4.7: Composite functions
( \newcommand{\kernel}{\mathrm{null}\,}\)
Similar to the way in which we used transformations to analyze the equation of a function, it is sometimes helpful to consider a given function as being several functions of the variable combined together.
For example, instead of thinking of the function f(x)=(2x−7)3 as being a single function, we can think of it as being two functions:
g(x)=2x−7 and h(x)=x3
Then f(x) is the combination or "composition" of these two functions together. The first function multiplies the variable by 2, and subtracts 7 from the result. The second function takes this answer and raises it to the third power. The notation for the composition of functions is an open circle: 0
In the example above we would say that the function f(x)=(2x−7)3 is equivalent to the composition h∘g(x) or h(g(x)). The order of function composition is important. The function g∘h(x) would be equivalent to g(h(x)), which would be
equal to g(x3)=2(x3)−7=2x3−7
Exercises 4.7
Find f∘g(x) and g∘f(x) for each of the following problems.
1) f(x)=x2g(x)=x−1
2) f(x)=|x−3|g(x)=2x+3
3) f(x)=xx−2g(x)=x+3x
4) \(\quad f(x)=x^{3}-1 \\ g(x)=\frac{1}{x^{3}+1\)
5) f(x)=√x+1g(x)=x4−1
6) \(\quad f(x)=2 x^{3}-1 \\ g(x)=\sqrt[3]{\frac{x+1}{2}\)
Find functions f(x) and g(x) so that the given function h(x)=f∘g(x)
7) h(x)=(3x+1)2
8) h(x)=(x2−2x)3
9) h(x)=√1−4x
10) h(x)=3√x2−1
11) h(x)=(x+1x−1)2
12) h(x)=(1−2x1+2x)3
13) h(x)=(3x2−1)−3
14) h(x)=(1+1x)−2
15) h(x)=√xx−1
16) h(x)=3√x−1x
17) h(x)=√(x2−x−1)3
18) h(x)=3√(1−x4)2
19) h(x)=2√4−x2
20) h(x)=−(3x−1)5
21) A spherical weather balloon is inflated so that the radius at time t is given by the equation:
r=f(t)=12t+2
Assume that r is in meters and t is in seconds, with t=0 corresponding to the time the balloon begins to be inflated. If the volume of a sphere is given by the formula:
v(r)=43πr3
Find V(f(t)) and use this to compute the time at which the volume of the balloon is 36πm3