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2.4: Nonlinear Equations in Rn

( \newcommand{\kernel}{\mathrm{null}\,}\)

Here we consider the nonlinear differential equation
F(x,z,p)=0,
where
x=(x1,,xn), z=u(x): ΩRnR1, p=u.
The following system of 2n+1 ordinary differential equations is called characteristic system.
x(t)=pFz(t)=ppFp(t)=xFFzp.
Let
x0(s)=(x01(s),,x0n(s)), s=(s1,,sn1),
be a given regular (n-1)-dimensional C2-hypersurface in Rn, i. e., we assume
rankx0(s)s=n1.
Here sD is a parameter from an (n1)-dimensional parameter domain D.

For example, x=x0(s) defines in the three dimensional case a regular surface in R3.

Assume
z0(s): DR1, p0(s)=(p01(s),,p0n(s))
are given sufficiently regular functions.

The (2n+1)-vector
(x0(s),z0(s),p0(s))
is called initial strip manifold and the condition
z0sl=n1i=1p0i(s)x0isl,
l=1,,n1, strip condition.

The initial strip manifold is said to be non-characteristic if
det
where the argument of F_{p_j} is the initial strip manifold.

Initial value problem of Cauchy. Seek a solution z=u(x) of the differential equation (\ref{nonlinear2}) such that the initial manifold is a subset of \{(x,u(x),\nabla u(x)):\ x\in \Omega\}.

As in the two dimensional case we have under additional regularity assumptions

Theorem 2.3. Suppose the initial strip manifold is not characteristic and satisfies differential equation (\ref{nonlinear2}), that is,
F(x_0(s),z_0(s),p_0(s))=0. Then there is a neighborhood of the initial manifold (x_0(s),z_0(s)) such that there exists a unique solution of the Cauchy initial value problem.

Sketch of proof. Let
x=x(s,t),\ z=z(s,t),\ p=p(s,t)
be the solution of the characteristic system and let
s=s(x),\ t=t(x)
be the inverse of x=x(s,t) which exists in a neighborhood of t=0. Then, it turns out that
z=u(x):= z(s_1(x_1,\ldots,x_n),\ldots,s_{n-1}(x_1,\ldots,x_n),t(x_1,\ldots,x_n))
is the solution of the problem.

Contributors and Attributions


This page titled 2.4: Nonlinear Equations in \mathbb{R}^n is shared under a not declared license and was authored, remixed, and/or curated by Erich Miersemann.

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