2.1: Functions and Function Notation
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Determining Whether a Relation Represents a Function
A relation is a set of ordered pairs. The set of the first components of each ordered pair is called the domain and the set of the second components of each ordered pair is called the range. Consider the following set of ordered pairs. The first numbers in each pair are the first five natural numbers. The second number in each pair is twice that of the first.
\[\{(1, 2), (2, 4), (3, 6), (4, 8), (5, 10)\}\tag{1.1.1}\]
The domain is \(\{1, 2, 3, 4, 5\}\). The range is \(\{2, 4, 6, 8, 10\}\).
Note that each value in the domain is also known as an input value, or independent variable , and is often labeled with the lowercase letter \(x\). Each value in the range is also known as an output value, or dependent variable , and is often labeled lowercase letter \(y\).
A function \(f\) is a relation that assigns a single value in the range to each value in the domain. In other words, no \(x\)-values are repeated. For our example that relates the first five natural numbers to numbers double their values, this relation is a function because each element in the domain, {1, 2, 3, 4, 5}, is paired with exactly one element in the range, \(\{2, 4, 6, 8, 10\}\).
Now let’s consider the set of ordered pairs that relates the terms “even” and “odd” to the first five natural numbers. It would appear as
\[\mathrm{\{(odd, 1), (even, 2), (odd, 3), (even, 4), (odd, 5)\}} \tag{1.1.2}\]
Notice that each element in the domain, {even, odd} is not paired with exactly one element in the range, \(\{1, 2, 3, 4, 5\}\). For example, the term “odd” corresponds to three values from the range, \(\{1, 3, 5\},\) and the term “even” corresponds to two values from the range, \(\{2, 4\}\). This violates the definition of a function, so this relation is not a function.
Figure \(\PageIndex{1}\) compares relations that are functions and not functions.
Function
A function is a relation in which each possible input value leads to exactly one output value. We say “the output is a function of the input.”
The input values make up the domain , and the output values make up the range .
How To: Given a relationship between two quantities, determine whether the relationship is a function
- Identify the input values.
- Identify the output values.
- If each input value leads to only one output value, classify the relationship as a function. If any input value leads to two or more outputs, do not classify the relationship as a function.
Example \(\PageIndex{1}\): Determining If Menu Price Lists Are Functions
The coffee shop menu, shown in Figure \(\PageIndex{2}\) consists of items and their prices.
- Is price a function of the item?
- Is the item a function of the price?
Solution
- Let’s begin by considering the input as the items on the menu. The output values are then the prices. See Figure \(\PageIndex{3}\).
Each item on the menu has only one price, so the price is a function of the item.
- Two items on the menu have the same price. If we consider the prices to be the input values and the items to be the output, then the same input value could have more than one output associated with it. See Figure \(\PageIndex{4}\).
Therefore, the item is a not a function of price.
Example \(\PageIndex{2}\): Determining If Class Grade Rules Are Functions
In a particular math class, the overall percent grade corresponds to a grade point average. Is grade point average a function of the percent grade? Is the percent grade a function of the grade point average? Table \(\PageIndex{1}\) shows a possible rule for assigning grade points.
| Percent grade | 0–56 | 57–61 | 62–66 | 67–71 | 72–77 | 78–86 | 87–91 | 92–100 |
| Grade point average | 0.0 | 1.0 | 1.5 | 2.0 | 2.5 | 3.0 | 3.5 | 4.0 |
Solution
For any percent grade earned, there is an associated grade point average, so the grade point average is a function of the percent grade. In other words, if we input the percent grade, the output is a specific grade point average.
In the grading system given, there is a range of percent grades that correspond to the same grade point average. For example, students who receive a grade point average of 3.0 could have a variety of percent grades ranging from 78 all the way to 86. Thus, percent grade is not a function of grade point average.
Exercise \(\PageIndex{2}\)
Table \(\PageIndex{2}\) lists the five greatest baseball players of all time in order of rank.
| Player | Rank |
|---|---|
| Babe Ruth | 1 |
| Willie Mays | 2 |
| Ty Cobb | 3 |
| Walter Johnson | 4 |
| Hank Aaron | 5 |
- Is the rank a function of the player name?
