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4.3E: Exercises

This page is a draft and is under active development. 

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Exercise 4.3E.1

1. A fundamental calculus technique is to use ________ to refine approximations to get an exact answer.

2. What is the upper bound in the summation 14i=7(48i201)?

3. This section approximates definite integrals using what geometric shape?

4. T/F: A sum using the Right Hand Rule is an example of a Riemann Sum.

Answer

Under Construction

Exercise 4.3E.2

Write out each term of the summation and compute the sum.

1. 4i=2i2

2. 3i=1(4i2)

3. 2i=2sin(πi/2)

4. 5i=11i

5. 6i=1(1)ii

6. 4i=1(1i1i+1)

7. 5i=0(1)icos(πi)

Answer

Under Construction

Exercise 4.3E.3

Write each sum in summation notation.

1. 3+6+9+12+15

2. 1+0+3+8+15+24+35+48+63

3. 12+23+34+45

4. 1e+e2e3+e4

Answer

Under Construction

Exercise 4.3E.4

Evaluate the summation using Theorem 37.

1. 2i=15i

2. 1i=10(3i22i)

3. 1i=15(2i310)

4. 1i=10(4i3+10i27i+11)

5. 1i=10(i33t2+2i+7)

6. 1+2+3+...+99+100

7. 1+4+9+...+361+400

Answer

Under Construction

Exercise 4.3E.5

Theorem 37 states:

ni=1ai=+i=1kai+ni=k+1ai, so

ni=k+1ai=ni=1aiki=1ai.

Use this fact, along with other parts of Theorem 37, to evaluate the summations given

1. 2i=110i

2. 2i=165i3

3. 1i=724

4. 1i=504i3

Answer

Under Construction

Exercise 4.3E.6

A definite integral baf(x)dx is given.
(a) Graph f(x) on [a,b].
(b) Add to the sketch rectangles using the provided rule.
(c) Approximate baf(x)dx by summing the areas of the rectangles.

1. 33x2dx, with 6 rectangles using the Left Hand Rule.

2. 20(5x2)dx, with 4 rectangles using the Midpoint Rule.

3. π0sinxdx, with 6 rectangles using the Right Hand Rule.

4. 302xdx, with 5 rectangles using the Left Hand Rule.

5. 21lnxdx, with 3 rectangles using the Midpoint Rule.

6. 911xdx, with 4 rectangles using the Right Hand Rule.

Answer

Under Construction

Exercise 4.3E.7

A definite integral baf(x)dx is given.
(a) Find a formula to approximate baf(x)dx using n subintervals and the provided rule.
(b) Evaluate the formula using n=10,100 and 1000.
(c) Find the limit of the formula, as n, to find the exact value of baf(x)dx.

1. 10x3dx, using the Right Hand Rule.

2. 113x2dx, using the Left Hand Rule.

3. 31(3x1)dx, using the Midpoint Rule.

4. 41(2x23)dx, using the Left Hand Rule.

5. 1010(5x)dx, using the Right Hand Rule.

6. 10(x3x2)dx, using the Right Hand Rule.

Answer

Under Construction

Exercise 4.3E.8

Find an antiderivative of the given function.

1. f(x)=5sec2x

2. f(x)=7x

3. g(t)=4t55t3+8

4. g(t)=58t

5. g(t)=cost+sint

6. f(x)=1x

Answer

Under Construction

Exercise 4.3E.9

State whether the given sums are equal or unequal.

1. 10i=1i and 10k=1k

Answer

They are equal; both represent the sum of the first 10 whole numbers

2. 10i=1i and 15i=6(i5)

Answer

They are equal; both represent the sum of the first 10 whole numbers

3. 10i=1i(i1) and 9j=0(j+1)j

Answer

They are equal by substituting j=i1.

4. 10i=1i(i1) and 10k=1(k2k)

Answer

They are equal; the first sum factors the terms of the second.

Exercise 4.3E.10

In the following exercises, use the rules for sums of powers of integers to compute the sums.

