Skip to main content
Mathematics LibreTexts

11.7: More Functions and Identities

  • Page ID
    122987
  • \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)

    \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)

    \( \newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\)

    ( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\)

    \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)

    \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\)

    \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)

    \( \newcommand{\Span}{\mathrm{span}}\)

    \( \newcommand{\id}{\mathrm{id}}\)

    \( \newcommand{\Span}{\mathrm{span}}\)

    \( \newcommand{\kernel}{\mathrm{null}\,}\)

    \( \newcommand{\range}{\mathrm{range}\,}\)

    \( \newcommand{\RealPart}{\mathrm{Re}}\)

    \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)

    \( \newcommand{\Argument}{\mathrm{Arg}}\)

    \( \newcommand{\norm}[1]{\| #1 \|}\)

    \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)

    \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\AA}{\unicode[.8,0]{x212B}}\)

    \( \newcommand{\vectorA}[1]{\vec{#1}}      % arrow\)

    \( \newcommand{\vectorAt}[1]{\vec{\text{#1}}}      % arrow\)

    \( \newcommand{\vectorB}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)

    \( \newcommand{\vectorC}[1]{\textbf{#1}} \)

    \( \newcommand{\vectorD}[1]{\overrightarrow{#1}} \)

    \( \newcommand{\vectorDt}[1]{\overrightarrow{\text{#1}}} \)

    \( \newcommand{\vectE}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{\mathbf {#1}}}} \)

    \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)

    \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)

    8.1 Sum and Difference Formulas

    Homework 8-1

    1. Screen Shot 2023-02-25 at 10.08.59 PM.png

    \(x_2=x_1, y_2=-y_1\), and \(r_2=r_1\). Thus, \(\cos (-\alpha)=\dfrac{x_2}{r_2}=\dfrac{x_1}{r_1}=\cos \alpha, \sin (-\alpha)=\dfrac{y_2}{r_2}=\dfrac{-y_1}{r_1}= -\sin \alpha\), and \(\tan (-\alpha)=\dfrac{y_2}{x_2}=\dfrac{-y_1}{x_1}=-\tan \alpha\)

    3. \(\dfrac{-(\sqrt{2}+\sqrt{6})}{4}\)

    Screen Shot 2023-02-25 at 10.11.03 PM.png

    5. \(\cos (0.3-2 x)=0.24, \sin (0.3-2 x)=0.97\)

    7. \(\cos \left(45^{\circ}+45^{\circ}\right)=\cos \left(90^{\circ}\right)=0\), but \(\cos 45^{\circ}+\cos 45^{\circ}=\dfrac{1}{\sqrt{2}}+\dfrac{1}{\sqrt{2}}=\sqrt{2}\)

    9. \(\tan \left(87^{\circ}-29^{\circ}\right) \approx 1.600\), but \(\tan 87^{\circ}-\tan 29^{\circ} \approx 18.527\)

    11. Screen Shot 2023-02-25 at 10.12.22 PM.png The curves are different.

    13.

    a \(\dfrac{63}{65}\)

    b \(\dfrac{-16}{65}\)

    c \(\dfrac{-16}{63}\)

    15.

    a \(\dfrac{44}{117}\)

    b \(\dfrac{4}{3}\)

    17.

    a \(\dfrac{36}{85}\)

    b \(\dfrac{-13}{84}\)

    19.

    a \(\dfrac{-16}{65}\)

    b \(\dfrac{63}{65}\)

    c \(\dfrac{-16}{63}\)

    d Screen Shot 2023-02-25 at 10.15.10 PM.png

    21. \(\cos 15^{\circ}=\dfrac{\sqrt{6}+\sqrt{2}}{4}, \tan 15^{\circ}=2-\sqrt{3}\)

    23. \(\dfrac{6 \sqrt{2}+1}{10}\)

    25. \(\cos \theta\)

    27. \(\dfrac{\sqrt{3}}{2} \cos t-\dfrac{1}{2} \sin t\)

    29. \(\dfrac{\sqrt{3} \tan \beta-1}{\sqrt{3}+\tan \beta}\)

    31. No

    33. No

    35. \(1=2\left(\dfrac{1}{\sqrt{2}}\right)\left(\dfrac{1}{\sqrt{2}}\right)\)

    37. \(\dfrac{1}{2}=\left(\dfrac{\sqrt{3}}{2}\right)^2-\left(\dfrac{1}{2}\right)^2\)