- Is the player name a function of the rank?
- Answer a
-
Yes
- Answer b
-
yes. (Note: If two players had been tied for, say, 4th place, then the name would not have been a function of rank.)
Using Function Notation
Once we determine that a relationship is a function, we need to display and define the functional relationships so that we can understand and use them, and sometimes also so that we can program them into computers. There are various ways of representing functions. A standard function notation is one representation that facilitates working with functions.
To represent “height is a function of age,” we start by identifying the descriptive variables \(h\) for height and \(a\) for age. The letters \(f\), \(g\),and \(h\) are often used to represent functions just as we use \(x\), \(y\),and \(z\) to represent numbers and \(A\), \(B\), and \(C\) to represent sets.
\[\begin{array}{ll} h \text{ is } f \text{ of }a \;\;\;\;\;\; & \text{We name the function }f \text{; height is a function of age.} \\ h=f(a) & \text{We use parentheses to indicate the function input.} \\ f(a) & \text{We name the function }f \text{ ; the expression is read as “ }f \text{ of }a \text{.”}\end{array}\]
Remember, we can use any letter to name the function; the notation \(h(a)\) shows us that \(h\) depends on \(a\). The value \(a\) must be put into the function \(h\) to get a result. The parentheses indicate that age is input into the function; they do not indicate multiplication.
We can also give an algebraic expression as the input to a function. For example \(f(a+b)\) means “first add \(a\) and \(b\), and the result is the input for the function \(f\).” The operations must be performed in this order to obtain the correct result.
Function Notation
The notation \(y=f(x)\) defines a function named \(f\). This is read as “\(y\) is a function of \(x\).” The letter \(x\) represents the input value, or independent variable. The letter \(y\), or \(f(x)\), represents the output value, or dependent variable.
Example \(\PageIndex{3}\): Using Function Notation for Days in a Month
Use function notation to represent a function whose input is the name of a month and output is the number of days in that month.
Solution
Using Function Notation for Days in a Month
Use function notation to represent a function whose input is the name of a month and output is the number of days in that month.
The number of days in a month is a function of the name of the month, so if we name the function \(f\), we write \(\text{days}=f(\text{month})\) or \(d=f(m)\). The name of the month is the input to a “rule” that associates a specific number (the output) with each input.
For example, \(f(\text{March})=31\), because March has 31 days. The notation \(d=f(m)\) reminds us that the number of days, \(d\) (the output), is dependent on the name of the month, \(m\) (the input).
Analysis
Note that the inputs to a function do not have to be numbers; function inputs can be names of people, labels of geometric objects, or any other element that determines some kind of output. However, most of the functions we will work with in this book will have numbers as inputs and outputs.
Example \(\PageIndex{3B}\): Interpreting Function Notation
A function \(N=f(y)\) gives the number of police officers, \(N\), in a town in year \(y\). What does \(f(2005)=300\) represent?
Solution
When we read \(f(2005)=300\), we see that the input year is 2005. The value for the output, the number of police officers \((N)\), is 300. Remember, \(N=f(y)\). The statement \(f(2005)=300\) tells us that in the year 2005 there were 300 police officers in the town.
Exercise \(\PageIndex{3}\)
Use function notation to express the weight of a pig in pounds as a function of its age in days \(d\).
- Answer
-
\(w=f(d)\)
Q&A
Instead of a notation such as \(y=f(x)\), could we use the same symbol for the output as for the function, such as \(y=y(x)\), meaning “\(y\) is a function of \(x\)?”
Yes, this is often done, especially in applied subjects that use higher math, such as physics and engineering. However, in exploring math itself we like to maintain a distinction between a function such as \(f\) , which is a rule or procedure, and the output y we get by applying \(f\) to a particular input \(x\) . This is why we usually use notation such as \(y=f(x),P=W(d)\) , and so on.
Finding Input and Output Values of a Function
When we know an input value and want to determine the corresponding output value for a function, we evaluate the function. Evaluating will always produce one result because each input value of a function corresponds to exactly one output value.
