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About 21 results
  • https://math.libretexts.org/Courses/De_Anza_College/Pre-Statistics/5%3A_Operations_on_Numbers/5.6%3A_Powers_and_Roots
    It can be a challenge when we first try to use technology to raise a number to a power or take a square root of a number. In this section, we will go over some pointers on how to successfully take pow...It can be a challenge when we first try to use technology to raise a number to a power or take a square root of a number. In this section, we will go over some pointers on how to successfully take powers and roots of a number. We will also continue our practice with the order of operations, remembering that as long as there are no parentheses, exponents always come before all other operations. We will see that taking a power of a number comes up in probability.
  • https://math.libretexts.org/Courses/Rio_Hondo/Math_150%3A_Survey_of_Mathematics/01%3A_Foundations/1.04%3A_Exponents
    \(62 \cdot 62 \cdot 62 \cdot 62 \cdot 62 \cdot 62 \cdot 62 \cdot 62 \cdot 62\) 5 is called the exponent, or power. \(8^5\) is read as "eight to the fifth power," or more simply as "eight to the fifth,...\(62 \cdot 62 \cdot 62 \cdot 62 \cdot 62 \cdot 62 \cdot 62 \cdot 62 \cdot 62\) 5 is called the exponent, or power. \(8^5\) is read as "eight to the fifth power," or more simply as "eight to the fifth," or "the fifth power of eight." When a number is raised to the second power, it is said to be squared. When a number is raised to the third power, it is said to be cubed. When a number is raised to the power of 4 or higher, we simply say that that number is raised to that particular power.
  • https://math.libretexts.org/Bookshelves/Applied_Mathematics/Calculus_for_Business_and_Social_Sciences_Corequisite_Workbook_(Dominguez_Martinez_and_Saykali)/04%3A_Functions/4.10%3A_Finding_all_Real_Roots_of_a_Function
    To find the real roots of a function, find where the function intersects the x-axis. To find where the function intersects the x-axis, set f(x)=0 and solve the equation for x.
  • https://math.libretexts.org/Courses/Highline_College/MATH_141%3A_Precalculus_I_(2nd_Edition)/03%3A_Polynomial_and_Rational_Functions/3.03%3A_Graphs_of_Polynomial_Functions
    The way to get this term is to multiply the terms with the highest power of \(x\) from each factor together - in other words, the leading term of \(A(x)\) is the product of the leading terms of the fa...The way to get this term is to multiply the terms with the highest power of \(x\) from each factor together - in other words, the leading term of \(A(x)\) is the product of the leading terms of the factors of \(A(x)\).
  • https://math.libretexts.org/Bookshelves/Algebra/Intermediate_Algebra_(Arnold)/06%3A_Polynomial_Functions/6.02%3A_Zeros_of_Polynomials
    In the previous section we studied the end-behavior of polynomials. In this section, our focus shifts to the interior. There are two important areas of concentration: the local maxima and minima of th...In the previous section we studied the end-behavior of polynomials. In this section, our focus shifts to the interior. There are two important areas of concentration: the local maxima and minima of the polynomial, and the location of the x-intercepts or zeros of the polynomial. In this section we concentrate on finding the zeros of the polynomial.
  • https://math.libretexts.org/Bookshelves/Algebra/Elementary_Algebra_(LibreTexts)/09%3A_Solving_Quadratic_Equations_and_Graphing_Parabolas/9.01%3A_Extracting_Square_Roots
    The sum of the squares of the legs of a right triangle is equal to the square of the hypotenuse: The height in feet of an object dropped from a 9-foot ladder is given by h(t)\(=−16t^{2}+9\), where t r...The sum of the squares of the legs of a right triangle is equal to the square of the hypotenuse: The height in feet of an object dropped from a 9-foot ladder is given by h(t)\(=−16t^{2}+9\), where t represents the time in seconds after the object has been dropped. How long does it take the object to hit the ground? (Hint: The height is 0 when the object hits the ground.)
  • https://math.libretexts.org/Courses/Hawaii_Community_College/Hawaii_Community_College_MA82X_Textbook/10%3A_Solving_Quadratic_Equations_and_Graphing_Parabolas/10.01%3A_Extracting_Square_Roots
    The sum of the squares of the legs of a right triangle is equal to the square of the hypotenuse: The height in feet of an object dropped from a 9-foot ladder is given by h(t)\(=−16t^{2}+9\), where t r...The sum of the squares of the legs of a right triangle is equal to the square of the hypotenuse: The height in feet of an object dropped from a 9-foot ladder is given by h(t)\(=−16t^{2}+9\), where t represents the time in seconds after the object has been dropped. How long does it take the object to hit the ground? (Hint: The height is 0 when the object hits the ground.)
  • https://math.libretexts.org/Courses/Highline_College/MATHP_141%3A_Corequisite_Precalculus/04%3A_Polynomial_and_Rational_Functions/4.03%3A_Graphs_of_Polynomial_Functions
    The way to get this term is to multiply the terms with the highest power of \(x\) from each factor together - in other words, the leading term of \(A(x)\) is the product of the leading terms of the fa...The way to get this term is to multiply the terms with the highest power of \(x\) from each factor together - in other words, the leading term of \(A(x)\) is the product of the leading terms of the factors of \(A(x)\).
  • https://math.libretexts.org/Courses/Coastline_College/Math_C097%3A_Support_for_Precalculus_Corequisite%3A_MATH_C170/1.04%3A_Polynomial_and_Rational_Functions/1.4.03%3A_Graphs_of_Polynomial_Functions
    The way to get this term is to multiply the terms with the highest power of \(x\) from each factor together - in other words, the leading term of \(A(x)\) is the product of the leading terms of the fa...The way to get this term is to multiply the terms with the highest power of \(x\) from each factor together - in other words, the leading term of \(A(x)\) is the product of the leading terms of the factors of \(A(x)\).
  • https://math.libretexts.org/Workbench/Hawaii_CC_Intermediate_Algebra/06%3A_Polynomial_and_Rational_Functions/6.04%3A_Solve_Polynomial_Equations_by_Factoring
    We have learned various techniques for factoring polynomials with up to four terms. The challenge is to identify the type of polynomial and then decide which method to apply.
  • https://math.libretexts.org/Bookshelves/Algebra/Advanced_Algebra/04%3A_Polynomial_and_Rational_Functions/404%3A_Solve_Polynomial_Equations_by_Factoring
    We have learned various techniques for factoring polynomials with up to four terms. The challenge is to identify the type of polynomial and then decide which method to apply.

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