1. 10i=5i

2. 10i=5i2

Answer

38530=355

Exercise 4.3E.11

Suppose that 100i=1ai=15 and 100i=1bi=12.

In the following exercises, compute the sums.

1. 100i=1(ai+bi)

2. 100i=1(aibi)

Answer

15(12)=27

3. 100i=1(3ai4bi)

4. 100i=1(5ai+4bi)

Answer

5(15)+4(12)=27

Exercise 4.3E.12

In the following exercises, use summation properties and formulas to rewrite and evaluate the sums.

1. 20k=1100(k25k+1)

2. 50j=1(j22j)

Answer

50j=1j

3. 20j=11(j210j)

4. 25k=1[(2k)2100k]

Answer

425k=1k210025k=1k=4(25)(26)(51)950(25)(26)=10,400

Exercise 4.3E.13

Let Ln denote the left-endpoint sum using n subintervals and let Rn denote the corresponding right-endpoint sum.

In the following exercises, compute the indicated left and right sums for the given functions on the indicated interval.

1. L4 for f(x)=1x1 on [2,3]

2. R4 for g(x)=cos(πx) on [0,1]

Answer

R4=0.25

3. L6 for f(x)=1x(x1) on [2,5]

4. R6 for f(x)=1x(x1) on [2,5]

Answer

R6=0.372

5. R4 for 1x2+1 on [2,2]

6. L4 for 1x2+1 on [2,2]

Answer

L4=2.20

7. R4 for x22x+1 on [0,2]

8. L8 for x22x+1 on [0,2]

Answer

L8=0.6875

Exercise 4.3E.14

1. Compute the left and right Riemann sums— L4 and R4, respectively—for f(x)=(2|x|) on [2,2]. Compute their average value and compare it with the area under the graph of f.

2. Compute the left and right Riemann sums— L6 and R6, respectively—for f(x)=(3|3x|) on [0,6]. Compute their average value and compare it with the area under the graph of f.

Answer

L6=9.000=R6. The graph of f is a triangle with area 9.

3. Compute the left and right Riemann sums— L4 and R4, respectively—for f(x)=4x2 on [2,2] and compare their values.

4. Compute the left and right Riemann sums— L6 and R6, respectively—for f(x)=9(x3)2 on [0,6] and compare their values.

Answer

L6=13.12899=R6. They are equal.

Exercise 4.3E.15

Express the following endpoint sums in sigma notation but do not evaluate them.

1. L30 for f(x)=x2 on [1,2]

2. L10 for f(x)=4x2 on [2,2]

Answer

L10=41010i=14(2+4(i1)10)

3. R20 for f(x)=sinx on [0,π]

4. R100 for lnx on [1,e]

Answer

R100=e1100100i=1ln(1+(e1)i100)

Exercise 4.3E.16

In the following exercises, graph the function then use a calculator or a computer program to evaluate the following left and right endpoint sums. Is the area under the curve between the left and right endpoint sums?

1. L100 and R100 for y=x23x+1 on the interval [1,1]

2. L100 and R100 for y=x2 on the interval [0,1]

Answer

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R100=0.33835,L100=0.32835. The plot shows that the left Riemann sum is an underestimate because the function is increasing. Similarly, the right Riemann sum is an overestimate. The area lies between the left and right Riemann sums. Ten rectangles are shown for visual clarity. This behavior persists for more rectangles.

3. L50 and R50 for y=x+1x21 on the interval [2,4]

4. L100 and R100 for y=x3 on the interval [1,1]

Answer

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L100=0.02,R100=0.02. The left endpoint sum is an underestimate because the function is increasing. Similarly, a right endpoint approximation is an overestimate. The area lies between the left and right endpoint estimates.

5. L50 and R50 for y=tan(x) on the interval [0,π4]

6. L100 and R100 for y=e2x on the interval [1,1]

Answer

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L100=3.555,R100=3.670. The plot shows that the left Riemann sum is an underestimate because the function is increasing. Ten rectangles are shown for visual clarity. This behavior persists for more rectangles.