When we know an output value and want to determine the input values that would produce that output value, we set the output equal to the function’s formula and solve for the input. Solving can produce more than one solution because different input values can produce the same output value.
Evaluation of Functions in Algebraic Forms
When we have a function in formula form, it is usually a simple matter to evaluate the function. For example, the function \(f(x)=5−3x^2\) can be evaluated by squaring the input value, multiplying by 3, and then subtracting the product from 5.
How To: Given the formula for a function, evaluate.
Given the formula for a function, evaluate.
- Replace the input variable in the formula with the value provided.
- Calculate the result.
Example \(\PageIndex{6A}\): Evaluating Functions at Specific Values
1. Evaluate \(f(x)=x^2+3x−4\) at
- \(2\)
- \(a\)
- \(a+h\)
- Evaluate \(\frac{f(a+h)−f(a)}{h}\)
Solution
Replace the x in the function with each specified value.
a. Because the input value is a number, 2, we can use simple algebra to simplify.
\[\begin{align*}f(2)&=2^2+3(2)−4\\&=4+6−4\\ &=6\end{align*}\]
b. In this case, the input value is a letter so we cannot simplify the answer any further.
\[f(a)=a^2+3a−4\nonumber\]
c. With an input value of \(a+h\), we must use the distributive property.
\[\begin{align*}f(a+h)&=(a+h)^2+3(a+h)−4\\&=a^2+2ah+h^2+3a+3h−4 \end{align*}\]
d. In this case, we apply the input values to the function more than once, and then perform algebraic operations on the result. We already found that
\[f(a+h)=a^2+2ah+h^2+3a+3h−4\nonumber\]
and we know that
\[f(a)=a^2+3a−4 \nonumber\]
Now we combine the results and simplify.
\[\begin{align*}\dfrac{f(a+h)−f(a)}{h}&=\dfrac{(a^2+2ah+h^2+3a+3h−4)−(a^2+3a−4)}{h}\\ &=\dfrac{(2ah+h^2+3h)}{h} \\ &=\dfrac{h(2a+h+3)}{h} & &\text{Factor out h.}\\ &=2a+h+3 & & \text{Simplify.}\end{align*}\]
Example \(\PageIndex{6B}\): Evaluating Functions
Given the function \(h(p)=p^2+2p\), evaluate \(h(4)\).
Solution
To evaluate \(h(4)\), we substitute the value 4 for the input variable p in the given function.
\[\begin{align*}h(p)&=p^2+2p\\h(4)&=(4)^2+2(4)\\ &=16+8\\&=24\end{align*}\]
Therefore, for an input of 4, we have an output of 24.
Exercise \(\PageIndex{6}\)
Given the function \(g(m)=\sqrt{m−4}\), evaluate \(g(5)\).
- Answer
-
\(g(5)=1\)
Example \(\PageIndex{7}\): Solving Functions
Given the function \(h(p)=p^2+2p\), solve for \(h(p)=3\).
Solution
\[\begin{array}{rl} h(p)=3\\p^2+2p=3 & \text{Substitute the original function}\\ p^2+2p−3=0 & \text{Subtract 3 from each side.}\\(p+3)(p−1)=0&\text{Factor.}\end{array} \nonumber \]
If \((p+3)(p−1)=0\), either \((p+3)=0\) or \((p−1)=0\) (or both of them equal \(0\)). We will set each factor equal to \(0\) and solve for \(p\) in each case.
\[(p+3)=0,\; p=−3 \nonumber \]
\[(p−1)=0,\, p=1 \nonumber\]
This gives us two solutions. The output \(h(p)=3\) when the input is either \(p=1\) or \(p=−3\). We can also verify by graphing as in Figure \(\PageIndex{6}\). The graph verifies that \(h(1)=h(−3)=3\) and \(h(4)=24\).
Exercise \(\PageIndex{7}\)
Given the function \(g(m)=\sqrt{m−4}\), solve \(g(m)=2\).
- Answer
-
\(m=8\)
Evaluation of Functions in Algebraic Forms
When we have a function in formula form, it is usually a simple matter to evaluate the function. For example, the function \(f(x)=5−3x^2\) can be evaluated by squaring the input value, multiplying by 3, and then subtracting the product from 5.
