23.3: Exercises
- Page ID
- 54478
\( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)
\( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)
\( \newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\)
( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\)
\( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)
\( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\)
\( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)
\( \newcommand{\Span}{\mathrm{span}}\)
\( \newcommand{\id}{\mathrm{id}}\)
\( \newcommand{\Span}{\mathrm{span}}\)
\( \newcommand{\kernel}{\mathrm{null}\,}\)
\( \newcommand{\range}{\mathrm{range}\,}\)
\( \newcommand{\RealPart}{\mathrm{Re}}\)
\( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)
\( \newcommand{\Argument}{\mathrm{Arg}}\)
\( \newcommand{\norm}[1]{\| #1 \|}\)
\( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)
\( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\AA}{\unicode[.8,0]{x212B}}\)
\( \newcommand{\vectorA}[1]{\vec{#1}} % arrow\)
\( \newcommand{\vectorAt}[1]{\vec{\text{#1}}} % arrow\)
\( \newcommand{\vectorB}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)
\( \newcommand{\vectorC}[1]{\textbf{#1}} \)
\( \newcommand{\vectorD}[1]{\overrightarrow{#1}} \)
\( \newcommand{\vectorDt}[1]{\overrightarrow{\text{#1}}} \)
\( \newcommand{\vectE}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{\mathbf {#1}}}} \)
\( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)
\( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)
\(\newcommand{\avec}{\mathbf a}\) \(\newcommand{\bvec}{\mathbf b}\) \(\newcommand{\cvec}{\mathbf c}\) \(\newcommand{\dvec}{\mathbf d}\) \(\newcommand{\dtil}{\widetilde{\mathbf d}}\) \(\newcommand{\evec}{\mathbf e}\) \(\newcommand{\fvec}{\mathbf f}\) \(\newcommand{\nvec}{\mathbf n}\) \(\newcommand{\pvec}{\mathbf p}\) \(\newcommand{\qvec}{\mathbf q}\) \(\newcommand{\svec}{\mathbf s}\) \(\newcommand{\tvec}{\mathbf t}\) \(\newcommand{\uvec}{\mathbf u}\) \(\newcommand{\vvec}{\mathbf v}\) \(\newcommand{\wvec}{\mathbf w}\) \(\newcommand{\xvec}{\mathbf x}\) \(\newcommand{\yvec}{\mathbf y}\) \(\newcommand{\zvec}{\mathbf z}\) \(\newcommand{\rvec}{\mathbf r}\) \(\newcommand{\mvec}{\mathbf m}\) \(\newcommand{\zerovec}{\mathbf 0}\) \(\newcommand{\onevec}{\mathbf 1}\) \(\newcommand{\real}{\mathbb R}\) \(\newcommand{\twovec}[2]{\left[\begin{array}{r}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\ctwovec}[2]{\left[\begin{array}{c}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\threevec}[3]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\cthreevec}[3]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\fourvec}[4]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\cfourvec}[4]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\fivevec}[5]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\cfivevec}[5]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\mattwo}[4]{\left[\begin{array}{rr}#1 \amp #2 \\ #3 \amp #4 \\ \end{array}\right]}\) \(\newcommand{\laspan}[1]{\text{Span}\{#1\}}\) \(\newcommand{\bcal}{\cal B}\) \(\newcommand{\ccal}{\cal C}\) \(\newcommand{\scal}{\cal S}\) \(\newcommand{\wcal}{\cal W}\) \(\newcommand{\ecal}{\cal E}\) \(\newcommand{\coords}[2]{\left\{#1\right\}_{#2}}\) \(\newcommand{\gray}[1]{\color{gray}{#1}}\) \(\newcommand{\lgray}[1]{\color{lightgray}{#1}}\) \(\newcommand{\rank}{\operatorname{rank}}\) \(\newcommand{\row}{\text{Row}}\) \(\newcommand{\col}{\text{Col}}\) \(\renewcommand{\row}{\text{Row}}\) \(\newcommand{\nul}{\text{Nul}}\) \(\newcommand{\var}{\text{Var}}\) \(\newcommand{\corr}{\text{corr}}\) \(\newcommand{\len}[1]{\left|#1\right|}\) \(\newcommand{\bbar}{\overline{\bvec}}\) \(\newcommand{\bhat}{\widehat{\bvec}}\) \(\newcommand{\bperp}{\bvec^\perp}\) \(\newcommand{\xhat}{\widehat{\xvec}}\) \(\newcommand{\vhat}{\widehat{\vvec}}\) \(\newcommand{\uhat}{\widehat{\uvec}}\) \(\newcommand{\what}{\widehat{\wvec}}\) \(\newcommand{\Sighat}{\widehat{\Sigma}}\) \(\newcommand{\lt}{<}\) \(\newcommand{\gt}{>}\) \(\newcommand{\amp}{&}\) \(\definecolor{fillinmathshade}{gray}{0.9}\)Find the first seven terms of the sequence.
