ex:ex2_5_9].]
In each case find invertible \(U\) and \(V\) such that \(UAV = \left[ \begin{array}{cc} I_{r} & 0 \\ 0 & 0 \end{array} \right]\), where \(r = rank \;A\).
\(A = \left[ \begin{array}{rrr} 1 & 1 & -1 \\ -2 & -2 & 4 \end{array} \right]\) \(A = \left[ \begin{array}{rr} 3 & 2 \\ 2 & 1 \end{array} \right]\) \(A = \left[ \begin{array}{rrrr} 1 & -1 & 2 & 1 \\ 2 & -1 & 0 & 3 \\ 0 & 1 & -4 & 1 \end{array} \right]\) \(A = \left[ \begin{array}{rrrr} 1 & 1 & 0 & -1 \\ 3 & 2 & 1 & 1 \\ 1 & 0 & 1 & 3 \end{array} \right]\)
- \(U = A^{-1}\), \(V = I^{2}\); \(rank \;A = 2\)
-
\(U = \left[ \begin{array}{rrr} -2 & 1 & 0 \\ 3 & -1 & 0 \\ 2 & -1 & 1 \end{array} \right]\),
\(V = \left[ \begin{array}{rrrr} 1 & 0 & -1 & -3 \\ 0 & 1 & 1 & 4 \\ 0 & 0 & 1 & 0 \\ 0 & 0 & 0 & 1 \end{array} \right]\); \(rank \;A = 2\)
Prove Lemma [lem:005213] for elementary matrices of:
type I; type II.
While trying to invert \(A\), \(\left[ \begin{array}{cc} A & I \end{array} \right]\) is carried to \(\left[ \begin{array}{cc} P & Q \end{array} \right]\) by row operations. Show that \(P = QA\).
If \(A\) and \(B\) are \(n \times n\) matrices and \(AB\) is a product of elementary matrices, show that the same is true of \(A\).
If \(U\) is invertible, show that the reduced row-echelon form of a matrix \(\left[ \begin{array}{cc} U & A \end{array} \right]\) is \(\left[ \begin{array}{cc} I & U^{-1}A \end{array} \right]\).
Write \(U^{-1} = E_{k}E_{k-1} \cdots E_{2}E_{1}\), \(E_{i}\) elementary. Then \(\left[ \begin{array}{cc} I & U^{-1}A \end{array} \right] = \left[ \begin{array}{cc} U^{-1}U & U^{-1}A \end{array} \right]\)
\(= U^{-1} \left[ \begin{array}{cc} U & A \end{array} \right] = E_{k}E_{k-1} \cdots E_{2}E_{1} \left[ \begin{array}{cc} U & A \end{array} \right]\). So \(\left[ \begin{array}{cc} U & A \end{array} \right] \rightarrow \left[ \begin{array}{cc} I & U^{-1}A \end{array} \right]\) by row operations
(Lemma [lem:005213]).
[ex:ex2_5_17] Two matrices \(A\) and \(B\) are called row-equivalent (written \(A \overset{r}{\sim} B\)) if there is a sequence of elementary row operations carrying \(A\) to \(B\).
- Show that \(A \overset{r}{\sim} B\) if and only if \(A = UB\) for some invertible matrix \(U\).
- Show that:
- \(A \overset{r}{\sim} A\) for all matrices \(A\).
- If \(A \overset{r}{\sim} B\), then \(B \overset{r}{\sim} A\)
- If \(A \overset{r}{\sim} B\) and \(B \overset{r}{\sim} C\), then \(A \overset{r}{\sim} C\).
- Show that, if \(A\) and \(B\) are both row-equivalent to some third matrix, then \(A \overset{r}{\sim} B\).
-
Show that \(\left[ \begin{array}{rrrr} 1 & -1 & 3 & 2 \\ 0 & 1 & 4 & 1 \\ 1 & 0 & 8 & 6 \end{array} \right]\) and
\(\left[ \begin{array}{rrrr} 1 & -1 & 4 & 5 \\ -2 & 1 & -11 & -8 \\ -1 & 2 & 2 & 2 \end{array} \right]\) are row-equivalent. [Hint: Consider (c) and Theorem [thm:001017].]