How To: Given the formula for a function, evaluate.
Given the formula for a function, evaluate.
- Replace the input variable in the formula with the value provided.
- Calculate the result.
Example \(\PageIndex{6A}\): Evaluating Functions at Specific Values
1. Evaluate \(f(x)=x^2+3x−4\) at
- \(2\)
- \(a\)
- \(a+h\)
- Evaluate \(\frac{f(a+h)−f(a)}{h}\)
Solution
Replace the x in the function with each specified value.
a. Because the input value is a number, 2, we can use simple algebra to simplify.
\[\begin{align*}f(2)&=2^2+3(2)−4\\&=4+6−4\\ &=6\end{align*}\]
b. In this case, the input value is a letter so we cannot simplify the answer any further.
\[f(a)=a^2+3a−4\nonumber\]
c. With an input value of \(a+h\), we must use the distributive property.
\[\begin{align*}f(a+h)&=(a+h)^2+3(a+h)−4\\&=a^2+2ah+h^2+3a+3h−4 \end{align*}\]
d. In this case, we apply the input values to the function more than once, and then perform algebraic operations on the result. We already found that
\[f(a+h)=a^2+2ah+h^2+3a+3h−4\nonumber\]
and we know that
\[f(a)=a^2+3a−4 \nonumber\]
Now we combine the results and simplify.
\[\begin{align*}\dfrac{f(a+h)−f(a)}{h}&=\dfrac{(a^2+2ah+h^2+3a+3h−4)−(a^2+3a−4)}{h}\\ &=\dfrac{(2ah+h^2+3h)}{h} \\ &=\dfrac{h(2a+h+3)}{h} & &\text{Factor out h.}\\ &=2a+h+3 & & \text{Simplify.}\end{align*}\]
Example \(\PageIndex{6B}\): Evaluating Functions
Given the function \(h(p)=p^2+2p\), evaluate \(h(4)\).
Solution
To evaluate \(h(4)\), we substitute the value 4 for the input variable p in the given function.
\[\begin{align*}h(p)&=p^2+2p\\h(4)&=(4)^2+2(4)\\ &=16+8\\&=24\end{align*}\]
Therefore, for an input of 4, we have an output of 24.
Exercise \(\PageIndex{6}\)
Given the function \(g(m)=\sqrt{m−4}\), evaluate \(g(5)\).
- Answer
-
\(g(5)=1\)
Example \(\PageIndex{7}\): Solving Functions
Given the function \(h(p)=p^2+2p\), solve for \(h(p)=3\).
Solution
\[\begin{array}{rl} h(p)=3\\p^2+2p=3 & \text{Substitute the original function}\\ p^2+2p−3=0 & \text{Subtract 3 from each side.}\\(p+3)(p−1)=0&\text{Factor.}\end{array} \nonumber \]
If \((p+3)(p−1)=0\), either \((p+3)=0\) or \((p−1)=0\) (or both of them equal \(0\)). We will set each factor equal to \(0\) and solve for \(p\) in each case.
\[(p+3)=0,\; p=−3 \nonumber \]
\[(p−1)=0,\, p=1 \nonumber\]
This gives us two solutions. The output \(h(p)=3\) when the input is either \(p=1\) or \(p=−3\). We can also verify by graphing as in Figure \(\PageIndex{6}\). The graph verifies that \(h(1)=h(−3)=3\) and \(h(4)=24\).
Exercise \(\PageIndex{7}\)
Given the function \(g(m)=\sqrt{m−4}\), solve \(g(m)=2\).
- Answer
-
\(m=8\)
Evaluating Functions Expressed in Formulas
Some functions are defined by mathematical rules or procedures expressed in equation form. If it is possible to express the function output with a formula involving the input quantity, then we can define a function in algebraic form. For example, the equation \(2n+6p=12\) expresses a functional relationship between \(n\) and \(p\). We can rewrite it to decide if \(p\) is a function of \(n\).
How to: Given a function in equation form, write its algebraic formula.
