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11.2: Defects in Voting Methods

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    Now that we have reviewed four different voting methods, how do you decide which method to use? One question to ask is which method is the fairest? Unfortunately, there is no completely fair method. What are the fairness criteria? They are guidelines that people use to help decide which voting method would be best to use under certain circumstances. They are the Majority Criterion, Condorcet Criterion, Monotonicity Criterion, and Independence of Irrelevant Alternatives Criterion.

    The Majority Criterion

    If a candidate receives a majority of the 1st-place votes in an election, then that candidate should be the winner of the election.

    Example 1: Majority Criterion Violated

    Suppose a group is planning to have a conference in one of four Arizona cities: Flagstaff, Phoenix, Tucson, or Yuma. The votes for where to hold the conference are summarized in the preference schedule shown below in Table \(\PageIndex{1}\).

    Table \(\PageIndex{1}\): Preference Schedule for Conference City

    Number of voters

    51

    25

    10

    14

    1st choice

    Flagstaff

    Phoenix

    Yuma

    Tucson

    2nd choice

    Phoenix

    Yuma

    Phoenix

    Phoenix

    3rd choice

    Tucson

    Tucson

    Tucson

    Yuma

    4th choice

    Yuma

    Flagstaff

    Flagstaff

    Flagstaff

    Solution

    If we use the Borda Count Method to determine the winner then the number of Borda points that each candidate receives are shown in Table \(\PageIndex{2}\).

    Table \(\PageIndex{2}\): Preference Schedule for Conference City with Borda Points

    Number of voters

    51

    25

    10

    14

    1st choice

    4 points

    Flagstaff

    204

    Phoenix

    100

    Yuma

    40

    Tucson

    56

    2nd choice

    3 points

    Phoenix

    153

    Yuma

    75

    Phoenix

    30

    Phoenix

    42

    3rd choice

    2 points

    Tucson

    102

    Tucson

    50

    Tucson

    20

    Yuma

    28

    4th choice

    1 point

    Yuma

    51

    Flagstaff

    25

    Flagstaff

    10

    Flagstaff

    14

    The totals of all the Borda points for each city are:

    Phoenix:

    Yuma:

    Tucson:

    Phoenix wins using the Borda Count Method. However, notice that Flagstaff actually has the majority of first-place votes. There are 100 voters total and 51 voters voted for Flagstaff in first place (51/100 = 51% or a majority of the first-place votes). So, Flagstaff should have won based on the Majority Criterion. This shows how the Borda Count Method can violate the Majority Criterion.

    The Condorcet Criterion

    If there is a candidate that in a head-to-head comparison is preferred by the voters over every other candidate, then that candidate should be the winner of the election. This candidate is known as the Condorcet candidate.

    Example 2: The Condorcet Criterion Violated

    Suppose you have a vacation club trying to figure out where it wants to spend next year’s vacation. The choices are Hawaii (H), Anaheim (A), or Orlando (O). The preference schedule for this election is shown below in Table \(\PageIndex{3}\).

    Table \(\PageIndex{3}\): Preference Schedule of Vacation Election

    Number of voters

    1

    3

    3

    3

    1st choice

    A

    A

    O

    H

    2nd choice

    O

    H

    H

    A

    3rd choice

    H

    O

    A

    O

    Solution

    Using the Plurality Method, A has four first-place votes, O has three first-place votes, and H has three first-place votes. So, Anaheim is the winner. However, if you use the Method of Pairwise Comparisons, A beats O (A has seven while O has three), H beats A (H has six while A has four), and H beats O (H has six while O has four). Thus, Hawaii wins all pairwise comparisons against the other candidates, and would win the election. In fact Hawaii is the Condorcet candidate. However, the Plurality Method declared Anaheim the winner, so the Plurality Method violated the Condorcet Criterion.

    The Monotonicity Criterion

    If candidate X is a winner of an election and, in a re-election, the only changes in the ballots are changes that favor X, then X should remain a winner of the election.

    Example 3: Monotonicity Criterion Violated

    Suppose you have a voting system for a mayor. The resulting preference schedule for this election is shown below in Table \(\PageIndex{4}\).

    Table \(\PageIndex{4}\): Preference Schedule of Mayoral Election

    Number of voters

    37

    22

    12

    29

    1st choice

    Adams

    Brown

    Brown

    Carter

    2nd choice

    Brown

    Carter

    Adams

    Adams

    3rd choice

    Carter

    Adams

    Carter

    Brown

    Solution

    Using the Plurality with Elimination Method, Adams has 37 first-place votes, Brown has 34, and Carter has 29, so Carter would be eliminated. Carter’s votes go to Adams, and Adams wins. Suppose that the results were announced, but then the election officials accidentally destroyed the ballots before they could be certified, so the election must be held again. Wanting to “jump on the bandwagon,” 10 of the voters who had originally voted in the order Brown, Adams, Carter; change their vote to the order of Adams, Brown, Carter. No other voting changes are made. Thus, the only voting changes are in favor of Adams. The new preference schedule is shown below in Table \(\PageIndex{5}\).