- (i) \(A \overset{r}{\sim} A\) because \(A = IA\). (ii) If \(A \overset{r}{\sim} B\), then \(A = UB\), \(U\) invertible, so \(B = U^{-1}A\). Thus \(B \overset{r}{\sim} A\). (iii) If \(A \overset{r}{\sim} B\) and \(B \overset{r}{\sim} C\), then \(A = UB\) and \(B = VC\), \(U\) and \(V\) invertible. Hence \(A = U(VC) = (UV)C\), so \(A \overset{r}{\sim} C\).
If \(U\) and \(V\) are invertible \(n \times n\) matrices, show that \(U \overset{r}{\sim} V\). (See Exercise [ex:ex2_5_17].)
(See Exercise [ex:ex2_5_17].) Find all matrices that are row-equivalent to:
\(\left[ \begin{array}{rrr} 0 & 0 & 0 \\ 0 & 0 & 0 \end{array} \right]\) \(\left[ \begin{array}{rrr} 0 & 0 & 0 \\ 0 & 0 & 1 \end{array} \right]\) \(\left[ \begin{array}{rrr} 1 & 0 & 0 \\ 0 & 1 & 0 \end{array} \right]\) \(\left[ \begin{array}{rrr} 1 & 2 & 0 \\ 0 & 0 & 1 \end{array} \right]\)
- If \(B \overset{r}{\sim} A\), let \(B = UA\), \(U\) invertible. If \(U = \left[ \begin{array}{rr} d & b \\ -b & d \end{array} \right]\), \(B = UA = \left[ \begin{array}{ccc} 0 & 0 & b \\ 0 & 0 & d \end{array} \right]\) where \(b\) and \(d\) are not both zero (as \(U\) is invertible). Every such matrix \(B\) arises in this way: Use \(U = \left[ \begin{array}{rr} a & b \\ -b & a \end{array} \right]\)–it is invertible by Example [exa:003540].
Let \(A\) and \(B\) be \(m \times n\) and \(n \times m\) matrices, respectively. If \(m > n\), show that \(AB\) is not invertible. [Hint: Use Theorem [thm:001473] to find \(\mathbf{x} \neq \mathbf{0}\) with \(B\mathbf{x} = \mathbf{0}\).]
Define an elementary column operation on a matrix to be one of the following: (I) Interchange two columns. (II) Multiply a column by a nonzero scalar. (III) Add a multiple of a column to another column. Show that:
- If an elementary column operation is done to an \(m \times n\) matrix \(A\), the result is \(AF\), where \(F\) is an \(n \times n\) elementary matrix.
- Given any \(m \times n\) matrix \(A\), there exist \(m \times m\) elementary matrices \(E_{1}, \dots, E_{k}\) and \(n \times n\) elementary matrices \(F_{1}, \dots, F_{p}\) such that, in block form,
\[E_{k} \cdots E_{1}AF_{1} \cdots F_{p} = \left[ \begin{array}{cc} I_{r} & 0 \\ 0 & 0 \end{array} \right] \nonumber \]
Suppose \(B\) is obtained from \(A\) by:
- interchanging rows \(i\) and \(j\);
- multiplying row \(i\) by \(k \neq 0\);
- adding \(k\) times row \(i\) to row \(j\ (i \neq j)\).
In each case describe how to obtain \(B^{-1}\) from \(A^{-1}\). [Hint: See part (a) of the preceding exercise.]
- Multiply column \(i\) by \(1/k\).
Two \(m \times n\) matrices \(A\) and \(B\) are called equivalent (written \(A \overset{e}{\sim} B\)) if there exist invertible matrices \(U\) and \(V\) (sizes \(m \times m\) and \(n \times n\)) such that \(A = UBV\).
- Prove the following the properties of equivalence.
- \(A \overset{e}{\sim} A\) for all \(m \times n\) matrices \(A\).
- If \(A \overset{e}{\sim} B\), then \(B \overset{e}{\sim} A\).
- If \(A \overset{e}{\sim} B\) and \(B \overset{e}{\sim} C\), then \(A \overset{e}{\sim} C\).
- Prove that two \(m \times n\) matrices are equivalent if they have the same \(rank \;\). [Hint: Use part (a) and Theorem [thm:005369].]