- Solve the equation to isolate the output variable on one side of the equal sign, with the other side as an expression that involves only the input variable.
- Use all the usual algebraic methods for solving equations, such as adding or subtracting the same quantity to or from both sides, or multiplying or dividing both sides of the equation by the same quantity.
Example \(\PageIndex{8A}\): Finding an Equation of a Function
Express the relationship \(2n+6p=12\) as a function \(p=f(n)\), if possible.
Solution
To express the relationship in this form, we need to be able to write the relationship where \(p\) is a function of \(n\), which means writing it as \(p=[\text{expression involving }n]\).
\[\begin{align*}2n+6p&=12 \\ 6p&=12−2n && \text{Subtract 2n from both sides.} \\ p&=\dfrac{12−2n}{6} & &\text{Divide both sides by 6 and simplify.} \\ p&=\frac{12}{6}−\frac{2n}{6} \\ p&=2−\frac{1}{3}n\end{align*}\]
Therefore, \(p\) as a function of \(n\) is written as
\[p=f(n)=2−\frac{1}{3}n \nonumber\]
Analysis
It is important to note that not every relationship expressed by an equation can also be expressed as a function with a formula.
Example \(\PageIndex{8B}\): Expressing the Equation of a Circle as a Function
Does the equation \(x^2+y^2=1\) represent a function with \(x\) as input and \(y\) as output? If so, express the relationship as a function \(y=f(x)\).
Solution
First we subtract \(x^2\) from both sides.
\[y^2=1−x^2 \nonumber\]
We now try to solve for \(y\) in this equation.
\[y=\pm\sqrt{1−x^2} \nonumber\]
\[\text{so, }y=\sqrt{1−x^2}\;\text{and}\;y = −\sqrt{1−x^2} \nonumber\]
We get two outputs corresponding to the same input, so this relationship cannot be represented as a single function \(y=f(x)\).
Exercise \(\PageIndex{8}\)
If \(x−8y^3=0\), express \(y\) as a function of \(x\).
- Answer
-
\(y=f(x)=\dfrac{\sqrt[3]{x}}{2}\)
Q & A
Are there relationships expressed by an equation that do represent a function but which still cannot be represented by an algebraic formula?
Yes, this can happen. For example, given the equation \(x=y+2^y\), if we want to express y as a function of x, there is no simple algebraic formula involving only \(x\) that equals \(y\). However, each \(x\) does determine a unique value for \(y\), and there are mathematical procedures by which \(y\) can be found to any desired accuracy. In this case, we say that the equation gives an implicit (implied) rule for \(y\) as a function of \(x\), even though the formula cannot be written explicitly.
Evaluating a Function Given in Tabular Form
As we saw above, we can represent functions in tables. Conversely, we can use information in tables to write functions, and we can evaluate functions using the tables. For example, how well do our pets recall the fond memories we share with them? There is an urban legend that a goldfish has a memory of 3 seconds, but this is just a myth. Goldfish can remember up to 3 months, while the beta fish has a memory of up to 5 months. And while a puppy’s memory span is no longer than 30 seconds, the adult dog can remember for 5 minutes. This is meager compared to a cat, whose memory span lasts for 16 hours.
The function that relates the type of pet to the duration of its memory span is more easily visualized with the use of a table (Table \(\PageIndex{10}\)).
| Pet Memory | span in hours |
|---|---|
| Puppy | 0.008 |
| Adult Dog | 0.083 |
| Cat | 3 |
| Goldfish | 2160 |
| Beta Fish | 3600 |
At times, evaluating a function in table form may be more useful than using equations. Here let us call the function \(P\). The domain of the function is the type of pet and the range is a real number representing the number of hours the pet’s memory span lasts. We can evaluate the function \(P\) at the input value of “goldfish.” We would write \(P(goldfish)=2160\). Notice that, to evaluate the function in table form, we identify the input value and the corresponding output value from the pertinent row of the table. The tabular form for function P seems ideally suited to this function, more so than writing it in paragraph or function form.
