2E: Exercises
( \newcommand{\kernel}{\mathrm{null}\,}\)
Check the following structures for the group properties:
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Z4 under addition.
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Z∗5 under multiplication.
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Z∗8 under multiplication.
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{±1,±i} under multiplication.
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Rotations that map a brick to itself.
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The four functions f(x)=x,g(x)=−x,h(x)=1x,j(x)=−1x under composition.
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The four matrices [1001],[−100−1],[100−1],[−1001] under multiplication.
- Answer
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5. If a,b,c denote rotations about three mutually perpendicular axes, then a2=b2=c2=e the identity rotation. Also ab=c,ac=b,bc=a Thus this group is isomorphic to K4.
Let H(C)={[1ab01c001]| a,b,c,∈C}.
Show that H(C) is a group under matrix multiplication. Demonstrate explicitly that H(C) is always non-abelian.
Let S=R∖{−1} and define a binary operation ⊕ on S by a⊕b=a+b+ab. Prove that (S,⊕) is an abelian group.
Given the groups R∗ and Z, let G=R∗×Z. Define a binary operation ⋆ by (a,m)⋆(b,n)=(ab,m+n). Show that (G,⋆) is a group under this operation.
Let G be a group. Show that if a2=e, for all elements of a∈G, then G must be abelian.
Let H consists of 2×2 matrices of the form [cos(x)−sin(x)sin(x)cos(x)], where x∈R. Prove that H is a subgroup of SL2(R).
Prove or disprove the following statements: Let H and K be subgroups of a group G.
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H∪K is a subgroup of G.
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H∩K is a subgroup of G.
Prove that for each element a∈G, where G is a group, the centralizer of a, C(a) is a subgroup of G. Prove that for each element a∈G, where G is a group, that C(a)=C(a−1).
Let G be a group. H={g2:g∈G}.
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Prove or disprove: If G is abelian then H is a subgroup.
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Prove or disprove: If H is a subgroup then G is abelian.
List the cyclic subgroups of U(30)={1,7,11,13,17,19,23,29}.
Show that U(20)≠<k> for any k in U(20). [Hence, U(20) is not cyclic.]
Decide whether U(10) is cyclic or not. Justify your answer.
Is (Z,+) cyclic group? If so, what are the possible generators?
Decide whether the following H is a subgroup of G. Justify your answer.
- H=N,G=Z
- H={1,3},G=Z∗10
- H={1,3},G=Z∗15
- H={(n,m)∈Z×Z|2∣(n+m)},G=Z×Z
Prove or disprove: If K is a subgroup of H and H is a subgroup of G then K is a subgroup of G.