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Mathematics LibreTexts

2.3: Solution of Polynomial Inequalities by Graphing

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In this section, we will combine the concepts of the previous two sections to solve polynomial inequalities. In Section 2.2, we solved equations by graphing and finding the 𝑥 -values which made 𝑦 =0. In solving an inequality, we will be concerned with finding the range of 𝑥 values that make 𝑦 either greater than or less than 0, depending on the given problem.
Example
Solve the given inequality.
2𝑥3 +8𝑥2 +5𝑥 3 0
First, we graph the function:
clipboard_e3f8e47f913fd0e34106737c8e2343cf8.png
Then we identify the intervals of 𝑥 -values that make the 𝑦 value greater than or equal to zero, as indicated in the problem.
clipboard_e6b2909ccb26526cd094be44a912eed0f.png
The indicated roots of the function (𝐴,𝐵 and 𝐶) are the 𝑥 -values that make 𝑦 equal to zero. These points divide the graph between the regions where 𝑦 is greater than zero and the regions where 𝑦 is less than zero. The solution to the given inequlaity 2𝑥3 +8𝑥2 +5𝑥 3 0 are A 𝑥 B OR 𝑥 C
When we find the values of A,B and C :A =3,B 1.366 and C 0.366, we can
complete the solution to the problem.
2𝑥3 +8𝑥2 +5𝑥 3 0
3 𝑥 1.366 OR 𝑥 0.366

Example
Solve the given inequality.
𝑥4 2𝑥3 5𝑥2 +8𝑥 +3 0
First, we graph the function:
clipboard_e0d1f896a2f4849e3bffdbc8dfefdf341.png
In this problem, we're looking for the intervals of 𝑥 values that make 𝑦 less than or equal to zero. First, we identify the roots of the function:
clipboard_e1ec85eef24e411dee8323fc1cd74e19d.png
Next, we'll identify the intervals where the 𝑦 values are less than zero:
clipboard_e23c9b391486aa6db2497514cd64fa7d8.png
So, the solution to the original inequality is:
𝑥4 2𝑥3 5𝑥2 +8𝑥 +3 0
2.034 𝑥 0.320 OR 1.806 𝑥 2.549
In the next example we'll be looking to identify both the intervals where 𝑦 is greater than zero, and the intervals where 𝑦 is less than zero.

Example
Determine the interval(s) for which 𝑥3 +5𝑥2 +5𝑥 +1 0
Determine the interval(s) for which 𝑥3 +5𝑥2 +5𝑥 +1 <0
Once again, we'll start by graphing the function to find the roots:
clipboard_e83e7f20222ec2c78613c50fea074f1cd.png

Now that we've indentified the roots, we can determine where the 𝑦 values are greater than zero and where they're less than zero.

For 𝑦 0, we can see that this corresponds to: 3.732 𝑥 1 OR 𝑥 0.268
For 𝑦 <0, we can see that this corresponds to: 𝑥 <3.732OR 1 <𝑥 <0.268

Exercises 2.3
1) Determine the interval(s) for which 𝑥3 4𝑥2 +2𝑥 +3 0
Determine the interval(s) for which 𝑥3 4𝑥2 +2𝑥 +3 <0
2) Determine the interval(s) for which 4𝑥3 4𝑥2 19𝑥 +10 0
Determine the interval(s) for which 4𝑥3 4𝑥2 19𝑥 +10 <0
3) Determine the interval(s) for which 𝑥3 2.5𝑥2 7𝑥 1.5 0
Determine the interval(s) for which 𝑥3 2.5𝑥2 7𝑥 1.5 <0
4) Determine the interval(s) for which 𝑥3 3.5𝑥2 +0.5𝑥 +5 0
Determine the interval(s) for which 𝑥3 3.5𝑥2 +0.5𝑥 +5 <0
5) Determine the interval(s) for which 6𝑥4 13𝑥3 +2𝑥2 4𝑥 +15 0
Determine the interval(s) for which 6𝑥4 13𝑥3 +2𝑥2 4𝑥 +15 <0
6) Determine the interval(s) for which 𝑥4 𝑥3 𝑥2 +3𝑥 5 0
Determine the interval(s) for which 𝑥4 𝑥3 𝑥2 +3𝑥 5 <0
7) Determine the interval(s) for which 3𝑥4 +3𝑥3 14𝑥2 𝑥 +3 0
Determine the interval(s) for which 3𝑥4 +3𝑥3 14𝑥2 𝑥 +3 <0
8) Determine the interval(s) for which 4𝑥4 4𝑥3 7𝑥2 +4𝑥 +3 0
Determine the interval(s) for which 4𝑥4 4𝑥3 7𝑥2 +4𝑥 +3 <0

Determine the interval(s) that satisfy each inequality.
9) 𝑥3 +𝑥2 5𝑥 +3 0
10) 𝑥3 7𝑥 +6 >0
11) 𝑥3 13𝑥 +12 >0
12) 𝑥4 10𝑥2 +9 <0
13) 6𝑥4 9𝑥2 4𝑥 +12 0
14) 𝑥4 5𝑥3 +20𝑥 16 >0
15) 𝑥3 2𝑥2 7𝑥 +6 0
16) 𝑥4 6𝑥3 +2𝑥2 5𝑥 +2 0
17) 2𝑥4 +3𝑥3 2𝑥2 4𝑥 +2 >0
18) 𝑥5 +5𝑥4 4𝑥3 +3𝑥2 2 0


This page titled 2.3: Solution of Polynomial Inequalities by Graphing is shared under a CC BY-NC-SA 4.0 license and was authored, remixed, and/or curated by Richard W. Beveridge.

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