How To: Given a function represented by a table, identify specific output and input values
1. Find the given input in the row (or column) of input values.
2. Identify the corresponding output value paired with that input value.
3. Find the given output values in the row (or column) of output values, noting every time that output value appears.
4. Identify the input value(s) corresponding to the given output value.
Example \(\PageIndex{9}\): Evaluating and Solving a Tabular Function
Using Table \(\PageIndex{11}\),
a. Evaluate \(g(3)\).
b. Solve \(g(n)=6\).
| \(n\) | 1 | 2 | 3 | 4 | 5 |
| \(g(n)\) | 8 | 6 | 7 | 6 | 8 |
Solution
a. Evaluating \(g(3)\) means determining the output value of the function \(g\) for the input value of \(n=3\). The table output value corresponding to \(n=3\) is 7, so \(g(3)=7\).
b. Solving \(g(n)=6\) means identifying the input values, n,that produce an output value of 6. Table \(\PageIndex{12}\) shows two solutions: 2 and 4.
| \(n\) | 1 | 2 | 3 | 4 | 5 |
| \(g(n)\) | 8 | 6 | 7 | 6 | 8 |
When we input 2 into the function \(g\), our output is 6. When we input 4 into the function \(g\), our output is also 6.
Exercise \(\PageIndex{1}\)
Using Table \(\PageIndex{12}\), evaluate \(g(1)\).
- Answer
-
\(g(1)=8\)
Finding Function Values from a Graph
Evaluating a function using a graph also requires finding the corresponding output value for a given input value, only in this case, we find the output value by looking at the graph. Solving a function equation using a graph requires finding all instances of the given output value on the graph and observing the corresponding input value(s).
Example \(\PageIndex{10}\): Reading Function Values from a Graph
Given the graph in Figure \(\PageIndex{7}\),
- Evaluate \(f(2)\).
- Solve \(f(x)=4\).
Solution
To evaluate \(f(2)\), locate the point on the curve where \(x=2\), then read the y-coordinate of that point. The point has coordinates \((2,1)\), so \(f(2)=1\). See Figure \(\PageIndex{8}\).
To solve \(f(x)=4\), we find the output value 4 on the vertical axis. Moving horizontally along the line \(y=4\), we locate two points of the curve with output value 4: \((−1,4)\) and \((3,4)\). These points represent the two solutions to \(f(x)=4\): −1 or 3. This means \(f(−1)=4\) and \(f(3)=4\), or when the input is −1 or 3, the output is 4. See Figure \(\PageIndex{9}\).
Exercise \(\PageIndex{10}\)
Given the graph in Figure \(\PageIndex{7}\), solve \(f(x)=1\).
- Answer
-
\(x=0\) or \(x=2\)
Determining Whether a Function is One-to-One
Some functions have a given output value that corresponds to two or more input values. For example, in the stock chart shown in the Figure at the beginning of this chapter, the stock price was $1000 on five different dates, meaning that there were five different input values that all resulted in the same output value of $1000.
However, some functions have only one input value for each output value, as well as having only one output for each input. We call these functions one-to-one functions. As an example, consider a school that uses only letter grades and decimal equivalents, as listed in Table \(\PageIndex{13}\).
| Letter Grade | Grade Point Average |
|---|---|
| A | 4.0 |
| B | 3.0 |
| C | 2.0 |
| D | 1.0 |
This grading system represents a one-to-one function, because each letter input yields one particular grade point average output and each grade point average corresponds to one input letter.
To visualize this concept, let’s look again at the two simple functions sketched in Figures \(\PageIndex{1a}\) and \(\PageIndex{1b}\). The function in part (a) shows a relationship that is not a one-to-one function because inputs \(q\) and \(r\) both give output \(n\). The function in part (b) shows a relationship that is a one-to-one function because each input is associated with a single output.
One-to-One Functions
A one-to-one function is a function in which each output value corresponds to exactly one input value.
Example \(\PageIndex{11}\): Determining Whether a Relationship Is a One-to-One Function
Is the area of a circle a function of its radius? If yes, is the function one-to-one?
Solution
A circle of radius \(r\) has a unique area measure given by \(A={\pi}r^2\), so for any input, \(r\), there is only one output, \(A\). The area is a function of radius\(r\).
