14.3: Partial Differentiation
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When we first considered what the derivative of a vector function might mean, there was really not much difficulty in understanding either how such a thing might be computed or what it might measure. In the case of functions of two variables, things are a bit harder to understand. If we think of a function of two variables in terms of its graph, a surface, there is a more-or-less obvious derivative-like question we might ask, namely, how "steep'' is the surface. But it's not clear that this has a simple answer, nor how we might proceed. We will start with what seem to be very small steps toward the goal; surprisingly, it turns out that these simple ideas hold the keys to a more general understanding.
Imagine a particular point on a surface; what might we be able to say about how steep it is? We can limit the question to make it more familiar: how steep is the surface in a particular direction? What does this even mean? Here's one way to think of it: Suppose we're interested in the point
In principle, this is a problem we know how to solve: find the slope of a curve in a plane. Let's start by looking at some particularly easy lines: those parallel to the
Consider again the parabolic surface
If, say, we're interested in the point
If we're interested in some other line
The partial derivative with respect to
Of course, we can do the same sort of calculation for lines parallel to the
The partial derivative with respect to
So far, using no new techniques, we have succeeded in measuring the slope of a surface in two quite special directions. For functions of one variable, the derivative is closely linked to the notion of tangent line. For surfaces, the analogous idea is the tangent plane---a plane that just touches a surface at a point, and has the same "steepness'' as the surface in all directions. Even though we haven't yet Figured out how to compute the slope in all directions, we have enough information to find tangent planes. Suppose we want the plane tangent to a surface at a particular point
How can we discover an equation for this tangent plane? We know a point on the plane,
How can we find vectors parallel to the tangent lines? Consider first the line tangent to the surface above the line
Now to find the desired normal vector we compute the cross product,
Find the plane tangent to
Solution
This point is on the upper hemisphere, so we use
The hemisphere and this tangent plane are pictured in Figure
So it appears that to find a tangent plane, we need only find two quite simple ordinary derivatives, namely
When does a surface have a tangent plane at a particular point? What we really want from a tangent plane, as from a tangent line, is that the plane be a "good'' approximation of the surface near the point. Here is how we can make this precise:
Let
and both
This definition takes a bit of absorbing. Let's rewrite the central equation a bit:
The first three terms on the right are the equation of the tangent plane, that is,
is the
We can see that the extra condition on
or
Now taking the limit of the two sides as
Contributors
Integrated by Justin Marshall.