10.6: Divide Monomials (Part 1)
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- Jul 2, 2019
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Learning Objectives
- Simplify expressions using the Quotient Property of Exponents
- Simplify expressions with zero exponents
- Simplify expressions using the Quotient to a Power Property
- Simplify expressions by applying several properties
- Divide monomials
be prepared!
Before you get started, take this readiness quiz.
- Simplify: 824. If you missed the problem, review Example 4.3.1.
- Simplify:(2m3)5. If you missed the problem, review Example 10.3.13.
- Simplify: 12x12y. If you missed the problem, review Example 4.3.5.
Simplify Expressions Using the Quotient Property of Exponents
Earlier in this chapter, we developed the properties of exponents for multiplication. We summarize these properties here.
Summary of Exponent Properties for Multiplication
If a, b are real numbers and m, n are whole numbers, then
Product Property | am • an = am + n |
Power Property | (am)n = am • n |
Product to a Power | (ab)m = ambm |
Now we will look at the exponent properties for division. A quick memory refresher may help before we get started. In Fractions you learned that fractions may be simplified by dividing out common factors from the numerator and denominator using the Equivalent Fractions Property. This property will also help us work with algebraic fractions—which are also quotients.
Definition: Equivalent Fractions Property
If a, b, c are whole numbers where b ≠ 0, c ≠ 0, then
ab=a⋅cb⋅canda⋅cb⋅c=ab
As before, we'll try to discover a property by looking at some examples.
Consider | x5x2 | and | x2x3 |
What do they mean? | x⋅x⋅x⋅x⋅xx⋅x | x⋅xx⋅x⋅x | |
Use the Equivalent Fractions Property | x⋅x⋅x⋅x⋅xx⋅x⋅1 | x⋅x⋅1x⋅x⋅x | |
Simplify. | x3 | 1x |
Notice that in each case the bases were the same and we subtracted the exponents.
- When the larger exponent was in the numerator, we were left with factors in the numerator and 1 in the denominator, which we simplified.
- When the larger exponent was in the denominator, we were left with factors in the denominator, and 1 in the numerator, which could not be simplified.
We write:
x5x2x2x3x5−21x3−2x31x
Definition: Quotient Property of Exponents
If a is a real number, a ≠ 0, and m, n are whole numbers, then
aman=am−n,m>nandaman=1an−m,n>m
A couple of examples with numbers may help to verify this property.
3432?=34−25253?=153−2819?=3225125?=1519=9✓15=15✓
When we work with numbers and the exponent is less than or equal to 3, we will apply the exponent. When the exponent is greater than 3, we leave the answer in exponential form.
Example 10.6.1:
Simplify: (a) x10x8 (b) 2922
Solution
To simplify an expression with a quotient, we need to first compare the exponents in the numerator and denominator.
(a)
Since 10 > 8, there are more factors of x in the numerator. | x10x8 |
Use the quotient property with m > n, aman=am−n. | x10−8 |
Simplify. | x2 |
(b)
Since 9 > 2, there are more factors of 2 in the numerator. | 2922 |
Use the quotient property with m > n, aman=am−n. | 29−2 |
Simplify. | 27 |
Notice that when the larger exponent is in the numerator, we are left with factors in the numerator.
Exercise 10.6.1:
Simplify: (a) x12x9 (b) 71475
- Answer a
-
x3
- Answer b
-
79
Exercise 10.6.2:
Simplify: (a) y23y17 (b) 81587
- Answer a
-
y6
- Answer b
-
88
Example 10.6.2:
Simplify: (a) b10b15 (b) 3335
Solution
To simplify an expression with a quotient, we need to first compare the exponents in the numerator and denominator.
(a)
Since 15 > 10, there are more factors of b in the denominator. | b10b15 |
Use the quotient property with n > m, aman=1an−m. | 1b15−10 |
Simplify. | 1b5 |
(b)
Since 5 > 3, there are more factors of 3 in the denominator. | 3335 |
Use the quotient property with n > m, aman=1an−m. | 135−3 |
Simplify. | 132 |
Apply the exponent. | 19 |
Notice that when the larger exponent is in the denominator, we are left with factors in the denominator and 1 in the numerator.
Exercise 10.6.3:
Simplify: (a) x8x15 (b) 12111221
- Answer a
-
1x7
- Answer b
-
11210
Exercise 10.6.4:
Simplify: (a) m17m26 (b) 78714
- Answer a
-
1m9
- Answer b
-
176
Example 10.6.3:
Simplify: (a) a5a9 (b) x11x7
Solution
(a)
Since 9 > 5, there are more a's in the denominator and so we will end up with factors in the denominator. | a5a9 |
Use the quotient property with n > m, aman=1an−m. | 1a9−5 |
Simplify. | 1a4 |
(b)
Notice there are more factors of x in the numerator, since 11 > 7. So we will end up with factors in the numerator. | x11x97 |
Use the quotient property with m > n, aman=am−n. | a11−7 |
Simplify. | x4 |
Exercise 10.6.5:
Simplify: (a) b19b11 (b) z5z11
- Answer a
-
b8
- Answer b
-
1z6
Exercise 10.6.6:
Simplify: (a) p9p17 (b) w13w9
- Answer a
-
1p8
- Answer b
-
w4
Simplify Expressions with Zero Exponents
A special case of the Quotient Property is when the exponents of the numerator and denominator are equal, such as an expression like amam. From earlier work with fractions, we know that
22=11717=1−43−43=1
In words, a number divided by itself is 1. So xx = 1, for any x (x ≠ 0), since any number divided by itself is 1.