If the function is one-to-one, the output value, the area, must correspond to a unique input value, the radius. Any area measure \(A\) is given by the formula \(A={\pi}r^2\). Because areas and radii are positive numbers, there is exactly one solution:\(\sqrt{\frac{A}{\pi}}\). So the area of a circle is a one-to-one function of the circle’s radius.
Exercise \(\PageIndex{11A}\)
- Is a balance a function of the bank account number?
- Is a bank account number a function of the balance?
- Is a balance a one-to-one function of the bank account number?
- Answer
-
a. yes, because each bank account has a single balance at any given time;
b. no, because several bank account numbers may have the same balance;
c. no, because the same output may correspond to more than one input.
Exercise \(\PageIndex{11B}\)
Evaluate the following:
- If each percent grade earned in a course translates to one letter grade, is the letter grade a function of the percent grade?
- If so, is the function one-to-one?
- Answer
-
a. Yes, letter grade is a function of percent grade;
b. No, it is not one-to-one. There are 100 different percent numbers we could get but only about five possible letter grades, so there cannot be only one percent number that corresponds to each letter grade.
Using the Vertical Line Test
As we have seen in some examples above, we can represent a function using a graph. Graphs display a great many input-output pairs in a small space. The visual information they provide often makes relationships easier to understand. By convention, graphs are typically constructed with the input values along the horizontal axis and the output values along the vertical axis.
The most common graphs name the input value \(x\) and the output \(y\), and we say \(y\) is a function of \(x\), or \(y=f(x)\) when the function is named \(f\). The graph of the function is the set of all points \((x,y)\) in the plane that satisfies the equation \(y=f(x)\). If the function is defined for only a few input values, then the graph of the function is only a few points, where the x-coordinate of each point is an input value and the y-coordinate of each point is the corresponding output value. For example, the black dots on the graph in Figure \(\PageIndex{10}\) tell us that \(f(0)=2\) and \(f(6)=1\). However, the set of all points \((x,y)\) satisfying \(y=f(x)\) is a curve. The curve shown includes \((0,2)\) and \((6,1)\) because the curve passes through those points
The vertical line test can be used to determine whether a graph represents a function. If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because a function has only one output value for each input value. See Figure \(\PageIndex{11}\) .
Howto: Given a graph, use the vertical line test to determine if the graph represents a function
- Inspect the graph to see if any vertical line drawn would intersect the curve more than once.
- If there is any such line, determine that the graph does not represent a function.
Example \(\PageIndex{12}\): Applying the Vertical Line Test
Which of the graphs in Figure \(\PageIndex{12}\) represent(s) a function \(y=f(x)\)?
Solution
If any vertical line intersects a graph more than once, the relation represented by the graph is not a function. Notice that any vertical line would pass through only one point of the two graphs shown in parts (a) and (b) of Figure \(\PageIndex{12}\). From this we can conclude that these two graphs represent functions. The third graph does not represent a function because, at most x-values, a vertical line would intersect the graph at more than one point, as shown in Figure \(\PageIndex{13}\).
Exercise \(\PageIndex{12}\)
Does the graph in Figure \(\PageIndex{14}\) represent a function?
- Answer
-
yes
Using the Horizontal Line Test
Once we have determined that a graph defines a function, an easy way to determine if it is a one-to-one function is to use the horizontal line test . Draw horizontal lines through the graph. If any horizontal line intersects the graph more than once, then the graph does not represent a one-to-one function.
Howto: Given a graph of a function, use the horizontal line test to determine if the graph represents a one-to-one function
- Inspect the graph to see if any horizontal line drawn would intersect the curve more than once.
- If there is any such line, determine that the function is not one-to-one.
Example \(\PageIndex{13}\): Applying the Horizontal Line Test
Consider the functions shown in Figure \(\PageIndex{12a}\) and Figure \(\PageIndex{12b}\). Are either of the functions one-to-one?
Solution
The function in Figure \(\PageIndex{12a}\) is not one-to-one. The horizontal line shown in Figure \(\PageIndex{15}\) intersects the graph of the function at two points (and we can even find horizontal lines that intersect it at three points.)