- \(a_n=3n\)
- \(a_n=5n+3\)
- \(a_n=n^2+2\)
- \(a_n=n\)
- \(a_n=(-1)^{n+1}\)
- \(a_n=\dfrac{\sqrt{n+1}}{n}\)
- \(a_k=10^k\)
- \(a_i=5+(-1)^i\)
- Answer
-
- \(3, 6, 9, 12, 15, 18, 21\)
- \(8, 13, 18, 23, 28, 33, 38\)
- \(3, 6, 11, 18, 27, 38, 51\)
- \(1, 2, 3, 4, 5, 6, 7\)
- \(1, −1, 1, −1, 1, −1, 1\)
- \(\sqrt{2}, \dfrac{\sqrt{3}}{2}, \dfrac{2}{3}, \dfrac{\sqrt{5}}{4}, \dfrac{\sqrt{6}}{5}, \dfrac{\sqrt{7}}{6}, \dfrac{\sqrt{8}}{7}\)
- \(10, 100, 1000, 10000, 100000, 1000000, 10000000\)
- \(4, 6, 4, 6, 4, 6, 4\)
Find the first six terms of the sequence.
- \(a_1=5\), \(a_n=a_{n-1}+3\) for \(n\geq 2\)
- \(a_1=7\), \(a_n=10\cdot a_{n-1}\) for \(n\geq 2\)
- \(a_1=1\), \(a_n=2\cdot a_{n-1}+1\) for \(n\geq 2\)
- \(a_1=6\), \(a_2=4\), \(a_n=a_{n-1}-a_{n-2}\) for \(n\geq 3\)
- Answer
-
- \(5, 8, 11, 14, 17\)
- \(7, 70, 700, 7000, 70000\)
- \(1, 3, 7, 15, 31\)
- \(6, 4, −2, −6, −4\)
Find the value of the series.
- \(\sum_{n=1}^4 a_n\), where \(a_n=5n\)
- \(\sum_{k=1}^5 a_k\), where \(a_k=k\)
- \(\sum_{i=1}^4 a_i\), where \(a_n=n^2\)
- \(\sum_{n=1}^6 (n-4)\)
- \(\sum_{k=1}^3 (k^2+4k-4)\)
- \(\sum_{j=1}^4 \dfrac{1}{j+1}\)
- Answer
-
- \(50\)
- \(15\)
- \(30\)
- \(−3\)
- \(26\)
- \(\dfrac {77}{60}\)
Is the sequence below part of an arithmetic sequence? In the case that it is part of an arithmetic sequence, find the formula for the \(n\)th term \(a_n\) in the form \(a_n=a_1+d\cdot (n-1)\).
- \(5, 8, 11, 14, 17, \dots\)
- \(-10, -7, -4, -1, 2, \dots\)
- \(-1, 1, -1, 1, -1, 1, \dots\)
- \(18, 164, 310, 474, \dots\)
- \(73.4, 51.7, 30, \dots\)
- \(9, 3, -3, -8, -14, \dots\)
- \(4, 4, 4, 4, 4, \dots\)
- \(-2.72, -2.82, -2.92, -3.02, -3.12, \dots\)
- \(\sqrt{2}, \sqrt{5}, \sqrt{8}, \sqrt{11}, \dots\)
- \(\dfrac{-3}{5}, \dfrac{-1}{10}, \dfrac{2}{5}, \dots\)
- \(a_n=4+5\cdot n\)
- \(a_j=2\cdot j-5\)
- \(a_n=n^2 +8n+15\)
- \(a_k=9\cdot (k+5) +7k-1\)
- Answer
-
For the convenience of those who prefer to use \(a_{n}=a+b \cdot n\) as standard form we have provided answers also in that form.