    39. False, but \(\cos 2 \alpha=2(0.32)^2-1\)

    41. False, but \(2 \theta=\sin ^{-1}(h)\)

    43. \(\sin 68^{\circ}\)

    45. \(\cos \dfrac{\pi}{8}\)

    47. \(\cos 6\theta\)

    49. \(\sin 10 t\)

    51. \(\tan 128^{\circ}\)

    53. \(\cos 4 \beta\)

    55.

    a \(\dfrac{5}{6}\)

    b \(\dfrac{\sqrt{11}}{6}\)

    c \(\dfrac{5}{\sqrt{11}}\)

    d \(\dfrac{5 \sqrt{11}}{18}\)

    e \(\dfrac{-7}{18}\)

    f \(\dfrac{-5 \sqrt{11}}{7}\)

    57.

    a \(\dfrac{1}{\sqrt{w^2+1}}\)

    b \(\dfrac{w}{\sqrt{w^2+1}}\)

    c \(\dfrac{1}{w}\)

    d \(\dfrac{2 w}{w^2+1}\)

    e \(\dfrac{w^2-1}{w^2+1}\)

    f \(\dfrac{2 w}{w^2-1}\)

    59.

    a \(\dfrac{-5}{13}\)

    b \(\dfrac{-120}{169}\)

    c \(\dfrac{119}{169}\)

    d \(\dfrac{-120}{119}\)

    e Screen Shot 2023-02-25 at 11.00.34 PM.png

    61.

    a \(\dfrac{8}{15}\)

    b \(\dfrac{-15}{17}\)

    c \(\dfrac{-8}{17}\)

    63.

    a \(2 \sin \theta \cos \theta+\sqrt{2} \cos \theta=0\)

    b \(\dfrac{\pi}{2}, \dfrac{5 \pi}{4}, \dfrac{3 \pi}{2}, \dfrac{7 \pi}{4}\)

    65.

    a \(2 \cos ^2 t-5 \cos t+2=0\)

    b \(\dfrac{\pi}{3}, \dfrac{5 \pi}{3}\)

    67.

    a \(\dfrac{2 \tan \beta}{1-\tan ^2 \beta}+2 \sin \beta=0\)

    b \(0, \dfrac{\pi}{3}, \pi, \dfrac{5 \pi}{3}\)

    69.

    a \(3 \cos \phi-\cos \phi=\sqrt{3}\)

    b \(\dfrac{\pi}{6}, \dfrac{11 \pi}{6}\)

    71.

    a \(\sin 3 \phi=1\)

    b \(\dfrac{\pi}{6}, \dfrac{5 \pi}{6}, \dfrac{3 \pi}{2}\)

    73.

    a \(\cos \left(\theta+90^{\circ}\right)=-\sin \theta\)

    b \(\sin \left(\theta+90^{\circ}\right)=\cos \theta\)

    75.

    a \(\cos \left(\dfrac{\pi}{2}-\theta\right)=\cos \dfrac{\pi}{2} \cos \theta+\sin \dfrac{\pi}{2} \sin \theta=\sin \theta\)

    b \(\sin \left(\dfrac{\pi}{2}-\theta\right)=\sin \dfrac{\pi}{2} \cos \theta-\cos \dfrac{\pi}{2} \sin \theta=\cos \theta\)

    77.

    \begin{aligned}
    \sin 2 \theta & =\sin (\theta+\theta) \\
    & =\sin \theta \cos \theta+\sin \theta \cos \theta \\
    & =2 \sin \theta \cos \theta
    \end{aligned}

    79.

    a Not an identity

    b \(\beta=\pi\) (many answers possible)

    81. Identity

    83.

    a Not an identity

    b \(\theta = 0\) (many answers possible)

    85. Identity

    87. Identity

    89.

