Skip to main content
Mathematics LibreTexts

1.27: Percents Part 3

  • Page ID
    153131
  • \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)

    \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)

    \( \newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\)

    ( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\)

    \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)

    \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\)

    \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)

    \( \newcommand{\Span}{\mathrm{span}}\)

    \( \newcommand{\id}{\mathrm{id}}\)

    \( \newcommand{\Span}{\mathrm{span}}\)

    \( \newcommand{\kernel}{\mathrm{null}\,}\)

    \( \newcommand{\range}{\mathrm{range}\,}\)

    \( \newcommand{\RealPart}{\mathrm{Re}}\)

    \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)

    \( \newcommand{\Argument}{\mathrm{Arg}}\)

    \( \newcommand{\norm}[1]{\| #1 \|}\)

    \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)

    \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\AA}{\unicode[.8,0]{x212B}}\)

    \( \newcommand{\vectorA}[1]{\vec{#1}}      % arrow\)

    \( \newcommand{\vectorAt}[1]{\vec{\text{#1}}}      % arrow\)

    \( \newcommand{\vectorB}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)

    \( \newcommand{\vectorC}[1]{\textbf{#1}} \)

    \( \newcommand{\vectorD}[1]{\overrightarrow{#1}} \)

    \( \newcommand{\vectorDt}[1]{\overrightarrow{\text{#1}}} \)

    \( \newcommand{\vectE}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{\mathbf {#1}}}} \)

    \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)

    \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)

    \(\newcommand{\avec}{\mathbf a}\) \(\newcommand{\bvec}{\mathbf b}\) \(\newcommand{\cvec}{\mathbf c}\) \(\newcommand{\dvec}{\mathbf d}\) \(\newcommand{\dtil}{\widetilde{\mathbf d}}\) \(\newcommand{\evec}{\mathbf e}\) \(\newcommand{\fvec}{\mathbf f}\) \(\newcommand{\nvec}{\mathbf n}\) \(\newcommand{\pvec}{\mathbf p}\) \(\newcommand{\qvec}{\mathbf q}\) \(\newcommand{\svec}{\mathbf s}\) \(\newcommand{\tvec}{\mathbf t}\) \(\newcommand{\uvec}{\mathbf u}\) \(\newcommand{\vvec}{\mathbf v}\) \(\newcommand{\wvec}{\mathbf w}\) \(\newcommand{\xvec}{\mathbf x}\) \(\newcommand{\yvec}{\mathbf y}\) \(\newcommand{\zvec}{\mathbf z}\) \(\newcommand{\rvec}{\mathbf r}\) \(\newcommand{\mvec}{\mathbf m}\) \(\newcommand{\zerovec}{\mathbf 0}\) \(\newcommand{\onevec}{\mathbf 1}\) \(\newcommand{\real}{\mathbb R}\) \(\newcommand{\twovec}[2]{\left[\begin{array}{r}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\ctwovec}[2]{\left[\begin{array}{c}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\threevec}[3]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\cthreevec}[3]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\fourvec}[4]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\cfourvec}[4]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\fivevec}[5]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\cfivevec}[5]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\mattwo}[4]{\left[\begin{array}{rr}#1 \amp #2 \\ #3 \amp #4 \\ \end{array}\right]}\) \(\newcommand{\laspan}[1]{\text{Span}\{#1\}}\) \(\newcommand{\bcal}{\cal B}\) \(\newcommand{\ccal}{\cal C}\) \(\newcommand{\scal}{\cal S}\) \(\newcommand{\wcal}{\cal W}\) \(\newcommand{\ecal}{\cal E}\) \(\newcommand{\coords}[2]{\left\{#1\right\}_{#2}}\) \(\newcommand{\gray}[1]{\color{gray}{#1}}\) \(\newcommand{\lgray}[1]{\color{lightgray}{#1}}\) \(\newcommand{\rank}{\operatorname{rank}}\) \(\newcommand{\row}{\text{Row}}\) \(\newcommand{\col}{\text{Col}}\) \(\renewcommand{\row}{\text{Row}}\) \(\newcommand{\nul}{\text{Nul}}\) \(\newcommand{\var}{\text{Var}}\) \(\newcommand{\corr}{\text{corr}}\) \(\newcommand{\len}[1]{\left|#1\right|}\) \(\newcommand{\bbar}{\overline{\bvec}}\) \(\newcommand{\bhat}{\widehat{\bvec}}\) \(\newcommand{\bperp}{\bvec^\perp}\) \(\newcommand{\xhat}{\widehat{\xvec}}\) \(\newcommand{\vhat}{\widehat{\vvec}}\) \(\newcommand{\uhat}{\widehat{\uvec}}\) \(\newcommand{\what}{\widehat{\wvec}}\) \(\newcommand{\Sighat}{\widehat{\Sigma}}\) \(\newcommand{\lt}{<}\) \(\newcommand{\gt}{>}\) \(\newcommand{\amp}{&}\) \(\definecolor{fillinmathshade}{gray}{0.9}\)
    karim-manjra-07NDEeH3lR4-unsplash-300x240.jpg
    Photo by Karim Manjra on Unsplash