- \(5 + 3(n−1) = 2 + 3n\)
- \(−10 + 3(n−1) = −13 + 3n\)
- no
- no
- \(73.4−21.7(n−1) = 95.1−21.7n\)
- no
- \(4 + 0 ·(n−1) = 4 + 0 ·n\)
- \(-2.72-.1(n-1)=-2.62-.1 n\)
- no
- \(-\dfrac{3}{5}+\dfrac{1}{2}(n-1)=-\dfrac{11}{10}+\dfrac{1}{2} n\)
- \(9 + 5(n − 1) = 4 + 5n\)
- \(−3 + 2(j − 1) = −5 + 2j\)
- no
- \(29 + 16(k − 1) = 13 + 16k\)
Determine the general \(n\)th term \(a_n\) of an arithmetic sequence \(\{a_n\}\) with the data given below.
- \(d=4\), and \(a_{8}=57\)
- \(d=-3\), and \(a_{99}=-70\)
- \(a_1=14\), and \(a_{7}=-16\)
- \(a_1=-80\), and \(a_{5}=224\)
- \(a_{3}=10\), and \(a_{14}=-23\)
- \(a_{20}=2\), and \(a_{60}=32\)
- Answer
-
- \(57 + 4(n − 8) = 29 + 4(n − 1) = 25 + 4n\)
- \(−70 − 3(n − 99) = 224 − 3(n − 1) = 227 − 3n\)
- \(14 − 5(n − 1) = 19 − 5n\)
- \(−80 + 76(n − 1) = −156 + 76n\)
- \(10 − 3(n − 3) = 16 − 3(n − 1) = 19 − 3n\)
- \(2+\dfrac{3}{4}(n-20)=-49 / 4+\dfrac{3}{4}(n-1)=-13+\dfrac{3}{4} n\)
Determine the value of the indicated term of the given arithmetic sequence.
- if \(a_1=8\), and \(a_{15}=92\), find \(a_{19}\)
- if \(d=-2\), and \(a_3=31\), find \(a_{81}\)
- if \(a_1=0\), and \(a_{17}=-102\), find \(a_{73}\)
- if \(a_{7}=128\), and \(a_{37}=38\), find \(a_{26}\)
- Answer
-
- \(116\)
- \(187\)
- \(-\dfrac{3621}{8}\)
- \(71\)
Determine the sum of the arithmetic sequence.
- Find the sum \(a_1+\dots +a_{48}\) for the arithmetic sequence \(a_i=4i+7\).
- Find the sum \(\sum_{i=1}^{21}a_i\) for the arithmetic sequence \(a_n=2-5n\).
- Find the sum: \(\sum\limits_{i=1}^{99} (10\cdot i+1)\)
- Find the sum: \(\sum\limits_{n=1}^{200} (-9-n)\)
- Find the sum of the first \(100\) terms of the arithmetic sequence: \(2, 4, 6, 8, 10, 12, \dots\)
- Find the sum of the first \(83\) terms of the arithmetic sequence: \(25, 21, 17, 13, 9, 5, \dots\)
- Find the sum of the first \(75\) terms of the arithmetic sequence: \(2012, 2002, 1992, 1982, \dots\)
- Find the sum of the first \(16\) terms of the arithmetic sequence: \(-11, -6, -1, \dots\)
- Find the sum of the first \(99\) terms of the arithmetic sequence: \(-8, -8.2, -8.4, -8.6, -8.8, -9, -9.2, \dots\)
- Find the sum \(7+8+9+10+\dots+776+777\)
- Find the sum of the first \(40\) terms of the arithmetic sequence: \(5, 5, 5, 5, 5, \dots\)
- Answer
-
- \(5, 040\)
- \(−1, 113\)
- \(49, 599\)
- \(−21, 900\)
- \(10, 100\)
- \(−11, 537\)
- \(123, 150\)
- \(424\)
- \(−1762.2\)
- \(302, 232\)
- \(200\)