1E: Exercises
( \newcommand{\kernel}{\mathrm{null}\,}\)
For every positive integer n, prove that 1(1)(2)+1(2)(3)+⋯+1(n)(n+1)=nn+1.
- Answer
-
We can rewrite each term as 1k(k+1)=k+1−kk(k+1)=1k−1k+1. Therefore, the sum telescopes as follows: 11−12+12−13+⋯+1n−1n+1=1−1n+1=nn+1.
For any positive integer n, prove that 2n32n−1 is always divisible by 17.
- Answer
-
By Fermat's Little Theorem, 216≡1(mod17)$and$316≡1(mod17). Therefore, 216n≡1(mod17) and 332n≡1(mod17). Hence, 2n32n−1≡1⋅1−1≡0(mod17).
a. Let a,b,c∈Z+. Show that gcd if and only if \gcd(a, b) = 1 and \gcd(a, c) = 1.
b. Let a,b,c,d \in \mathbb{Z}. If a|b and c|d, show that gcd(a,c)|gcd(b,d).
Show that a^5 \equiv a \pmod{5} for all integers a.
Using Euclidean algorithm to find \gcd(2520,154) and express \gcd(2520, 154) as an integer combination of 2520 and 154. Also,
Using the Euclidean algorithm to find \gcd(-2520,154) and express \gcd(-2520, 154) as an integer combination of -2520 and 154.
For every positive integer n, prove that n^3-n is divisible by 3.
For any k \in \mathbb{N} prove that \gcd(4k+3, 7k+5)=1.
a) Use the Euclidean algorithm to find the \gcd(-29,571)?
b) Find integers x and y s.t. \gcd(-29,571)= -29(x)+571(y)?
Show that any two consecutive odd integers are relatively prime.
If m,n are any odd integers, show that m^2-n^2 is divisible by 8.
a) Prove that for all integers n\geq 1,
\frac{1}{2!}+ \frac{2}{3!} + \cdots +\frac{n}{(n+1)!} = 1-\frac{1}{(n+1)!}.
b) Prove that for all integers n\geq 1,
\frac{1}{\sqrt{1}}+ \frac{1}{\sqrt{2}} + \cdots + \frac{1}{\sqrt{n}} \geq \sqrt{n}.
For integer n\geq 1, define
S_n=- {2 \choose 2}+{3 \choose 2}-{4 \choose 2}+{5 \choose 2}\cdots + {2n+1 \choose 2}.
-
Evaluate S_n for n=1,2,3,4 and 5.
-
Use part (a) to guess a formula for S_n.
-
Use mathematical induction to prove your guess.
Find the remainder when 8^{391} is divided by 5.
For each of the following pairs of integers a and n. show that a and n are relatively prime, determine multuplicative inverse of [a] in \mathbb{Z}_n, and Find all integers x for ax \cong 11 (mod \, n).
- a=16, n=35.
- a=69, n=89.
Find the remainder when (201)(203)(205)(207) is divided by 13.