    Screen Shot 2023-02-25 at 11.23.22 PM.png

    a \(l_1=\sin \alpha, l_2=\cos \alpha\)

    b \(\theta_1\) and \(\beta\) are both complements of \(\phi ; \theta_2\) and \(\alpha+\beta\) are alternate interior angles

    c \(s_1=\cos (\alpha+\beta), s_2=\sin (\alpha+\beta)\)

    d \(s_3=\sin \alpha \sin \beta, s_4=\sin \alpha \cos \beta\)

    e \(s_5=\cos \alpha \cos \beta, s_6=\cos \alpha \sin \beta\)

    f \(\sin (\alpha+\beta)=\sin \alpha \cos \beta+\cos \alpha \sin \beta, \cos (\alpha+\beta)=\cos \alpha \cos \beta+\sin \alpha \sin \beta\)

    91.

    a \((A B)^2=2-2 \cos (\alpha-\beta)\)

    b \((A B)^2=(\cos \alpha-\cos \beta)^2+(\sin \alpha-\sin \beta)^2\)

    c

    \begin{aligned}
    & 2-2 \cos (\alpha-\beta)=(\cos \alpha-\cos \beta)^2+(\sin \alpha-\sin \beta)^2 \\
    & 2-2 \cos (\alpha-\beta)=\cos ^2-2 \cos \alpha \cos \beta+\cos ^2 \beta +\sin ^2 \alpha-2 \sin \alpha \sin \beta+\sin ^2 \beta \\
    & 2-2 \cos (\alpha-\beta)=1+1-2(\cos \alpha \cos \beta-\sin \alpha \sin \beta) -2 \cos (\alpha-\beta)=-2(\cos \alpha \cos \beta-\sin \alpha \sin \beta) \\
    & \cos (\alpha-\beta)=\cos \alpha \cos \beta-\sin \alpha \sin \beta \\
    \end{aligned}

    8.2 Inverse Trigonometric Functions

    Homework 8-2

    1. No inverse: Some horizontal lines intersect the curve in more than one point.

    3. Inverse exists: The function is 1-1.

    5. Screen Shot 2023-02-26 at 3.47.08 PM.png No inverse

    7. Screen Shot 2023-02-26 at 3.47.18 PM.png No inverse

    9. \(16.5^{\circ}\)

    11. \(46.4^{\circ}\)

    13. \(=51.9^{\circ}\)

    15. \(\dfrac{3 \pi}{4}\)

    17. \(\dfrac{-\pi}{6}\)

    19. \(\dfrac{\pi}{6}\)

    21. Screen Shot 2023-02-26 at 3.49.42 PM.png

    a \(h=500 \tan \theta\)

    b \(\theta=\tan ^{-1}\left(\dfrac{h}{500}\right)\)

    c \(\theta=\tan ^{-1}(2)\), so the angle of elevation is \(\tan ^{-1} 2 \approx 63.4^{\circ}\) when the rocket is 1000 yd high

    23. Screen Shot 2023-02-26 at 3.51.08 PM.png

    a \(d=\dfrac{50}{\tan \theta}\)

    b \(\theta=\tan ^{-1}\left(\dfrac{50}{d}\right)\)

    c \(\theta=\tan ^{-1}(0.25)\); the billboard subtends an angle of \(\tan ^{-1}(0.25) \approx 14^{\circ}\) at a distance of 200 \(\mathrm{ft}\).

    25. Screen Shot 2023-02-26 at 3.53.06 PM.png

    a \(\alpha=\tan ^{-1}\left(\dfrac{1}{x}\right)\)

    b \(\beta=\tan ^{-1}\left(\dfrac{5}{x}\right)-\tan ^{-1}\left(\dfrac{1}{x}\right)\)

    c \(\beta=45^{\circ}-\tan ^{-1}\left(\dfrac{1}{5}\right)\), so the painting subtends an angle of \(45^{\circ}-\tan ^{-1}\left(\dfrac{1}{5}\right) \approx 33.7^{\circ}\) when Martin is 5 meters from the wall.

    27. \(t=\dfrac{1}{2 \pi \omega}\left(\sin ^{-1} \dfrac{V}{V_0}-\phi\right)\)

    29. \(A=\sin ^{-1}\left(\dfrac{a \sin B}{b}\right)\)

    31. \(\theta=\pm \cos ^{-1}\left(\dfrac{k}{P R^4}\right)\)

    33. \(\dfrac{2}{\sqrt{5}}\)

    35. \(\dfrac{1}{\sqrt{5}}\)

    37. \(\dfrac{5}{7}\)

    39. \(\dfrac{\sqrt{1-x^2}}{x}\)

    41. \(\sqrt{1-h^2}\)

    43. \(\dfrac{2 t}{\sqrt{4 t^2+1}}\)

    45.

