3.3: Systems of First Order
( \newcommand{\kernel}{\mathrm{null}\,}\)
Consider the quasilinear system
n∑k=1Ak(x,u)uuk+b(x,u)=0,
where Ak are m×m-matrices, sufficiently regular with respect to their arguments, and
$$
u=\left(u1⋮um
u_{x_k}=\left(u1,xk⋮um,xk
b=\left(b1⋮bm
\]
We ask the same question as above: can we calculate all derivatives of u in a neighborhood of a given hypersurface S in R defined by χ(x)=0, ∇χ≠0, provided u(x) is given on S?
For an answer we map S onto a flat surface S0 by using the mapping λ=λ(x) of Section 3.1 and write equation (???) in new coordinates. Set v(λ)=u(x(λ)), then
$$\sum_{k=1}^nA^k(x,u)\chi_{x_k}v_{\lambda_n}=\mbox{terms known on}\ \mathcal{S}_0.\]
We can solve this system with respect to vλn, provided that
$$\det\left(\sum_{k=1}^nA^k(x,u)\chi_{x_k}\right)\not=0\]
on S.
Definition. Equation
$$\det\left(\sum_{k=1}^nA^k(x,u)\chi_{x_k}\right)=0\]
is called characteristic equation associated to equation (???) and a surface S: χ(x)=0, defined by a solution χ, ∇χ≠0, of this characteristic equation is said to be characteristic surface.
Set
$$C(x,u,\zeta)=\det\left(\sum_{k=1}^nA^k(x,u)\zeta_k\right)\]
for ζk∈R.
Definition.
- The system (???) is hyperbolic at (x,u(x)) if there is a regular linear mapping ζ=Qη, where η=(η1,…,ηn−1,κ), such that there exists m {\it real} roots κk=κk(x,u(x),η1,…,ηn−1), k=1,…,m, of D(x,u(x),η1,…,ηn−1,κ)=0for all (η1,…,ηn−1), where D(x,u(x),η1,…,ηn−1,κ)=C(x,u(x),x,Qη).
- System (???) is parabolic if there exists a regular linear mapping ζ=Qη such that D is independent of κ, that is, D depends on less than n parameters.
- System (???) is elliptic if C(x,u,ζ)=0 only if ζ=0.
Remark. In the elliptic case all derivatives of the solution can be calculated from the given data and the given equation.
Contributors and Attributions
Integrated by Justin Marshall.