4.0E: Exercises
This page is a draft and is under active development.
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Exercise 4.0.1
1. Define the term “antiderivative” in your own words
2. Is it more accurate to refer to “the” antiderivative of f(x) or “an” antiderivative of f(x)?
3. Use your own words to define the indefinite integral of f(x).
4. Fill in the blanks: “Inverse operations do the ____ things in the _____ order.”
5. What is an “initial value problem”?
6. The derivative of a position function is a _____ function.
7. The antiderivative of an acceleration function is a ______ function.
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Under Construction
Exercise 4.0.2
Evaluate the indefinite integrals:
1. ∫3x3dx
2. ∫x8dx
3. ∫(10x2−2)dx
4. ∫dt
5. ∫1ds
6. ∫13t2dt
7. ∫1t2dt
8. ∫1√xdx
9. ∫sec2θdθ
10. ∫sinθdθ
11. ∫(secxtanx+cscxcotx)dx
12. ∫5eθdθ
13. ∫3tdt
14. ∫5t2dt
15. ∫(2t+3)2dt
16. ∫(t2+3)(t3−2t)dt
17. ∫x2x3dx
18. ∫eπdx
19. ∫adx
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Under Construction
Exercise 4.0.3
This problem investigates why Theorem 35 states that ∫1xdx=ln|x|+C.
(a) What is the domain of y=lnx?
(b) Find ddx(lnx).
(c) What is the domain of y=ln(−x)?
(d) Find ddx((ln(−x)).
(e) You should find that 1/x has two types of antiderivatives, depending on whether x>0 or x<0. In one expression, give a formula for ∫1xdx that takes these different domains into account, and explain your answer.
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Under Construction
Exercise 4.0.4
Find f(x) described by the given initial value problem.
1. f′(x)=sinx and f(0)=2
2. f′(x)=5ex and f(0)=10
3. f′(x)=4x3−3x2 and f(−1)=9
4. f′(x)=sec2x and f(π/4)=5
5. f′(x)=7x and f(2)=1
6. f″(x)=5 and f′(0)=7,f(0)=3
7. f″(x)=7x and f′(1)=−1,f(1)=10
8. f″(x)=5ex and f′(0)=3,f(0)=5
9. f″(θ)=sinθ and f′(π)=2,f(π)=4
10. f″(x)=24x2+2x−cosx and f′(0)=5,f(0)=0
11. f″(x)=0 and f′(1)=3,f(1)=1
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Under Construction
Exercise 4.0.5
Use information gained from the first and second derivative to sketch f(x)=1ex+1.
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Under Construction
Exercise 4.0.6
Given y=x2excosx, find dy.
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Under Construction