    Screen Shot 2023-02-26 at 3.59.02 PM.png

    \(x\) -1 \(\dfrac{-\sqrt{3}}{2}\) \(\dfrac{-\sqrt{2}}{2}\) \(\dfrac{-1}{2}\) 0 \(\dfrac{1}{2}\) \(\dfrac{\sqrt{2}}{2}\) \(\dfrac{\sqrt{3}}{2}\) 1
    \(\cos ^{-1} x\) \(\pi\) \(\dfrac{5\pi}{6}\) \(\dfrac{3\pi}{4}\) \(\dfrac{2\pi}{3}\) \(\dfrac{\pi}{2}\) \(\dfrac{\pi}{3}\) \(\dfrac{\pi}{4}\) \(\dfrac{\pi}{6}\) 0

    47.

    Screen Shot 2023-02-26 at 3.59.35 PM.png

    \(x\) \(-\sqrt{3}\) -1 \(\dfrac{-1}{\sqrt{3}}\) 0 \(\dfrac{1}{\sqrt{3}}\) 1 \(\sqrt{3}\)
    \(\cos ^{-1} x\) \(\dfrac{-\pi}{2}\) \(\dfrac{-\pi}{3}\) \(\dfrac{-\pi}{6}\) 0 \(\dfrac{\pi}{6}\) \(\dfrac{\pi}{4}\) \(\dfrac{\pi}{3}\)

    49.

    a-b. Screen Shot 2023-02-26 at 4.02.39 PM.png

    c. No

    51.

    a. Screen Shot 2023-02-26 at 4.02.52 PM.png

    c. No

    53. \(\dfrac{8}{17}\)

    55. \(\dfrac{16}{65}\)

    57. \(\dfrac{4 \sqrt{2}}{7}\)

    59.

    a \(\dfrac{-63}{65}\)

    b \(\dfrac{16}{65}\)

    c \(\dfrac{-33}{65}\)

    d \(\dfrac{56}{65}\)

    61. 1

    63.

    a \(\dfrac{2 x}{x^2+1}\)

    b \(1-x^2\)

    65. \(\sin 2 \theta=\dfrac{2 x \sqrt{25-x^2}}{25}, \cos 2 \theta=\dfrac{25-2 x^2}{25}\)

    67. \(\arctan \dfrac{x}{3}+\dfrac{3 x}{2\left(x^2+9\right)}\)

    69.

    a \(-1 \leq x \leq 1\)

    b Yes.

    c All

    d \(x<\dfrac{-\pi}{2}\) or \(x>\dfrac{\pi}{2}\)

    71.

    a Domain: \(-1 \leq x \leq 1\), range: \(\left\{\dfrac{\pi}{2}\right\}\)

    73.

    a \(\dfrac{\theta}{2}\)

    b \(t=\sin \theta\)

    c \(\dfrac{1}{2} \arcsin t\)

    8.3 The Reciprocal Functions

    Homework 8-3

    1. 2.203

    3. 0.466

    5. 5.883

    7. 1.203

    9. 2

    11. 1

    13. \(\dfrac{-2 \sqrt{3}}{3}\)

    15. \(\sqrt{2}\)

    17.

    \(\theta\) 0 \(\dfrac{\pi}{6}\) \(\dfrac{\pi}{4}\) \(\dfrac{\pi}{3}\) \(\dfrac{\pi}{2}\) \(\dfrac{2\pi}{3}\) \(\dfrac{3\pi}{4}\) \(\dfrac{5\pi}{6}\) \(\pi\)
    \(\sec \theta\) 1 \(\dfrac{2\sqrt{3}}{3}\) \(\sqrt{2}\) 2 undefined -2 \(-\sqrt{2}\) \(-\dfrac{2\sqrt{3}}{3}\) -1
    \(\csc \theta\) undefined 2 \(\sqrt{2}\) \(\dfrac{2\sqrt{3}}{3}\) 1 \(\dfrac{2\sqrt{3}}{3}\) \(\sqrt{2}\) 2 undefined
    \(\cot \theta\) undefined \(\sqrt{3}\) 1 \(\dfrac{\sqrt{3}}{3}\) 0 \(\dfrac{-\sqrt{3}}{3}\) -1 \(-\sqrt{3}\) undefined

    19.