The Quotient Property of Exponents shows us how to simplify aman when m > n and when n < m by subtracting exponents. What if m = n?
Now we will simplify amam in two ways to lead us to the definition of the zero exponent. Consider first 88, which we know is 1.
88=1 | |
Write 8 as 23. | 2323=1 |
Subtract exponents. | 23−3=1 |
Simplify. | 20=1 |
We see aman simplifies to a0 and to 1. So a0 = 1.
Definition: Zero Exponent
If a is a non-zero number, then a0 = 1. Any nonzero number raised to the zero power is 1.
In this text, we assume any variable that we raise to the zero power is not zero.
Example 10.6.4:
Simplify: (a) 120 (b) y0
Solution
The definition says any non-zero number raised to the zero power is 1.
(a) 120
Use the definition of the zero exponent. | 1 |
(b) y0
Use the definition of the zero exponent. | 1 |
Exercise 10.6.7:
Simplify: (a) 170 (b) m0
- Answer a
-
1
- Answer b
-
1
Exercise 10.6.8:
Simplify: (a) k0 (b) 290
- Answer a
-
1
- Answer b
-
1
Now that we have defined the zero exponent, we can expand all the Properties of Exponents to include whole number exponents.
What about raising an expression to the zero power? Let's look at (2x)0. We can use the product to a power rule to rewrite this expression.
(2x)0 | |
Use the Product to a Power Rule. | 20x0 |
Use the Zero Exponent Property. | 1 • 1 |
Simplify. | 1 |
This tells us that any non-zero expression raised to the zero power is one.
Example 10.6.5:
Simplify: (7z)0.
Solution
Use the definition of the zero exponent. | 1 |
Exercise 10.6.9:
Simplify: (−4y)0.
- Answer
-
1
Exercise 10.6.10:
Simplify: (23x)0.
- Answer
-
1
Example 10.6.6:
Simplify: (a) (−3x2y)0 (b) −3x2y0
Solution
(a) (−3x2y)0
The product is raised to the zero power. | (−3x2y)0 |
Use the definition of the zero exponent. | 1 |
(b) −3x2y0
Notice that only the variable y is being raised to the zero power. | −3x2y0 |
Use the definition of the zero exponent. | −3x2 • 1 |
Simplify. | −3x2 |
Exercise 10.6.11:
Simplify: (a) (7x2y)0 (b) 7x2y0
- Answer a
-
1
- Answer b
-
7x2
Exercise 10.6.12:
Simplify: (a) −23x2y0 (b) (−23x2y)0
- Answer a
-
−23x2
- Answer b
-
1
Simplify Expressions Using the Quotient to a Power Property
Now we will look at an example that will lead us to the Quotient to a Power Property.
(xy)3 | |
This means | xy⋅xy⋅xy |
Multiply the fractions. | x⋅x⋅xy⋅y⋅y |
Write with exponents. | x3y3 |
Notice that the exponent applies to both the numerator and the denominator. We see that (xy)3 is x3y3. We write:
(xy)3=x3y3
This leads to the Quotient to a Power Property for Exponents.
Definition: Quotient to a Power Property of Exponents
If a and b are real numbers, b ≠ 0, and m is a counting number, then
(ab)m=ambm
To raise a fraction to a power, raise the numerator and denominator to that power.
An example with numbers may help you understand this property:
(23)3?=233323⋅23⋅23?=827827=827✓
Example 10.6.7:
Simplify: (a) (58)2 (b) (x3)4 (c) (ym)3
Solution
(a) (58)2
Use the Quotient to a Power Property, (ab)m=ambm. | 5282 |
Simplify. | 2564 |
(b) (x3)4
Use the Quotient to a Power Property, (ab)m=ambm. | x434 |
Simplify. | x481 |
(c) (ym)3
Raise the numerator and denominator to the third power. | y3m3 |
Exercise 10.6.13:
Simplify: (a) (79)2 (b) (y8)3 (c) (pq)6
- Answer a
-
4981
- Answer b
-
y3512
- Answer c
-
p6q6
Exercise 10.6.14:
Simplify: (a) (18)2 (b) (−5m)3 (c) (rs)4
- Answer a
-
164
- Answer b
-
−125m3
- Answer c
-
r4s4
Contributors and Attributions
Lynn Marecek (Santa Ana College) and MaryAnne Anthony-Smith (Formerly of Santa Ana College). This content is licensed under Creative Commons Attribution License v4.0 "Download for free at http://cnx.org/contents/fd53eae1-fa2...49835c3c@5.191."