    Table \(\PageIndex{5}\): Preference Schedule of Mayoral Re-election

    Number of voters

    47

    22

    2

    29

    1st choice

    Adams

    Brown

    Brown

    Carter

    2nd choice

    Brown

    Carter

    Adams

    Adams

    3rd choice

    Carter

    Adams

    Carter

    Brown

    Now using the Plurality with Elimination Method, Adams has 47 first-place votes, Brown has 24, and Carter has 29. This time, Brown is eliminated first instead of Carter. Two of Brown’s votes go to Adams and 22 of Brown’s votes go to Carter. Now, Adams has 47 + 2 = 49 votes and Carter has 29 + 22 = 51 votes. Carter wins the election. This doesn’t make sense since Adams had won the election before, and the only changes that were made to the ballots were in favor of Adams. However, Adams doesn’t win the re-election. The reason that this happened is that there was a difference in who was eliminated first, and that caused a difference in how the votes are re-distributed. In this example, the Plurality with Elimination Method violates the Monotonicity Criterion.

    The Independence of Irrelevant Alternatives Criterion

    If candidate X is a winner of an election and one (or more) of the other candidates is removed and the ballots recounted, then X should still be a winner of the election.

    Example 4: The Independence of Irrelevant Alternatives Criterion Violated

    A committee is trying to award a scholarship to one of four students: Anna (A), Brian (B), Carlos (C), and Dmitri (D). The votes are shown below.

    Table \(\PageIndex{6}\): Preference Schedule for Scholarship

    Number of voters

    5

    5

    6

    4

    1st choice

    D

    A

    C

    B

    2nd choice

    A

    C

    B

    D

    3rd choice

    C

    B

    D

    A

    4th choice

    B

    D

    A

    C

    Solution

    Using the Method of Pairwise Comparisons:

    A vs B: 10 votes to 10 votes, A gets ½ point and B gets ½ point

    A vs C: 14 votes to 6 votes, A gets 1 point

    A vs D: 5 votes to 15 votes, D gets 1 point

    B vs C: 4 votes to 16 votes, C gets 1 point

    B vs D: 15 votes to 5 votes, B gets 1 point

    C vs D: 11 votes to 9 votes, C gets 1 point

    So A has 1½ points, B has 1 point, C has 2 points, and D has 1 point. So Carlos is awarded the scholarship.

    Now suppose it turns out that Dmitri didn’t qualify for the scholarship after all. Though it should make no difference, the committee decides to recount the vote. The preference schedule without Dmitri is below.

    Table \(\PageIndex{7}\): Preference Schedule for Scholarship with Dmitri Removed

    Number of voters

    10

    6

    4

    1st choice

    A

    C

    B

    2nd choice

    C

    B

    A

    3rd choice

    B

    A

    C

    Using the Method of Pairwise Comparisons:

    A vs B: 10 votes to 10 votes, A gets ½ point and B gets ½ point

    A vs C: 14 votes to 6 votes, A gets 1 point

    B vs C: 4 votes to 16 votes, C gets 1 point

    So A has 1½ points, B has ½ point, and C has 1 point. Now Anna is awarded the scholarship instead of Carlos. This is an example of The Method of Pairwise Comparisons violating the Independence of Irrelevant Alternatives Criterion.

    Arrow's Impossibility Theorem

    No voting system can satisfy all four fairness criteria in all cases.

    In summary, every one of the fairness criteria can possibly be violated by at least one of the voting methods as shown in Table \(\PageIndex{8}\). However, keep in mind that this does not mean that the voting method in question will violate a criterion in every election. It is just important to know that these violations are possible.

    Table \(\PageIndex{8}\): Summary of Violations of Fairness Criteria

    Plurality

    Borda Count

    Plurality with Elimination

    Pairwise Comparisons

    Majority Criterion

    *

    Violation Possible

    *

    *

    Condorcet Criterion

    Violation Possible

    Violation Possible

    Violation Possible

    *

    Monotonicity Criterion

    *

    *

    Violation Possible

    *

    Independence of Irrelevant Alternatives Criterion

    Violation Possible

    Violation Possible

    Violation Possible

    Violation Possible

    * The indicated voting method does not violate the indicated criterion in any election.


    11.2: Defects in Voting Methods is shared under a not declared license and was authored, remixed, and/or curated by LibreTexts.

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