    a 0.980

    b 1.020

    c 1.369

    d 1.020

    e 0.284

    f 1.020

    21. \(\sin \theta=\dfrac{4}{5}, \quad \cos \theta=\dfrac{3}{5}, \quad \tan \theta=\dfrac{4}{3}, \quad \sec \theta=\dfrac{5}{3}, \quad \csc \theta=\dfrac{5}{4}, \quad \cot \theta=\dfrac{3}{4}\)

    23. \(\sin \theta=\dfrac{4}{\sqrt{41}}, \quad \cos \theta=\dfrac{5}{\sqrt{41}}, \quad \tan \theta=\dfrac{4}{5}, \quad \sec \theta=\dfrac{\sqrt{41}}{5}, \quad \csc \theta=\dfrac{\sqrt{41}}{4}, \quad \cot \theta=\dfrac{5}{4}\)

    25. \(\sin \theta=\dfrac{5}{\sqrt{74}}, \quad \cos \theta=\dfrac{-7}{\sqrt{74}}, \quad \tan \theta=\dfrac{-5}{7}, \quad \sec \theta=\dfrac{-\sqrt{74}}{7}, \quad \csc \theta=\dfrac{\sqrt{74}}{5}, \quad \cot \theta=\dfrac{-7}{5}\)

    27. \(\sin \theta=\dfrac{-5}{8}, \quad \cos \theta=\dfrac{\sqrt{39}}{8}, \quad \tan \theta=\dfrac{5}{\sqrt{39}}, \sec \theta=\dfrac{-8}{\sqrt{39}}, \quad \csc \theta=\dfrac{-8}{5}, \quad \cot \theta=\dfrac{\sqrt{39}}{5}\)

    29.

    a \(d=h \csc \theta\)

    b 155.572 miles

    31.

    a \(0.78 \mathrm{sec}\)

    b \(l=8 t^2 \sin 2 \theta\)

    33. \(\sin \theta = \dfrac{7}{\sqrt{x^2 + 49}}, \cos \theta = \dfrac{x}{\sqrt{x^2 + 49}}, \tan \theta = \dfrac{7}{x}, \sec \theta = \dfrac{\sqrt{x^2 + 49}}{x}, \csc \theta = \dfrac{\sqrt{x^2 + 49}}{7}, \cot \theta = \dfrac{x}{7}\)

    35. \(\sin \theta = S, \cos \theta = \sqrt{1 - S^2}, \tan \theta = \dfrac{S}{\sqrt{1 - S^2}}, \sec \theta = \dfrac{1}{\sqrt{1 - S^2}}, \csc \theta = \dfrac{1}{S}, \cot \theta = \dfrac{\sqrt{1 - S^2}}{S}\)

    37. \(\sin \theta = \dfrac{-\sqrt{9 - a^2}}{3}, \cos \theta = \dfrac{a}{3}, \tan \theta = \dfrac{-\sqrt{9 - a^2}}{a}, \sec \theta = \dfrac{3}{a}, \csc \theta = \dfrac{-3}{\sqrt{9 - a^2}}, \cot \theta = \dfrac{-a}{\sqrt{9 - a^2}}\)

    39. \(A C, O A, B D, O D, O E, E F\)

    41.

    Screen Shot 2023-02-26 at 4.36.45 PM.png

    \begin{aligned}
    \sin \theta &= \dfrac{-\sqrt{3}}{2}, \quad \cos \theta = \dfrac{1}{2}, \\
    \tan \theta &= -\sqrt{3}, \quad \sec \theta = 2, \\
    \csc \theta &= \dfrac{-2\sqrt{3}}{3}, \quad \cot \theta = \dfrac{-\sqrt{3}}{3}
    \end{aligned}

    43.

    Screen Shot 2023-02-26 at 4.36.54 PM.png

    \begin{aligned}
    \sin \alpha &= \dfrac{1}{3}, \quad \cos \alpha = \dfrac{2\sqrt{2}}{3}, \\
    \tan \alpha &= \dfrac{\sqrt{2}}{4}, \quad \sec \alpha = \dfrac{3\sqrt{2}}{4}, \\
    \csc \alpha &= 3, \quad \cot \alpha = 2\sqrt{2}
    \end{aligned}

    45.

