6.3.1: Fractal Dimension

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Page ID: 74344

Leah Griffith, Veronica Holbrook, Johnny Johnson & Nancy Garcia
Rio Hondo College

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6.3.2 Learning Objectives

Determine the dimension of a fractal

In addition to visual self-similarity, fractals exhibit other interesting properties. For example, notice that each step of the Sierpinski gasket iteration removes one quarter of the remaining area. If this process is continued indefinitely, we would end up essentially removing all the area, meaning we started with a 2-dimensional area, and somehow end up with something less than that, but seemingly more than just a 1-dimensional line.

To explore this idea, we need to discuss dimension. Something like a line is 1-dimensional; it only has length. Any curve is 1-dimensional. Things like squares and circles are 2-dimensional, since they have length and width, describing an area. Objects like boxes and cylinders have length, width, and depth, describing a volume, and are 3-dimensional.

$3 categories pictured: 1 dimension a line or a curve. 2 dimension a square, triangle, or circle. 3 dimension a cube or a cylinder.$

Certain rules apply for scaling objects, related to their dimension.

If I had a line with length 1, and wanted scale its length by 2, I would need two copies of the original line. If I had a line of length 1, and wanted to scale its length by 3, I would need three copies of the original.

$Three images: The image of a horizontal line. The image of the same line connected to another of the same length with a vertical hash mark to show the division. The last image is the orignal line connected to two others of the same size with two vertcial hash marks to show the division.$

If I had a rectangle with length 2 and height 1, and wanted to scale its length and width by 2, I would need four copies of the original rectangle. If I wanted to scale the length and width by 3, I would need nine copies of the original rectangle.

$Three images: the first a rectangle with length 2 and height one. The second image shows the first rectangle repeated four times to create a larger rectangle with length 4 and height 2. The third image shows the first rectangle repeated nine times to create a larger rectangle with length 6 and height 3.$

If I had a cubical box with sides of length 1, and wanted to scale its length and width by 2, I would need eight copies of the original cube. If I wanted to scale the length and width by 3, I would need 27 copies of the original cube.

$Three images: A cube each of its six sides length of one unit. The second image repeats the cube 8 times to create a larger cube with each side 2 units. The third image repeats the cube 27 times to create a larger cube with each side 3 units.$

Notice that in the 1-dimensional case, copies needed = scale.

In the 2-dimensional case, copies needed $=$ scale$^{2}$.
In the 3-dimensional case, copies needed $=$ scale$^{3}$.

From these examples, we might infer a pattern.

Scaling-Dimension Relation

To scale a $D$-dimensional shape by a scaling factor $S,$ the number of copies $C$ of the original shape needed will be given by:

Copies $=$ Scale$^{\text{Dimension}}$, or $C=S^D$

Example 5

Use the scaling-dimension relation to determine the dimension of the Sierpinski gasket.

Solution

Suppose we define the original gasket to have side length 1. The larger gasket shown is twice as wide and twice as tall, so has been scaled by a factor of 2.

$The Serpenski Gadget which is an equilateral triangle with equilateral triangles cut out of it repeatedly every time a new solid trianlge is generated. See the explanation in detail in the previous section of this chapter.$

Notice that to construct the larger gasket, 3 copies of the original gasket are needed.

Using the scaling-dimension relation $C=S^{D},$ we obtain the equation $3=2^{D}$

since $2^{1}=2$ and $2^{2}=4,$ we can immediately see that $D$ is somewhere between 1 and $2 ;$ the gasket is more than a 1 -dimensional shape, but we've taken away so much area its now less than 2-dimensional.

Solving the equation $3=2^{D}$ requires logarithms. If you studied logarithms earlier, you may recall how to solve this equation (if not, just skip to the box below and use that formula):

\[\begin{array}{ll}
3=2^{D} & \text{Take the logarithm of both sides} \\
\log (3)=\log \left(2^{D}\right) & \text{Use the exponent property of logs} \\
\log (3)=D \log (2) & \text{Divide by log(2)} \\
D=\frac{\log (3)}{\log (2)} \approx 1.585 & \text{The dimension of the gasket is about 1.585}
\end{array}\]

Scaling-Dimension Relation, to find Dimension

To find the dimension $D$ of a fractal, determine the scaling factor $S$ and the number of copies $C$ of the original shape needed, then use the formula

\[D=\frac{\log (C)}{\log (S)} \nonumber\]

Try it Now 2

Determine the fractal dimension of the fractal produced using the initiator and generator

$The initiator is a solid square. The generator replaces the original square with nine squares, the four corner and middle square are shaded the others are cutouts.$

Answer

$The next step would be to replace the five shaded squares with the same cutout pattern from the previous steps. The fourth step would be to replace all newly generated squares with the same pattern.$

Scaling the fractal by a factor of 3 requires 5 copies of the original. $D=\frac{\log (5)}{\log (3)} \approx 1.465$