    You may use a calculator throughout this module.

    There is one more situation involving percents that often trips people up: working backwards from the result of a percent change to find the original value.

    \(\text{Amount}=\text{Rate}\cdot\text{Base}\)

    \(A=R\cdot{B}\)

    Finding the Base After a Percent Increase

    Suppose a \(12\%\) tax is added to a price; what percent of the original is the new amount?

    Well, the original number is \(100\%\) of itself, so the new amount must be \(100\%+12\%=112\%\) of the original.

    As a proportion, \(\dfrac{A}{B}=\dfrac{112}{100}\).

    As an equation, \(A=1.12\cdot{B}\).

    A very common error is to find \(12\%\) of the new amount and subtract that from the new amount. However, this doesn’t give the correct result. Instead, we must divide the new amount by \(112\%\).

    If an unknown number is increased by a percent, add that percent to \(100\%\) and use that result for the rate.

    \(\dfrac{\text{new amount}}{\text{unknown base}}=\dfrac{100+\text{percent}}{100}\)

    Exercises
    1. A sales tax of \(8\%\) is added to the selling price of a lawn tractor, making the total price \($1,402.92\). What is the selling price of the lawn tractor without tax?
    2. Clackamas Community College’s enrollment in Fall 2023 was \(17,605\) students, which was an increase of \(18.465\%\) from Fall 2022. What was the enrollment in Fall 2022?
    3. While your author and his children were stuck overnight at the Seattle airport, they bought three 20-ounce bottles of Sprite for \($11.86\), but the prices weren’t shown and they weren’t given a receipt. Suspecting that the sales tax rate was \(10.1\%\) from previous experience, your author was able to figure out the cost of one Sprite. Can you?

    Finding the Base After a Percent Decrease

    Suppose a \(12\%\) discount is applied to a price; what percent of the original is the new amount?

    As above, the original number is \(100\%\) of itself, so the new amount must be \(100\%-12\%=88\%\) of the original.

    As a proportion, \(\dfrac{A}{B}=\dfrac{88}{100}\).

    As an equation, \(A=0.88\cdot{B}\).

    As above, the most common error people make is finding \(12\%\) of the new amount and adding that to the new amount, but this doesn’t give the correct result. Instead, we must divide the new amount by \(88\%\).

    If an unknown number is decreased by a percent, subtract that percent from \(100\%\) and use that result for the rate.

    \(\dfrac{\text{new amount}}{\text{unknown base}}=\dfrac{100-\text{percent}}{100}\)

    Exercises
    1. A city department’s budget was cut by \(5.00\%\) this year. If this year’s budget is \($3.04\) million, what was last year’s budget?
    2. The estimated population of San Francisco in July 2022 was \(808,400\) people, which was a decrease of \(7.50\%\) from April 2020. What was the estimated population in April 2020? (Round to the nearest hundred people.)[1]
    3. An educational website claims that by purchasing access for \($5\), you’ll save \(69\%\) off the standard price. What is the standard price?

    1. Source: www.census.gov/quickfacts/fact/table/sanfranciscocitycalifornia/PST045222

    1.27: Percents Part 3 is shared under a CC BY-NC-SA 4.0 license and was authored, remixed, and/or curated by LibreTexts.

    • Was this article helpful?