    Screen Shot 2023-02-26 at 4.37.06 PM.png

    \begin{aligned}
    & \sin \gamma=\dfrac{-4}{\sqrt{17}}, \quad \cos \gamma= \dfrac{-1}{\sqrt{17}},\\
    & \tan \gamma=4, \quad \sec \gamma= -\sqrt{17},\\
    & \csc \gamma=\dfrac{-\sqrt{17}}{4}, \quad \cot \gamma=\dfrac{1}{4}
    \end{aligned}

    47. \(\dfrac{4\sqrt{3}}{3} + 2\sqrt{2}\)

    49. \(\dfrac{\sqrt{3}}{3}\)

    51. \(\dfrac{4\sqrt{6}}{3} + \dfrac{10}{3}\)

    53.

    \(x\) 0 \(\dfrac{\pi}{4}\) \(\dfrac{\pi}{2}\) \(\dfrac{3\pi}{4}\) \(\pi\) \(\dfrac{5\pi}{4}\) \(\dfrac{3\pi}{2}\) \(\dfrac{7\pi}{4}\) \(2\pi\)
    \(\sec x\) 1 \(\sqrt{2}\) undefined \(-\sqrt{2}\) -1 \(-\sqrt{2}\) undefined \(\sqrt{2}\) 1

    Screen Shot 2023-02-26 at 6.28.01 PM.png

    55. Screen Shot 2023-02-26 at 6.32.18 PM.png

    57.

    \(x\) 0 \(\dfrac{\pi}{4}\) \(\dfrac{\pi}{2}\) \(\dfrac{3\pi}{4}\) \(\pi\) \(\dfrac{5\pi}{4}\) \(\dfrac{3\pi}{2}\) \(\dfrac{7\pi}{4}\) \(2\pi\)
    \(\cot x\) undefined 1 0 -1 undefined 1 0 -1 undefined

    Screen Shot 2023-02-26 at 6.34.13 PM.png

    59.

    \begin{aligned}
    \dfrac{\csc x}{\cot x} &= \dfrac{\frac{1}{\sin x}}{\frac{\cos x}{\sin x}} \\
    &= \dfrac{1}{\sin x} \div \dfrac{\cos x}{\sin x} \\
    &= \dfrac{1}{\sin x} \cdot \dfrac{\sin x}{\cos x} \\
    &= \dfrac{1}{\cos x} \\
    &= \sec x
    \end{aligned}

    61.

    \begin{aligned}
    \dfrac{\sec x \cot x}{\csc x} &= \dfrac{\frac{1}{\cos x} \cdot \frac{\cos x}{\sin x}}{\frac{1}{\sin x}} \\
    &= \dfrac{\frac{1}{\sin x}}{\frac{1}{\sin x}} \\
    &= 1
    \end{aligned}

    63.

    \begin{aligned}
    \tan x \csc x &= \dfrac{\sin x}{\cos x} \cdot \dfrac{1}{\sin x} \\
    &= \dfrac{1}{\cos x} =\sec x
    \end{aligned}

    65. \(\dfrac{\pi}{6}, \dfrac{5 \pi}{6}\)

    67. \(\dfrac{3 \pi}{4}, \dfrac{5 \pi}{4}\)

    69. \(\dfrac{5 \pi}{6}, \dfrac{11 \pi}{6}\)

    71. \(\dfrac{-\sqrt{5}}{5}\)

    73. \(\dfrac{\sqrt{a^2-4}}{2}\)

    75. \(\dfrac{\sqrt{w^2-1}}{-w}\)

    77. \(\sec s = \dfrac{-5}{4}, \quad \csc s = \dfrac{5}{3}, \quad \cot s = \dfrac{-4}{3}\)

    79. \(\sec s = \dfrac{1}{\sqrt{1-w^2}}, \quad \csc s = \dfrac{1}{w}, \quad \cot s = \dfrac{\sqrt{1-w^2}}{w}\)

    81. \(\dfrac{\sin \theta}{\cos ^2 \theta}\)

    83. \(\sec t\)

    85. \(\dfrac{1-\sin \beta}{\cos \beta}\)

    87. \(-\cos x\)

    89.

    \begin{aligned}
    \cos ^2 \theta+\sin ^2 \theta & =1 \\
    \dfrac{\cos ^2 \theta}{\cos ^2 \theta}+\dfrac{\sin ^2 \theta}{\cos ^2 \theta} & =\dfrac{1}{\cos ^2 \theta} \\
    1+\tan ^2 \theta & =\sec ^2 \theta
    \end{aligned}

    91.

