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Assignment 5

  • Page ID
    169953
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    Exercise \(\PageIndex{1}\)
    1. If \(\sigma \in A_n\) and \(\tau \in S_n\text{,}\) show that \(\tau^{-1} \sigma \tau \in A_n\text{.}\)
    2. What are the possible cycle structures of elements of \(A_5\text{?}\) What about \(A_6\text{?}\)
    Answer

    1. Let \(\sigma \in A_n\) and \(\tau \in S_n\text{.}\)

     If \(\tau \in A_n\) then \(\tau^{-1} \sigma \tau \in A_n\text{.}\) Otherwise  \(\tau\) is odd permutation and  \(\tau^{-1}\) is also odd (show). Then sum of odd numbers is even, \(\tau^{-1} \sigma \tau \in A_n\text{.}\)

    2,  The possible cycle types in \({A_5}\) are:
     \(11111 , 221, 311\)
     The possible cycle types in \({A_6}\) are:
    \( 111111 , 2211, 3111, 33, 42 \)

    Exercise \(\PageIndex{2}\)
    1. Find all of the subgroups in \(A_4\text{.}\) What is the order of each subgroup?
    2.  What are the conjugacy classes of \(A_4\)?
    3. Let \(H=\{ e, (12)(34), (13)(24), (14)(23)\}.\) Find the left cosets and right cosets of \(H\) in \(A_4.\)
    Answer

    1.  Since \(|A_4|=12\), by Lagrange's theorem, the possible order of subgroups are \(1, 2, 3, 4, 6\) and \(12\). But \(A_4\) has no subgroup of order \(6\) (done in class).
    Hence, the subgroups of \(A_4\)  are:
     Order \(1: \{e\}\)
    Order \(2: \{e, (12)(34)\}, \{e, (13)(24)\}, \{e, (14)(23)\}\)
    Order \(3: \{e, (123), (321)\}, \{e, (124), (421)\}, \{e, (134), (431)\}, \{e, (234), (431)\}\)
     Order \(4: \{e, (12)(34), (13)(24), (14)(23)\}\)
     Order \(12: A_4\)

    2. Show that the conjugacy classes of \(A_4\) are:
     \(\{e\}, \{(12)(34), (13)(24), (14)(23)\}, \{(123), (134), (243), (142)\}, \{(321), (431), (234), (124)\}.\)

    3.  Since \([A_4:H]=\dfrac{12}{4}=3\). Hence there are \(3\) left cosets of \(H\) in \(A_4\) and \(3\) right cosets of \(H\) in \(A_4\)
    Left cosets:
    \(eH = H = (12)(34)H = (13)(24)H = (14)(23)H\)
     Since \((123)(12)(34) = (134)\), \((123)(13)(24) = (243)\), \((123)(14)(23) = (142),\)
     \((123)H = (134)H = (243)H = (142)H = \{(123), (134), (243), (142)\}\)
      Since \((132)(12)(34) = (234)\), \((132)(13)(24) = (124)\), \((132)(14)(23) = (143).\)
     \((132)H = (234)H = (124)H = (143)H = \{(132), (234), (124), (143)\}\)
     Right cosets:
     \(He = H = H(12)(34) = H(13)(24) = (14)(23)H\)
     Since \((12)(34)(123) = (243)\), \((13)(24)(123) = (142)\), \((14)(23)(123) = (134),\)
     \(H(123) = H(243) = H(142) = H(134) = \{(123), (243), (142), (134)\}\)
     Since \((12)(34)(132) = (143)\), \((13)(24)(132) = (234)\), \((14)(23)(132) = (124),\)
    \((132)H = (143)H = (234)H = (124)H  = \{(132), (143), (234), (124)\}.\)

    Exercise \(\PageIndex{3}\)
    1. Find the center of \(D_4\) and \(D_5\). Justify your answer.
    2. What is the center of \(D_n\text{?}\)
    3.  Find the conjugacy classes of  \(D_4\). Justify your answer.
    Answer

    1. Consider \( a = s^r k \) and \( b = r^j \) in \( D_n \) for some \( 0 \leq k, j < n \). Then
    \[
    ab = s^{r(k+j)},
    \]
    and,
    \[
    ba = s^{r(k-j)}.
    \]
    The equation \( ab = ba \) implies that 
    \[
    k - j \equiv k + j \pmod{n}.
    \]
    But this is only true if \( j = \frac{n}{2} \) or \( j = 0 \).
    Therefore, all reflections are not in the center of \( D_n \). Furthermore, the only rotation that is in the center is \( r^{\frac{n}{2}} \) (and trivially \( e \)).
    So, if \( n \) is odd, then the center of \( D_n \) is \( \{ e \} \), otherwise, the center of \( D_n \) is \( \{ e, r^{\frac{n}{2}} \} \).
    For example,
    \[
    Z(D_4) = \{ e, r^2 \}, \quad Z(D_5) = \{ e \}.
    \]

    2. The center of \(D_n\) is \(\{e\}\) if \(n\) is odd and \(\{e, r^{n/2}\}\) if \(n\) is even.

    3. 

