5.3: Exercises
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Find a possible formula of the graph displayed below.
- Answer
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- y=|x|+1
- y=−√x
- y=(x−2)2+1
- y=1x+2+2
- y=−(x+2)3
- y=−|x−3|+2
Sketch the graph of the function, based on the basic graphs in Section 5.1 and the transformations described above. Confirm your answer by graphing the function with the calculator.
- f(x)=|x|−3
- f(x)=1x+2
- f(x)=−x2
- f(x)=(x−1)3
- f(x)=√−x
- f(x)=4⋅|x−3|
- f(x)=−√x+1
- f(x)=(12⋅x)2+3
- Answer
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Consider the graph of f(x)=x2−7x+1. Find the formula of the function that is given by performing the following transformations on the graph.
- Shift the graph of f down by 4.
- Shift the graph of f to the left by 3 units.
- Reflect the graph of f about the x-axis.
- Reflect the graph of f about the y-axis.
- Stretch the graph of f away from the y-axis by a factor 3.
- Compress the graph of f towards the y-axis by a factor 2.
- Answer
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- y=x2−7x−3
- y=(x+3)2−7⋅(x+3)+1=x2−x−11
- y=−x2+7x−1
- y=x2+7x+1
- y=19x2−73x+1
- y=4x2−14x+1
How are the graphs of f and g related?
- f(x)=√x,g(x)=√x−5
- f(x)=|x|,g(x)=2⋅|x|
- f(x)=(x+1)3,g(x)=(x−3)3
- f(x)=x2+3x+5,g(x)=(2x)2+3(2x)2+5
- f(x)=1x+3,g(x)=−1x
- f(x)=2⋅|x|,g(x)=|x+1|+1
- Answer
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- shift to the right by 5
- stretched away from the x-axis by a factor 2
- shift to the right by 4
- compressed towards the y-axis by a factor 2
- shifted to the right by 3 (to get the graph of y=1x ) and then reflected about the x-axis
- compressed towards the x-axis by a factor 2 (you get y=|x|) then shifted to the left by 1 and up by 1
Determine, if the function is even, odd, or neither.
- y=2x3
- y=5x2
- y=3x4−4x2+5
- y=2x3+5x2
- y=|x|
- y=1x
- Answer
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- odd
- even
- even
- neither
- even
- odd
- even
- neither
- odd
The graph of the function y=f(x) is displayed below.
Sketch the graph of the following functions.
- y=f(x)+1
- y=f(x−3)
- y=−f(x)
- y=2f(x)
- y=f(2x)
- y=f(12x)
- Answer
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