The function in Figure \(\PageIndex{12b}\) is one-to-one. Any horizontal line will intersect a diagonal line at most once.
Exercise \(\PageIndex{13}\)
Is the graph shown in Figure \(\PageIndex{13}\) one-to-one?
- Answer
-
No, because it does not pass the horizontal line test.
Identifying Basic Toolkit Functions
In this text, we will be exploring functions—the shapes of their graphs, their unique characteristics, their algebraic formulas, and how to solve problems with them. When learning to read, we start with the alphabet. When learning to do arithmetic, we start with numbers. When working with functions, it is similarly helpful to have a base set of building-block elements. We call these our “toolkit functions,” which form a set of basic named functions for which we know the graph, formula, and special properties. Some of these functions are programmed to individual buttons on many calculators. For these definitions we will use x as the input variable and \(y=f(x)\) as the output variable.
We will see these toolkit functions, combinations of toolkit functions, their graphs, and their transformations frequently throughout this book. It will be very helpful if we can recognize these toolkit functions and their features quickly by name, formula, graph, and basic table properties. The graphs and sample table values are included with each function shown in Table \(\PageIndex{14}\).
| Name | Function | Graph |
|---|---|---|
| Constant | \(f(x)=c\) where \(c\) is a constant | |
| Identity | \(f(x)=x\) | |
| Absolute Value | \(f(x)=|x|\) | |
| Quadratic | \(f(x)=x^2\) | |
| Cubic | \(f(x)=x^3\) | |
| reciprocal | \(f(x)=\dfrac{1}{x}\) | |
| Reciprocal squared | \(f(x)=\dfrac{1}{x^2}\) | |
| Square root | \(f(x)=\sqrt{x}\) | |
| Cube root | \(f(x)=\sqrt[3]{x}\) |
Key Equations
- Constant function \(f(x)=c\), where \(c\) is a constant
- Identity function \(f(x)=x\)
- Absolute value function \(f(x)=|x|\)
- Quadratic function \(f(x)=x^2\)
- Cubic function \(f(x)=x^3\)
- Reciprocal function \(f(x)=\dfrac{1}{x}\)
- Reciprocal squared function \(f(x)=\frac{1}{x^2}\)
- Square root function \(f(x)=\sqrt{x}\)
- Cube root function \(f(x)=3\sqrt{x}\)
Key Concepts
- A relation is a set of ordered pairs. A function is a specific type of relation in which each domain value, or input, leads to exactly one range value, or output.
- Function notation is a shorthand method for relating the input to the output in the form \(y=f(x)\).
- In tabular form, a function can be represented by rows or columns that relate to input and output values.
- To evaluate a function, we determine an output value for a corresponding input value. Algebraic forms of a function can be evaluated by replacing the input variable with a given value.
- To solve for a specific function value, we determine the input values that yield the specific output value.
- An algebraic form of a function can be written from an equation.
- Input and output values of a function can be identified from a table.
- Relating input values to output values on a graph is another way to evaluate a function.
- A function is one-to-one if each output value corresponds to only one input value.
- A graph represents a function if any vertical line drawn on the graph intersects the graph at no more than one point.
- The graph of a one-to-one function passes the horizontal line test.
Footnotes
1
http://www.baseball-almanac.com/lege.../lisn100.shtml
. Accessed 3/24/2014.
2 www.kgbanswers.com/how-long-i...y-span/4221590. Accessed 3/24/2014.
Glossary
dependent variable
an output variable
domain
the set of all possible input values for a relation
function
a relation in which each input value yields a unique output value
horizontal line test
a method of testing whether a function is one-to-one by determining whether any horizontal line intersects the graph more than once
independent variable
an input variable
input
each object or value in a domain that relates to another object or value by a relationship known as a function
one-to-one function
a function for which each value of the output is associated with a unique input value
output
each object or value in the range that is produced when an input value is entered into a function
range
the set of output values that result from the input values in a relation
relation
a set of ordered pairs
vertical line test
a method of testing whether a graph represents a function by determining whether a vertical line intersects the graph no more than once