4.3: Exercises
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Graph the equation in the standard window.
- y=3x−5
- y=x2−3x−2
- y=x4−3x3+2x−1
- y=√x2−4
- y=1x+2
- y=|x+3|
For the last exercise, the absolute value is obtained by pressing math▹enter.
- Answer
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Solve the equation for y and graph all branches in the same window.
- x2+y2=4
- (x+5)2+y2=15
- (x−1)2+(y−2)2=9
- y2+x2−8x−14=0
- y2=x2+3
- y2=−x2+77
- Answer
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- y1=√4−x2, y2=−√4−x2,
- y1=√15−(x+5)2, y2=−√15−(x+5)2,
- y1=2+√9−(x−1)2, y2=2−√9−(x−1)2,
- y1=√−x2+8x+14, y2=−√−x2+8x+14,
- y1=√x2+3, y2=−√x2+3,
- y1=√−x2+77, y2=−√−x2+77,
- y1=√4−x2, y2=−√4−x2,
Find all zeros of the given function. Round your answer to the nearest hundredth.
- f(x)=x2+3x+1
- f(x)=x4−3x2+2
- f(x)=x3+2x−6
- f(x)=x5−11x4+20x3+88x2−224x+1
- f(x)=x3−5x2+2x+3
- f(x)=√2x−3−2x+3
- f(x)=0.04x3−0.02x2−0.5174x+0.81
- f(x)=0.04x3−0.02x2−0.5175x+0.81
- f(x)=0.04x3−0.02x2−0.5176x+0.81
- Answer
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- x≈−2.62,x≈−0.38
- x=±1,x=±√2≈±1.41
- x≈1.46
- x≈−2.83,x≈0.01,x≈2.82,x≈4.01,x≈7.00
- x≈−0.578,x≈1.187,x≈4.388
- x≈1.61,x=2,x≈6.91
- x≈−4.00
- x=−4,x=2.25
- x≈−4.00,x≈2.22,x≈2.28
Find all solutions of the equation. Round your answer to the nearest thousandth.
- x3+3=x5+7
- 4x3+6x2−3x−2=0
- 2xx−3=x2+2x+1
- 53x+1=x5+6
- x3+x2=x4−x2+x
- 3x2=x3−x2+3x
- Answer
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- x≈−1.488
- x≈−1.764,x≈−0.416,x≈0.681
- x≈5.220
- x≈−1.431,x≈0.038
- x≈−1.247,x=0,x≈0.445,x≈1.802
- x=0,x=1,x=3
Graph the equation. Determine how many maxima and minima the graph has. To this end, resize the graphing window (via the zoom-in, zoom-out, and zoom-box functions of the calculator) to zoom into the maxima or minima of the graph.
- y=x2−4x+13
- y=−x2+x−20
- y=2x3−5x2+3x
- y=x4−5x3+8x2−5x+1
- Answer
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- There is one minimum. Zoom out for the graph.
- There is one maximum. Resize the window to Ymin= −100.
- There is one local maximum and one local minimum. The graph with Xmin=−4, Xmax= 4, Ymin= −2, Ymax= 2 is below.
- Zooming into the graph reveals two local minima and one local maximum. We graph the function with Xmin=−2, Xmax= 4, Ymin= −1.3, Ymax= 0.5.
- There is one minimum. Zoom out for the graph.
Approximate the (local) maxima and minima of the graph. Round your answer to the nearest tenth.
- y=x3+2x2−x+1
- y=x3−5x2+8x−3
- y=−x4+3x3+x2+2
- y=x4−x3−4x2+6x+2
- y=x4−x3−4x2+8x+2
- y=x4−x3−4x2+7x+2
- Answer
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(there is only one minimum and no maximum in part (e))