    Let \(D_4 = <r, s | r^4 = e, s^2 = e, srs = r^{-1}>.\)
    The conjugacy classes of \(D_4\) are \(\{e\}, \{r^2\}, \{r,r^3\}, \{s, r^2s\}, \{rs, r^3s\}\).
    Clearly, \([e] = \{e\}\).

    Consider the following for the class \([r^m]\) for some \(m\):
    \[
    r^n r^m r^{-n} = r^m,
    \]
    and
    \[
    s r^n r^m r^{-n} s = r^{-m},
    \]
    for all \(n\). Therefore, \([r^m] = \{r^m, r^{-m}\}\). That is, 
    \[
    [r] = \{r, r^3\}, \quad [r^2] = \{r^2\}.
    \]

    Consider the class \([sr^m]\) for some \(m\). We have:
    \[
    r^n s r^m r^{-n} = s r^{m - 2n},
    \]
    and
    \[
    s r^n s r^m s r^{-n} = s s r^{-n + m + n} = s r^{-m}.
    \]
    for all \(n\). Since \(D_4\) has an even number of rotations, we can partition the reflections into two conjugacy classes: even and odd. If there were only one conjugacy class of reflections, \(m - 2n\) would not cycle properly. Thus, we have:
    \[
    [s r^2] = \{ s r^n \mid n \in 2\mathbb{N} \} = \{s, sr^2\},
    \]
    and
    \[
    [s r] = \{ s r, s r^3 \}.
    \]

    To summarize, the conjugacy classes are:
    \[
    [e], [r], [r^2], [s], [sr].
    \]
    Thus, the members of a conjugacy class of \( D_4 \) are different but have the same type of effect on a square: 

    1.   \( r \) and \( r^3 \) are a 90-degree rotation in some direction,
    2.    \( s \) and \( r^2s \) are a reflection across a diagonal,
    3.  \( rs \) and \( r^3s \) are a reflection across an edge bisector.
       
    Exercise \(\PageIndex{4}\)

    List all of the subgroups of \(S_4\text{.}\) Find each of the following sets:

    1. \(\displaystyle \{ \sigma \in S_4 : \sigma(1) = 3 \}\)
    2. \(\displaystyle \{ \sigma \in S_4 : \sigma(2) = 2 \}\)
    3.  \(\{ \sigma \in S_4 : \sigma(1) = 3\) and \(\sigma(2) = 2 \}\text{.}\)
    4. Are any of these sets subgroups of \(S_4\text{?}\)
    Exercise \(\PageIndex{5}\)

    Let \(\sigma \in S_X\text{.}\) If \(\sigma^n(x) = y\) for some \(n \in \mathbb Z\text{,}\) we will say that \(x \sim y\text{.}\) 

    1. Show that \(\sim\) is an equivalence relation on \(X\text{.}\)
    2.  Define the orbit of \(x \in X\) under \(\sigma \in S_X\) to be the set
      \[ {\mathcal O}_{x, \sigma} = \{ y : x \sim y \}\text{.} \nonumber \]

      Compute the orbits of each element in \(\{1, 2, 3, 4, 5\}\) under each of the following elements in \(S_5\text{:}\)

      \begin{align*} \alpha & = (1254)\\ \beta & = (123)(45)\\ \gamma & = (13)(25)\text{.} \end{align*}
       That is for example: \begin{align*} {\mathcal O}_{x, \sigma}&  = \{ y \in \{1,2,3,4,5\} : x \sim y \}\\
       &=\{ y :\sigma^n(x) = y,\text{for some } n\in \mathbb{N} \}\\
       \end{align*}

    3. If \({\mathcal O}_{x, \sigma} \cap {\mathcal O}_{y, \sigma} \neq \emptyset\text{,}\) prove that \({\mathcal O}_{x, \sigma} = {\mathcal O}_{y, \sigma}\text{.}\) The orbits under a permutation \(\sigma\) are the equivalence classes corresponding to the equivalence relation \(\sim\text{.}\)
      A subgroup \(H\) of \(S_X\) is transitive if for every \(x, y \in X\text{,}\) there exists a \(\sigma \in H\) such that \(\sigma(x) = y\text{.}\) Prove that \(\langle \sigma \rangle\) is transitive if and only if \({\mathcal O}_{x, \sigma} = X\) for some \(x \in X\text{.}\)


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