Exercise 4.3E.17

1. Let tj denote the time that it took Tejay van Garteren to ride the jth stage of the Tour de France in 2014. If there were a total of 21 stages, interpret 21j=1tj.

2. Let rj denote the total rainfall in Portland on the jth day of the year in 2009. Interpret 31j=1rj.

Answer

The sum represents the cumulative rainfall in January 2009.

3. Let dj denote the hours of daylight and δj denote the increase in the hours of daylight from day j1 to day j in Fargo, North Dakota, on thejth day of the year. Interpret d1+365j=2δj.

4. To help get in shape, Joe gets a new pair of running shoes. If Joe runs 1 mi each day in week 1 and adds 110 mi to his daily routine each week, what is the total mileage on Joe’s shoes after 25 weeks?

Answer

The total mileage is 7×25i=1(1+(i1)10)=7×25+710×12×25=385mi.

Exercise 4.3E.18

1. The following table gives approximate values of the average annual atmospheric rate of increase in carbon dioxide (CO2) each decade since 1960, in parts per million (ppm). Estimate the total increase in atmospheric CO2 between 1964 and 2013.

Decade Ppm/y
1964-1973 1.07
1976-1983 1.34
1984-1993 1.40
1994-2003 1.87
2004-2013 2.07

Average Annual Atmospheric CO2 Increase, 1964–2013 Source: http://www.esrl.noaa.gov/gmd/ccgg/trends/.

2. The following table gives the approximate increase in sea level in inches over 20 years starting in the given year. Estimate the net change in mean sea level from 1870 to 2010.

Starting Year 20- Year Change
1870 0.3
1890 1.5
1910 0.2
1930 2.8
1950 0.7
1970 1.1
1990 1.5

Approximate 20-Year Sea Level Increases, 1870–1990

Source: http://link.springer.com/article/10....712-011-9119-1

Answer

Add the numbers to get 8.1-in. net increase.

3. The following table gives the approximate increase in dollars in the average price of a gallon of gas per decade since 1950. If the average price of a gallon of gas in 2010 was $2.60, what was the average price of a gallon of gas in 1950?

Starting Year 10- Year Change
1950 0.03
1960 0.05
1970 0.86
1980 −0.03
1990 0.29
2000 1.12

Approximate 10-Year Gas Price Increases, 1950–2000

Source: epb.lbl.gov/homepages/Rick_Di...011-trends.pdf.

4. The following table gives the percent growth of the U.S. population beginning in July of the year indicated. If the U.S. population was 281,421,906 in July 2000, estimate the U.S. population in July 2010.

Year % Change/Year
2000 1.12
2001 0.99
2002 0.93
2003 0.86
2004 0.93
2005 0.93
2006 0.97
2007 0.96
2008 0.95
2009 0.88

Annual Percentage Growth of U.S. Population, 2000–2009

Source: www.census.gov/popest/data.

(Hint: To obtain the population in July 2001, multiply the population in July 2000 by 1.0112 to get 284,573,831.)

Answer

309,389,957

Exercise 4.3E.19

In the following exercises, estimate the areas under the curves by computing the left Riemann sums, L8.

1.

alt

2.

alt

Answer

L8=3+2+1+2+3+4+5+4=24

3.

alt

4.

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Answer

L8=3+5+7+6+8+6+5+4=44

Exercise 4.3E.20

Use a computer algebra system to compute the Riemann sum:

1. LN, for N=10,30,50 for f(x)=1x2 on [1,1].

2. LN, for N=10,30,50 for f(x)=11+x2 on [1,1].

Answer

L101.7604,L301.7625,L501.76265

3. LN, for N=10,30,50 for f(x)=sin2x on [0,2π]. Compare these estimates with π.

Exercise 4.3E.21

In the following exercises, use a calculator or a computer program to evaluate the endpoint sums RN and LN for N=1,10,100.

How do these estimates compare with the exact answers, which you can find via geometry?

