8.9: Complex Rational Expressions
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Simple And Complex Fractions
Simple Fraction
In section 8.2 we saw that a simple fraction was a fraction of the form PQ, where P and Q are polynomials and Q≠0.
Complex Fraction
A complex fraction is a fraction in which the numerator or denominator, or both, is a fraction. The fractions
81523 and 1−1x1−1x2
are examples of complex fractions, or more generally, complex rational expressions.
There are two methods for simplifying complex rational expressions: the combine-divide method and the LCD-multiply-divide method.
The Combine-Divide Method
- If necessary, combine the terms of the numerator together.
- If necessary, combine the terms of the denominator together.
- Divide the numerator by the denominator.
Sample Set A
Simplify each complex rational expression.
x38x512
Steps 1 and 2 are not necessary so we proceed with step 3:
x38x512=x38⋅12x5=x382⋅312x52=32x2
1−1x1−1x2
Step 1: Combine the terms of the numerator: LCD = x.
1−1x=xx−1x=x−1x
Step 2: Combine the terms of the denominator: LCD = x2.
1−1x2=x2x2−1x2=x2−1x2
Step 3: Divide the numerator by the denominator.
x−1xx2−1x2=x−1x⋅x2x2−1=x−1xx2(x+1)(x+1)=xx+1
Thus,
1−1x1−1x2=xx+1
2−13m−7m22+3m+1m2
Step 1: Combine the terms of the numerator: LCD = m2.
2−13m−7m2=2m2m2−13mm2−7m2=2m2−13m−7m2
Step 2: Combine the terms of the denominator: LCD = m2
2+3m+1m2=2m2m2+3mm2+1m2=2m2+3m+1m2
Step 3: Divide the numerator by the denominator:
2m2−13m−7m22m2+3m−1m2=2m2−13m−7m2⋅m22m2+3m+1=(2m+1)(m−7)m2⋅m2(2m+1)(m+1)=m−7m+1
Thus,
2−13m−7m22+3m+1m2=m−7m+1
Practice Set A
Use the combine-divide method to simplify each expression.
27x2615x38
- Answer
-
125x
3−1x3+1x
- Answer
-
3x−13x+1
1+xyx−y2x
- Answer
-
xy(x−y)
m−3+2mm−4+3m
- Answer
-
m−2m−3
1+1x−11−1x−1
- Answer
-
xx−2
The LCD-Multiply-Divide Method
- Find the LCD of all the terms.
- Multiply the numerator and denominator by the LCD.
- Reduce if necessary.
Sample Set B
Simplify each complex fraction.
1−4a21+2a
Step 1: The LCD =a2.
Step 2: Multiply both the numerator and denominator by a2.
a2(1−4a2)a2(1+2a)=a2⋅1−a2⋅4a2a2⋅1+a2⋅2a=a2−4a2+2a.
Step 3: Reduce:
a2−4a2+2a=(a+2)(a−2)a(a+2)=a−2a
Thus,
1−4a21+2a=a−2a
1−5x−6x21+6x+5x2
Step 1: The LCD is x2.
Step 2: Multiply the numerator and denominator by x2.
x2(1−5x−6x2)x2(1+6x+5x2)=x2⋅1−x2⋅5x−x2⋅6x2x2⋅1+x2⋅6x+x2⋅5x2=x2−5x−6x2+6x+5
Step 3: Reduce:
x2−5x−6x2+6x+5=(x−6)(x+1)(x+5)(x+1)=x−6x+5
Thus,
1−5x−6x21+6x+5x2=x−6x+5
Practice Set B
The following problems are the same problems as the problems in Practice Set A. Simplify these expressions using the LCD-multiply-divide method. Compare the answers to the answers produced in Practice Set A.
27x2615x38
- Answer
-
125x
3−1x3+1x
- Answer
-
3x−13x+1
1+xyx−y2x
- Answer
-
xy(x−y)
m−3+2mm−4+3m
- Answer
-
m−2m−3
1+1x−11−1x−1
- Answer
-
xx−2
Exercises
For the following problems, simplify each complex rational expression.
1+141−14
- Answer
-
53
1−131+13
1−1y1+1y
- Answer
-
y−1y+1
a+1xa−1x
ab+cbab−cb
- Answer
-
a+ca−c
5m+4m5m−4m
3+1x3x+1x2
- Answer
-
x
1+xx+y1−xx+y
2+5a+12−5a+1
- Answer
-
2a+72a−3
1−1a−11+1a−1
4−1m22+1m
- Answer
-
2m−1m
9−1x23−1x
k−1kk+1k
- Answer
-
k−1
mm+1−1m+12
2xy2x−y−y2x−y3
- Answer
-
3y2(2x−y)2
1a+b−1a−b1a+b+1a−b
5x+3−5x−35x+3+5x−3
- Answer
-
−3x
2+1y+11y+23
1x2−1y21x+1y
- Answer
-
y−xxy
1+5x+6x21−1x−12x2
1+1y−2y21+7y+10y2
- Answer
-
y−1y+5
3nm−2−mn3nm+4+mn
- Answer
-
3x−4
yx+y−xx−yxx+y+yx−y
aa−2−aa+22aa−2+a2a+2
- Answer
-
4a2+4
3−21−1m+1
x−11−1xx+11+1x
- Answer
-
(x−2)(x+1)(x−1)(x+2)
In electricity theory, when two resistors of resistance R1 and R2 ohms are connected in parallel, the total resistance R is:
R=11R1+1R2
Write this complex fraction as a simple fraction.
According to Einstein's theory of relativity, two velocities v1 and v2 are not added according to v=v1+v2, but rather by
v=v1+v21+v1v2c2
Write this complex fraction as a simple fraction.
Einstein's formula is really only applicable for velocities near the speed of light (c=186,000 miles per second). At very much lower velocities, such as 500 miles per hour, the formula v=v1+v2 provides an extremely good approximation.
- Answer
-
c2(V1+V2)c2+V1V2
Exercises For Review
Supply the missing word. Absolute value speaks to the question of how ____ and not “which way.”
Find the product. (3x+4)2
- Answer
-
9x2+24x+16
Factor x4−y4
Solve the equation 3x−1−5x+3=0.
- Answer
-
x=7
One inlet pipe can fill a tank in 10 minutes. Another inlet pipe can fill the same tank in 4 minutes. How long does it take both pipes working together to fill the tank?