    a \(\csc \theta=-\sqrt{26}\)

    b \(\sin \theta=\dfrac{-\sqrt{26}}{26}, \cos \theta=\dfrac{-5 \sqrt{26}}{26}, \tan \theta=\dfrac{1}{5}, \sec \theta=\dfrac{-\sqrt{26}}{5}\)

    93. \(\cos t=\pm \sqrt{1-\sin ^2 t}, \quad \tan t=\dfrac{\pm \sin t}{\sqrt{1-\sin ^2 t}}, \sec t=\dfrac{\pm 1}{\sqrt{1-\sin ^2 t}}, \csc t=\dfrac{1}{\sin t}, \cot t=\dfrac{\pm \sqrt{1-\sin ^2 t}}{\sin t}\)

    95.

    \begin{aligned}
    \dfrac{a}{\sin A} & =\dfrac{b}{\sin B}=\dfrac{c}{\sin C} \\
    a \cdot \dfrac{1}{\sin A} & =b \cdot \dfrac{1}{\sin B}=c \cdot \dfrac{1}{\sin C} \\
    a \csc A & =b \csc B=c \csc C
    \end{aligned}

    8.4 Chapter Summary and Review

    Review Problems

    1. False

    3. True

    5. False

    7. False

    9. \(\dfrac{2-\sqrt{21}}{5 \sqrt{2}}\)

    11.

    a \(\dfrac{5 \sqrt{33}-3}{32}\)

    b \(\dfrac{5 \sqrt{33}-3}{\sqrt{5}(3 \sqrt{3}+\sqrt{11})}\)

    13. 1

    15. \(\dfrac{\tan t+\sqrt{3}}{1-\sqrt{3} \tan t}\)

    17.

    a \(\dfrac{4}{5}\)

    b \(\dfrac{3}{5}\)

    c \(\dfrac{4}{3}\)

    d \(\dfrac{24}{25}\)

    e \(\dfrac{-7}{25}\)

    f \(\dfrac{-24}{7}\)

    19. \(\sin 9x\)

    21. \(\tan (2 \phi-2)\)

    23. \(\sin 8 \theta\)

    25.

    a \(1-2 \sin ^2 \theta-\sin \theta=1\)

    b \(0, \pi, \dfrac{7 \pi}{6}, \dfrac{11 \pi}{6}\)

    27. Screen Shot 2023-02-27 at 2.17.20 AM.png No

    29.

    a \(\dfrac{-\pi}{3}\)

    b \(\dfrac{2 \pi}{3}\)

    31.

    a \(\tan ^{-1}\left(\dfrac{52.8}{x}\right)\)

    b \(69.25^{\circ}, 27.83^{\circ}\)

    33. \(\theta=\sin ^{-1}\left(\dfrac{v_y+g t}{v_0}\right)\)

    35. \(\dfrac{2}{3}\)

    37. \(\sqrt{1-4 t^2}\)

    39. Because \(|\sin \theta| \leq 1, \sin ^{-1} t\) is undefined for \(|t|>1\). If \(x \neq 0\), then either \(|x|>1\) or \(\left|\frac{1}{x}\right|>1\). If \(x=0\), then \(\frac{1}{x}\) is undefined.

    41.

    a 2.203

    b −3.236

    c 0.466

    43.

    \begin{aligned}
    \sin \theta &= \dfrac{13}{\sqrt{313}}, \quad \cos \theta = \dfrac{12}{\sqrt{313}}, \quad \tan \theta = \dfrac{13}{12}, \\
    \sec \theta &= \dfrac{\sqrt{313}}{12}, \quad \csc \theta = \dfrac{\sqrt{313}}{13}, \quad \cot \theta = \dfrac{12}{13}
    \end{aligned}

    45.

    \begin{aligned}
    \sin \theta &= \dfrac{1}{3}, \quad \cos \theta = \dfrac{-2\sqrt{2}}{3}, \quad \tan \theta = \dfrac{-1}{2\sqrt{2}}, \\
    \sec \theta &= \dfrac{-3}{2\sqrt{2}}, \quad \csc \theta = 3, \quad \cot \theta = -2\sqrt{2}
    \end{aligned}

    47.

    \begin{aligned}
    \sin \theta &= \dfrac{-9}{\sqrt{106}}, \quad \cos \theta = \dfrac{-5}{\sqrt{106}}, \quad \tan \theta = \dfrac{9}{5} \\
    \sec \theta &= \dfrac{-\sqrt{106}}, \quad \csc \theta = \dfrac{-\sqrt{106}}{9}, \quad \cot \theta = \dfrac{5}{9}
    \end{aligned}