1. y=cos(πx) on the interval [0,1]

Answer

R1=1,L1=1,R10=0.1,L10=0.1,L100=0.01, and R100=0.1. By symmetry of the graph, the exact area is zero.

2. y=3x+2 on the interval [3,5]

Exercise 4.3E.22

In the following exercises, use a calculator or a computer program to evaluate the endpoint sums RN and LN for N=1,10,100.

1. y=x45x2+4 on the interval [2,2], which has an exact area of 3215

Answer

R1=0,L1=0,R10=2.4499,L10=2.4499,R100=2.1365,L100=2.1365

2. y=lnx on the interval [1,2], which has an exact area of \(\displaystyle 2ln(2)−1\

Exercise 4.3E.23

1. Explain why, if f(a)0 and f is increasing on [a,b], that the left endpoint estimate is a lower bound for the area below the graph of f on [a,b].

Answer

If [c,d]is a subinterval of [a,b] under one of the left-endpoint sum rectangles, then the area of the rectangle contributing to the left-endpoint estimate is f(c)(dc).

But, f(c)f(x) for cxd, so the area under the graph of f between c and d is f(c)(dc) plus the area below the graph of f but above the horizontal line segment at height f(c), which is positive.

As this is true for each left-endpoint sum interval, it follows that the left Riemann sum is less than or equal to the area below the graph of f on [a,b].

2. Explain why, if f(b)0 and f is decreasing on [a,b], that the left endpoint estimate is an upper bound for the area below the graph of f on [a,b].

3. Show that, in general, RNLN=(ba)×f(b)f(a)N.

Answer

LN=baNNi=1f(a+(ba)i1N)=baNN1i=0f(a+(ba)iN) and RN=baNNi=1f(a+(ba)iN).

The left sum has a term corresponding to i=0 and the right sum has a term corresponding to i=N.

In RNLN, any term corresponding to i=1,2,,N1 occurs once with a plus sign and once with a minus sign, so each such term cancels and one is left with RNLN=baN(f(a+(ba))NN)(f(a)+(ba)0N)=baN(f(b)f(a)).

4. Explain why, if f is increasing on [ a,b], the error between either LN or RN and the area A below the graph of f is at most \(\displaystyle (b−a)\frac{f(b)−f(a)}{N]|).

Exercise 4.3E.24

For each of the three graphs:

a. Obtain a lower bound L(A) for the area enclosed by the curve by adding the areas of the squares enclosed completely by the curve.

b. Obtain an upper bound U(A) for the area by adding to L(A) the areas B(A) of the squares enclosed partially by the curve.

alt

Answer

Graph 1:

a. L(A)=0,B(A)=20

b. U(A)=20.

Graph 2:

a. L(A)=9

b. B(A)=11,U(A)=20.

Graph 3:

a. L(A)=11.0

b. B(A)=4.5,U(A)=15.5.

In the previous exercise, explain why L(A) gets no smaller while U(A) gets no larger as the squares are subdivided into four boxes of equal area.

Answer

Under Construction

Exercise 4.3E.25

A unit circle is made up of n wedges equivalent to the inner wedge in the figure. The base of the inner triangle is 1 unit and its height is sin(πn). The base of the outer triangle is B=cos(πn)+sin(πn)tan(πn) and the height is H=Bsin(2πn). Use this information to argue that the area of a unit circle is equal to π.\)

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Answer

Let A be the area of the unit circle. The circle encloses n congruent triangles each of area sin(2πn)2, so n2sin(2πn)A. Similarly, the circle is contained inside n congruent triangles each of area BH2=12(cos(πn)+sin(πn)tan(πn))sin(2πn), so An2sin(2πn)(cos(πn))+sin(πn)tan(πn). As n,n2sin(2πn)=πsin(2πn)(2πn)π, so we conclude πA. Also, as n,cos(πn)+sin(πn)tan(πn)1, so we also have Aπ. By the squeeze theorem for limits, we conclude that A=π.


4.3E: Exercises is shared under a CC BY-NC-SA license and was authored, remixed, and/or curated by LibreTexts.

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