Skip to main content
\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)
Mathematics LibreTexts

1.2: Functions of Several Variables

  1. Last updated
  2. Save as PDF
  • Page ID
    596

    • \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\) \(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)

    A function of several variables is a function where the domain is a subset of \(\mathbb{R}^n\) and range is \(\mathbb{R}\). For example

    \[ f(x,y) = x - y \]

    is a function of two variables

    \[ g(z,y,x) = \dfrac{ x - y}{ y-z}\]

    is a function of three variables.

    Finding the Domain

    To find the domain of a function of several variables, we look for zero denominators and negatives under square roots:

    Example \(\PageIndex{1}\): Domain of a Function

    Find the domain of

    \[ f(x,y) = \dfrac{\sqrt{x-y}}{x+y}.\]

    Solution

    First, the inside of the square root must be positive (since we are discussing real numbers), that is

    \[ x - y \ge 0\]

    second, the denominator must be nonzero, that is

    \[ x + y \neq 0\]

    hence we need to stay off the line

    \[y = -x.\]

    Putting this together gives

    \[(x,y) | x - y \ge 0 \;\; \text{ and } \;\; y \neq -x.\]

    The graph to the right shows the domain as the shaded green region.

    Exercise 1

    Find the domain of the function

    \[ f(x,y,z) = \dfrac{xyz}{\sqrt{4-x^2-y^2-z^2}}.\]

    Contours (Level Curves)

    The topographical map shown below is of the Rubicon Trail. It represents the function that maps a longitude and latitude to an altitude.

    Each curve represents a path where the z-coordinate (altitude) is a constant. Crossing many topo lines in a short distance represents a path that is very steep. Now lets make our own contour map of the function:

    \[ f(x,y) = y - x^2\]

    by setting constant values for \(z\):

    \(z\) Equation
    1 \(y = x^2 + 1\)
    2 \(y = x^2 + 2\)

    We see that each topo line is a parabola and that the y-intercept gives the height. Below is a contour diagram of this function.

    Names for the curves drawn are level curves, isotherms (for temperature), isobars (for pressure), and equipotential lines (for electric potential fields) depending on what the two variable function represents.

    Larry Green (Lake Tahoe Community College)

    • Integrated by Justin Marshall.