    49.

    \begin{aligned}
    \sin \alpha &= \dfrac{-\sqrt{11}}{6}, \quad \cos \alpha = \dfrac{-5}{6}, \quad \tan \alpha = \dfrac{\sqrt{11}}{5}, \\
    \sec \alpha &= \dfrac{-6}{5}, \quad \csc \alpha = \dfrac{-6}{\sqrt{11}}, \quad \cot \alpha = \dfrac{5}{\sqrt{11}}
    \end{aligned}

    51.

    \begin{aligned}
    \sin \theta &= \dfrac{s}{4}, \quad \cos \theta = \dfrac{\sqrt{16 - s^2}}{4}, \\
    \tan \theta &= \dfrac{s}{\sqrt{16-s^2}}, \quad \sec \theta = \dfrac{4}{\sqrt{16-s^2}}, \\
    \csc \theta &= \dfrac{4}{s}, \quad \cot \theta = \dfrac{\sqrt{16 - s^2}}{s}
    \end{aligned}

    53.

    \begin{aligned}
    \sin \theta &= \dfrac{w}{\sqrt{w^2+144}}, \quad \cos \theta = \dfrac{-12}{\sqrt{w^2+144}}, \\
    \tan \theta &= \dfrac{-w}{12}, \quad \sec \theta = \dfrac{-\sqrt{w^2+144}}{12}, \\
    \csc \theta &= \dfrac{\sqrt{w^2+144}}{w}, \quad \cot \theta = \dfrac{-12}{w}
    \end{aligned}

    55.

    \begin{aligned}
    \sin \alpha &= \dfrac{k}{2}, \quad \cos \alpha = \dfrac{-\sqrt{4-k^2}}{2}, \\
    \tan \alpha &= \dfrac{-k}{\sqrt{4-k^2}}, \quad \sec \alpha = \dfrac{-2}{\sqrt{4-k^2}}, \\
    \csc \alpha &= \dfrac{2}{k}, \quad \cot \alpha = \dfrac{-\sqrt{4-k^2}}{k}
    \end{aligned}

    57. \(\sin \theta=0.3, \cos \theta=-0.4, \tan \theta=-0.75, \sec \theta=-2.5, \csc \theta \approx 3.33, \cot \theta \approx-1.33\)

    59. -8

    61. \(\sqrt{2}\)

    63. \(\theta \approx 2.8, \theta \approx 0.30\)

    65. \(y=\csc x\) or \(y=\cot x\)

    67. \(y=\sec x\)

    69. \(y=\sec x\) or \(y=\csc x\)

    71. \(f(x)=\sin x-1\)

    73. \(G(x)=\tan x-1\)

    75. \(\cos ^2 x\)

    77. \(\cos ^2 B\)

    79. \(\csc \theta\)

    81. \(\sqrt{3} \tan \theta \sin \theta\)

    83.

    a \(A C=\tan \alpha, D C=\tan \beta, A D=\tan \alpha-\tan \beta\)

    b They are right triangles that share \(\angle B\).

    c \(\angle A=\angle F, \angle B\) is the complement of \(\angle A\), and \(\angle F D C\) is the complement of \(\angle F\).

    d \(\dfrac{C F}{C D}=\tan \alpha\), so \(C F=\tan \alpha \tan \beta\)

    e They are right triangles with \(\angle A=\angle F\).

    f \(\angle E B D=\alpha-\beta\), so \(\tan (\alpha-\beta)=\dfrac{\text { opp }}{\text { adj }}=\dfrac{D E}{B E} ; \dfrac{D E}{B E}\) and \(\dfrac{A D}{B F}\) are ratios of corresponding sides of similar triangles; \(A D=\tan \alpha-\tan \beta\) by part (a), \(B F=B C+C F=1+\tan \alpha \tan \beta\) by part (d).

    85. \(d=25 \csc 112^{\circ}, \alpha=45^{\circ}, a \approx 19.07, b \approx 10.54\)


    This page titled 11.7: More Functions and Identities is shared under a GNU Free Documentation License 1.3 license and was authored, remixed, and/or curated by Katherine Yoshiwara via source content that was edited to the style and standards of the LibreTexts platform; a detailed edit history is available upon request.

    • Was this article helpful?